The figure below shows a line graph and two shaded triangles that are similar:Which statement about the slope of the line is true?
It is –2 throughout the line.
It is fraction negative 1 over 2 throughout the line.
The slope from point O to point A is one-half times the slope of the line from point A to point B. The slope from point O to point A is two times the slope of the line from point A to point B.
The figure below shows a line graph and two shaded - 1

Answers

Answer 1
Answer:

Answer:

The slope is fraction negative 1 over 2 throughout the line.

Step-by-step explanation:

The slope (m) of a line is computed as follows

m = (y2 - y1)/(x2 -x1)

where (x1, y1) and (x2, y2) are the coordinates of 2 points of the line. Taking, for example, points (0, 0) and (-4, 2), the slope is:

m = (2 - 0)/(-4 -0)  = -1/2

Then, the slope is -1/2 throughout the line.

Answer 2
Answer: Every time the y-value decreases by 1, the x-value increases by 2, so the slope is -1/2 throughout the line.

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Which of the following expressions represents a function?{(1, 2), (4, –2), (8, 3), (9, –3)} y2 = 16 − x2 2x2 + y2 = 5x = 7
Which radical expression is equivalent to 3^3/4

Which is an equation of the line containing the points (4, 10) and (6, 11) in standard form?–x + 2y = 16



2x – y = –2



x + 2y = 24



x – 2y = –16

Answers

Hello,

Answer A
y-10=(11-10)/(6-4) * (x-4)
==>2y=x+16
==>-x+2y=16

Write a compound inequality that represents the situation. all real numbers at least –6 and at most 3A. –6 ≥ x ≥ 3

B. –6 < x ≤ 3

C. –6 ≤ x ≤ 3

D. –6 < x < 3

Answers

Hello,

Answer C
=====================


What are the factors of 6tu

Answers


Depending on the value of 't' and 'u', the numerical value of that expression
could have almost anything for factors. 

For example, if  't' happens to be 3 and 'u' happens to be 10, then  6tu = 180,
and the factors of  6tu  are

   1,   2,   3,  4,  5,  6,  9,  10,  12,  15,  18,  20,  30,  36,  45,  60,  90, and  180.

But that would only be temporary ... only as long as  t=3  and  u=10. 

The only factors you can always count on, that don't depend on the values
of  't'  and  'u', are

           1,  6,  t,  u,  6t,  6u,  tu,  and  6tu .

On August 8, 1981, American Savings offered an insured tax-free account paying 23.24% compounded monthly. If you had invested $90,000 at that time, how much would you have on August 8, 2014, assuming that you could have locked the interest rate at the time of deposit? Someone please help me!!

Answers

Answer:

$181,432,754

Step-by-step explanation:

We use the formula for compound interest here, to determine the amount

Mathematically, that would be;

A =I (1 + r/n)^nt

where A is the amount which we want to calculate

I is the initial amount which is $90,000

r is the rate = 23.24% = 23.24/100 = 0.2324

n is the number of times per year the interest is compounded = 12 (compounded monthly)

t is the number of years = 2014 - 1981 = 33

Substituting these values, we have;

A = 90,000(1 + 0.2324/12)^(33 * 12)

A = 90,000(1 + 0.0194)^396

A = 90,000(1.0194)^396

A = 181,432,754.27210504

Which is approximately $181,432,754 to the nearest whole dollars

The volume of a cylinder is 36 pie cubic units and its height is 4 units. find its lateral area.

Answers

V=hpir^2
V=36pi
h=4
LA=2hpir
find r then find lateral area

36pi=4pir^2
divide by 4pi
9=r^2
sqrt both sides
3=r

LA=2hpir
LA=2*4*pi*3
LA=8*pi*3
LA=24pi

lateral area=24 pi squarea units

Find the range of the following piecewise function.[0,11)
(-4,6]
(0,11]
[-4,6)

Answers

Given:

The piecewise function is

f(x)=\begin{cases}x+4 & \text{ if } -4\leq x<3 \n 2x-1 & \text{ if } 3\leq x<6 \end{cases}

To find:

The range of given piecewise function.

Solution:

Range is the set of output values.

Both functions f(x)=x+4 and f(x)=2x-1 as linear functions.

Starting value of f(x)=x+4 is at x=-4 and end value is at x=3.

Starting value: f(-4)=-4+4=0

End value: f(3)=3+4=7

Starting value of f(x)=2x-1 is at x=3 and end value is at x=6.

Starting value: f(3)=2(3)-1=5

End value: f(6)=2(6)-1=11

Least range value is 0 at x=-4 and 0 is included in the range because -4 is included in the domain.

Largest range value is 11 at x=6 and 11 is not included in the range because 6 is not included in the domain.

So, the range of the given piecewise function is [0,11).

Therefore, the correct option is A.