Answer:
box 1 has larger mass than box 2
Explanation:
We need to consider the linear momentum of the boxes immediately before and after they crash.
Recall that momentum is defined as mass times velocity.
So for before the collision, the linear momentum of the system of two boxes is:
m1 * 4km/h - m2 * 8km/h
with m1 representing mass "1" on the left, and m2 representing mass 2 on the right.
Notice the sign of the linear momentum (one positive (moving towards the right) and the other one negative (moving towards the left)
For after the collision, we have or the linear momentum of the system:
- m1 * 2km/h - m2 * 1km/h
Then, since the linear momentum is conserved in the collision, we make the initial momentum equal the final and study the mass relationship between m1 and m2:
4 m1 - 8 m2 = - 2 m1 - m2
combining like terms for each mas on one side and another of the equal sign, we get;
4 m1 + 2 m1 = 8 m2 - m2
6 m1 = 7 m2
therefore m1 = (7/6) m2
which (since 7/6 is a number larger than one) tells us that m1 is larger than m2 by a factor of 7/6
Therefore, answer 1 is the correct answer.
To solve this problem we will apply the concepts related to the Doppler effect. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other. Mathematically it can be described as,
Here,
= Frequency of Source
= Speed of sound
f = Frequency heard before slowing down
f' = Frequency heard after slowing down
v = Speed of the train before slowing down
So if the speed of the train after slowing down will be v/2, we can do a system equation of 2x2 at the two moments, then,
The first equation is,
Now the second expression will be,
Dividing the two expression we have,
Solving for v, we have,
Therefore the speed of the train before and after slowing down is 22.12m/s
The speed of the train can be determined using the Doppler effect formula.
The question involves the Doppler effect, which is the change in frequency or wavelength of a wave as observed by an observer moving relative to the source of the wave. In this case, the train whistle's frequency changes from 300 Hz to 290 Hz as the train approaches the station.
To find the speed of the train before and after slowing down, we can use the formula for the Doppler effect:
f' = f((v + v_o)/(v - v_s))
Where:
By substituting the given values for observed frequency (290 Hz), source frequency (300 Hz), and the speed of sound (343 m/s), we can solve for the speed of the train before and after slowing down.
#SPJ3
To find the components of the velocity vector, you can use trigonometry. The north component is calculated using the sine function and the west component is calculated using the cosine function. After 2.20 hours, the distance traveled north and west can be found by multiplying the velocity components by the time.
To find the components of the velocity vector in the northerly and westerly directions, we can use trigonometry. The velocity vector is 835 km/h and is traveling in a direction 41.5° west of north. To find the north component, we can use the sine function: North component = velocity * sin(angle). To find the west component, we can use the cosine function: West component = velocity * cos(angle).
After 2.20 hours, we can find the distance traveled north and west by multiplying the velocity components by the time: Distance north = North component * time and Distance west = West component * time.
Let's calculate the values:
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Answer:
a.) Speed V = 29.3 m/s
b.) K.E = 1931.6 J
Explanation: Please find the attached files for the solution
The wheel's speed at the bottom of the hill can be found through the conservation of energy equation considering both translational and rotational kinetic energy, while the total kinetic energy at the bottom of the hill is a sum of translational and rotational kinetic energy.
These two questions address the physics concepts of conservation of energy, kinetic energy, and rotational motion. To answer the first question, (a) How fast is the wheel moving when it reaches the bottom of the hill if it rolled without slipping all the way down?, we need to consider the potential energy the wheel has at the top of the hill is completely converted into kinetic energy at the bottom. This includes both translational and rotational kinetic energy. Solving for the final velocity, vf, which would be the speed of the wheel, we get vf = sqrt((2*g*h)/(1+I/(m*r^2))), where g is the acceleration due to gravity, h is the height of the hill, I is the moment of inertia of the wheel, m is the mass of the wheel, and r is the radius of the wheel.
For the second question, (b) How much total kinetic energy does it have when it reaches bottom of the hill?, we use the formula for total kinetic energy at the bottom of the hill, K= 0.5*m*v^2+0.5*I*(v/r)^2. Substituting the value of v found in the first part we find the kinetic energy which we can use the formula provided in the reference information.
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Answer:
Explanation:
The force due to gravitation is equal to zero for each of the masses.
M1= 181kg
M2= 712kg
m = 72.6kg
The distance between M1 and M2 is said to be fixed , therefore no value should be given I.e it's a constant.
From the formula for gravitational force we have that
F = GMm/r^2
GmM1/(d-r)^2. = GmM2/r^2
where r is the distance between the 72.6 kg and 712kg
d is the distance between M1 and M2
Solving mathematically
r(√M1+√M2) = d√M2
r = d√M2/√M1 + √M2
d×26.68/ 13.45+26.68
d×26.68/40.13
r = 0.665d
We are given:
The tuning fork vibrates at 15660 oscillations per minute
Period of one back-and forth movement:
the given data can be rewritten as:
1 minute / 15660 oscillations
60 seconds / 15660 oscillations (1 minute = 60 seconds)
dividing the values
0.0038 seconds / Oscillation
Therefore, one back and forth vibration takes 0.0038 seconds
The volume of Ampicillin IM q8h to be administered per dose is 1.5 mL when the order is to give 600 mg of it from a concentration of 400 mg per mL prepared by the dilution of 2 g in 4.8 mL of sterile water.
1. The information we know
2. We need to find:
The volume of Ampicillin in mL per dose
3. Calculation of the Ampicillin's volume to be administered
We can calculate the volume of Ampicillin as follows:
Therefore, we need to administer 1.5 mL of Ampicillin per dose.
Find more about doses here:
I hope it helps you!
Answer:
1.5 ml
Explanation:
The nurse is to administer 600 mg of Ampicillin IM q8h
the reconstitute yield 400 mg per mL
400 mg is in 1 ml
600 mg will be (600 mg × 1 ml) / 400 mg = 1.5 ml