MATHEMATICS HIGH SCHOOL

What do 20-(12+6) equal

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

Since the 12 + 6 are parenthesis, we do these first

12 + 6 = 18

Then will solve the rest, 20 - 18

20 - 18 = 2, therefore leaving us with the answer of 2

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Describe how the shape moves from:Frame 1 to Frame 2

Frame 2 to Frame 3

Frame 3 to Frame 4

Answers

Answer:

1. Frame 1 to Frame 2 - Vertical downward translation

2. Frame 2 to Frame 3 - $90^(0)$ counterclockwise rotation

3. Frame 3 to Frame 4 - Vertical upward translation

Step-by-step explanation:

The movement of the shapes from one frame to the other can be described by solid transformations. These are procedures required to change the orientation or size of a given shape. They include: rotation, translation, dilation and reflection.

1. When the shape in frame 1 is translated vertically downwards, it would produce the shape in frame 2.

2. Rotating the shape in frame 2 by $90^(0)$ counterclockwise would move it to the shape in frame 3.

3. Vertical upward dilation would move the shape in frame 3 to that in frame 4.

2v2 -5v +3 = 0 how did I do this?

Answers

$2v2 -5v +3 = 0 \n \n\Delta = b^(2)-4ac = (-5)^(2)-4*2*3= 25-24=1\n \nv_(1)=(-b-√(\Delta ))/(2a) =(5- √(1 ))/(2*2)=(5- 1)/(4)= (4)/(4)=1\n \nv_(2)=(-b+√(\Delta ))/(2a) =(5+ √(1 ))/(2*2)=(5+1)/(4)= (6)/(4)=(3)/(2)=1(1)/(2)$

In parallelogram ABCD, E is the midpoint of AB and F is the midpoint of DC . Let G be the intersection of the diagonal DB and the line segment EF . Prove that G is the midpoint of EF.

Answers

The midpoint of the line $\overline{EF}$ is the point that divides $\overline{EF}$ in two halves of the same length.

ΔDFG ≅ ΔBGE and $\overline{FG}$ ≅ $\overline{EG}$ by CPCTC, therefore, Gis the midpoint of $\overline{EF}$

Reasons:

The given parameters are;

The midpoint of AB in parallelogram ABCD = E

The midpoint of DC = F

Point of intersection of EF and DB = Point G

Required:

To prove that point G is the midpoint of EF.

Solution:

Statement ${}$ Reason

1. m∠BDC ≅ m∠ABD ${}$ 1. Alternate angles theorem

2. m∠DGF ≅ m∠BGE ${}$ 2.Vertical angles theorem

3. $\overline{DC}$ = $\overline {AB}$ ${}$ 3. Opposite sides of a parallelogram ABCD

4. $\overline{CF}$ ≅ $\overline{DF}$ ${}$ 4. Definition of midpoint of DC

5. $\overline{CF}$ = $\mathbf{\overline{DF}}$ ${}$ 5. Definition of congruency

6. $\overline{CF}$ + $\overline{DF}$ = DC ${}$ 6. Segment addition property

7. $\overline{CF}$ + $\overline{CF}$ = DC ${}$ 7. Substitution property

8. 2· $\overline{CF}$ = DC ${}$ 8. Addition

9. $\overline{CF}$ = 0.5· $\overline{DC}$ = $\overline{DF}$ ${}$ 9. Division property

Similarly;

10. $\overline{AE}$ = 0.5· $\overline{AB}$ = $\overline{EB}$ ${}$ 10. Division property

11. 0.5· $\overline{DC}$ = 0.5· $\overline{AB}$ ${}$ 11. Multiplication property of equality

12. $\overline{AE}$ = $\overline{EB}$ ${}$ 12. Substitution property

13. ΔDFG ≅ ΔBGE ${}$ 13. Angle-Angle-Side rule of congruency

14. $\overline{FG}$ ≅ $\overline{EG}$ ${}$ 14. CPCTC ${}$

15. $\overline{FG}$ = $\overline{EG}$ ${}$ 15. Definition of congruency

16. Point G is the midpoint of $\overline{EF}$ ${}$ 17. Definition of midpoint

Learn more about the midpoint of a line here:

brainly.com/question/5127222

Answer:

GF = GE that prove G is the mid-point of EF

Step-by-step explanation:

In the Parallelogram ABCD

∵E is the mid-point of AB

∵F is the mid-point of CD

∵AB = CD opposite sides in the parallelogram

∴EB = DF⇒(1)

∵AB // CD opposite sides in the parallelogram

∴m∠EBD = m∠FDB alternate angles ⇒(2)

∵BD intersects EF at G

∴m∠BGE = m∠DGF vertically opposite angles ⇒(3)

By using (1) , (2) and (3) you can prove:

ΔBGE is congruent to ΔDGF ⇒ AAS

∴GF = GE

∴G is the mid-point of EF

A bird sits on top of a lamppost. The angle of depression from the bird to the feet of an observer standing away from the lamppost is 35 degrees. The distance from the bird to the observer is 25 meters. How tall is the lamppost? Draw a diagram, label it, and show how to find this value.

Answers

Hello,
See the picture jointed

How much is a 1914 50 mark note worth

Answers

Step-by-step explanation:

Oh no entiendo nada todavía

Answer:

Depends on the wear. But ~ $5 to $20 USD

Step-by-step explanation:

The value of a 1914 German 50 Mark banknote can vary widely depending on its condition, rarity, and demand among collectors. In September 2021, a 1914 50 Mark German banknote in average to good circulated condition might be worth between $5 to $20 USD. However, if the banknote is in excellent condition with minimal wear and is considered rare due to specific features or historical significance, its value could be significantly higher.

Find the distance and midpoint for the following coordinates.
P(7.6 , 10.1) and Q(4.6 , 3.1)

Answers

Solving for the midpoint:

x - coordinate: (7.6 + 4.6)/2 = 6.1
y - coordinate: (10.1 + 3.1)/2 = 6.6

Midpoint: (6.1 , 6.6)

Solving for the distance:

Distance formula: sqrt( (x2 - x1)^2 + (y2 - y1)^2 )

D = sqrt( (7.6 - 4.6)^2 + (10.1 - 3.1)^2 )
D = sqrt( 3^2 + 7^2)
D = sqrt(58)
D = 7.62 units

Distance = 7.62 units

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4. Classify the triangle by its sides. The lengths of the sides are 9, 9, and 9.A) equilateralB) scaleneC) obtuseD) isosceles7. Line a is parallel to line b and m.(Angle 7 ) = 135 Find m(angle 4) A) 135B) 145C) 45D) 358. Find the values of x and y for which the lines are parallel. A) x = 68, y = 72B) x = 46, y = 72C) x = 68, y = 74D) x = 72, y = 6811.Look at the figure. If Angle 1 Is Congruent To angle 2 , describe the relationship between lines a and b.A) The lines are perpendicular.B) The lines are parallel.C) The lines intersect.D) The lines are transversals.12. Find the value of x for which the lines are parallel.A) 63B) 71C) 64D) 72