What is the answer to this ?????? 4/5 - 1/2=?????

Answers

Answer 1

Answer: Hello,this is your answer.

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One hundred times the quantity six plus five

Answers

100 times (6+5)
100 times 11
100 groups of 11=1100
Hope I helped:)

100 ( 6 + 5 )

100 (11)

100 × 11

⇒ 1100.

SLOVE BY ELIMIMATION METHOD
X+Y=6
X-Y=10

Answers

Step-by-step explanation:

x + y = 6 ...................equation 1

x - y = 10 ..................equation 2

Solving equation 1 and 2

x + y = 6

x -y =10

2x = 16

x = 16 /2

Therefore x = 8

Now

putting x = 8 in equation 1

8 + y = 6

y = 6 -8

y = -2

hope it was helpful :)

Answer:

x=8 and y= -2

Step-by-step explanation:

x+y=6

x-y=10 + ( add them together)

-----------------

2x=16 ( substitute/ plug x back in )

x=8

8+y=6

8-y=10

y=-2

How do i graph the parabolas y = 1/32x^2

Answers

$y=(1)/(32)x^2 \n \nx=-16 \Rightarrow y=(1)/(32) *(-16)^2=(1)/(\not32^1)*\not256^8=8\n \nx=-8 \Rightarrow y=(1)/(32) *(-8)^2=(1)/(\not32^1)*\not64^2=2\n \nx=0 \Rightarrow y=(1)/(32) *(0)^2=(1)/(\not32^1)*0=0 \n \nx=8 \Rightarrow y=(1)/(32) *(8)^2=(1)/(\not32^1)*\not64^2=2 \n \nx= 16 \Rightarrow y=(1)/(32) *( 16)^2=(1)/(\not32^1)*\not256^8=8$

Find the zeros in simplest radical form:
y=1/2x^2-4

Answers

$y= (1)/(2)x^2-4\n \n y =0 \n \n(1)/(2)x^2-4 =0 \ \ / \cdot 2\n \nx^2-8=0 \n \n(x-√(8))(x+√(8))=0 \n \n x-√(8)= \ \ or \ \ x+√(8) = 0 \n \nx=√(8) \ \ or \ \ x=-√(8) \n \nx=√(4\cdot 2) \ \ or \ \ x= -√(4\cdot 2)\n \n x=2√(2) \ \ or \ \ x=-2√(2)$

$y= (1)/(2) x^2-4\n\ny=0\ \ \ \Leftrightarrow\ \ \ (1)/(2) x^2-4=0\ /\cdot2\ \ \ \Leftrightarrow\ \ \ x^2-8=0\n\nx^2-(2 √(2) )^2=0\ \ \ \Leftrightarrow\ \ \ (x-2 √(2) )(x+2 √(2) )=0\n\nx-2 √(2) =0\ \ \ \ \ \ \ \ or\ \ \ \ \ \ \ \ \ x+2 √(2)=0\n\nx=2 √(2)\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=-2 \sqrt{2$