GEOMETRY. image attached
GEOMETRY. image attached - 1

Answers

Answer 1
Answer: \bf \measuredangle DFC=\cfrac{1}{2}(\widehat{BG}+\widehat{CD})\implies \measuredangle DFC=\cfrac{\widehat{BG}+\widehat{CD}}{2}

you know what the arcCD is, and what the angle DFC is, so
solve for the arcBG

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What is the solution to this system of linear equations?x + y = 4x − y = 6
Can someone help me whit this?!?
On the graph of the equation 2x + 5y = −30, what is the value of the y-intercept?

Solve this equation:
5/8y=-1

Answers

(5)/(8) y = -1

First, change (5)/(8) y to (5y)/(8) / Your problem should look like: (5y)/(8) = -1
Second, multiply both sides by 8. / Your problem should look like: 5y = -8
Third, divide both sides by 5. / Your problem should look like: y =  -(8)/(5)

Answer as fraction: y = - (8)/(5)
Answer as decimal: -1.6



5/8y=−1

Multiply both sides by 8/5.

(8/5)*(5/8y)=(8/5)*(−1)

y=−8/5

Subtract 8.263 from 13.48.
A)5.217
B)5.783
C)21.743
D)6.815

Answers

13.48-8.263=5.217 just use a calculator i mean it helps

Chocos is a dish made from wheat, sugar, and cocoa. Bertha is making a large pot of chocos for a party. Wheat(w) cost $5 per pound, sugar(s) costs $3 per pound, and cocoa(c) costs $4 per pound. She spends $48 on 12 pounds of food. She buys twice as much cocoa as sugar.

Answers

The question is incomplete, complete question is;

Chocos is a dish made from wheat, suguar, and cocoa. Bertha is making a large pot of chocos for a party. Wheat (w) costs $5 per pound, sugar (s) costs $3 per pound, and cocoa (c) costs $4 per pound. She spends $48 on 12 pounds of food. She buys twice as much cocoa as sugar. How much wheat, sugar, and cocoa will she use (in pounds) in her dish?

Answer:

She uses 3 pounds of wheat, 3 pounds of sugar and 6 pounds of cocoa in her dish.

Step-by-step explanation:

Given,

Total amount of spent money = $ 48

Total quantity of ingredients = 12 pounds

Let the quantity of wheat, sugar and cocoa she buys be x, y z pounds respectively.

\therefore x+y+z=12\ equation 1\nand\ 5x+3y+4z=48\ equation2

And according to question, quantity of cocoa is 2 times of sugar.

\therefore z=2y

Now substituting the value of z in equation 1and 2, we get;

x+y+2y=12\nx+3y=12\ equation3

5x+3y+4*2y=48\n5x+3y+8y=48\n5x+11y=48\ equation\ 4

Now multiply equation 3 by 5 and then subtract equation 4 from it.

5(x+3y)=5*12\n(5x+15y=60)-(5x+11y=48)\n4y=12\ny=(12)/(4)=3

\therefore z=2y=2*3=6

And substituting the value of y in equation 3, we get;

x+3y=12\nx+3*3=12\nx+9=12\nx=12-9=3

Thus the amount she uses is 3 pounds of wheat, 3 pounds of sugar and 6 pounds of cocoa in her dish.

Miles bought a car that cost 23,556, nearest ten thousands, how much did the cart cost

Answers

Rounding to the nearest ten thousands, the car costed $20,000

PLS HELP MEYour current test average in Science is an 81. You’ve taken 5 tests. You only have one test remaining. You can raise your average to an 85.
t or f

Answers

The marks that have to be scored in 6th test to make the average 85 is 105 .

What is Average ?

Average of a data set is the ratio of sum of all the data to the number of data in the set.

It is given that the average score = 81

Total tests up till now = 5

Total tests overall = 6

New Average = 85

Let the sum of the score for 5 tests is x

Then by the formula of average

x / 5 = 81

x  = 405

Now let the marks scored in the 6th test is y

then ( 405 +y) / 6 = 85

405 + y = 510

y = 105

Therefore ,  the marks that have to be scored in 6th test to make the average 85 is 105 .

To know more about Average

brainly.com/question/24057012

#SPJ2


false... even if you got 100 on the next test, you would only have an 84 average


Hope this helped!!! :) (comment if you don't understand)

The Greek alphabet contains 24 letters. How many fraternity names with Greek letters can be formed if each fraternity name contains 3 letters and repetition of letters is not permitted?a)69
B)12144
c)13824

Answers

For the first letter we have 24 choices. Since letters can't repeat the second letter has 23 choices (24 minus 1 that was used for the first slot) and the third has 22 (24 minus one for the first slot and one for the second slot).

The total number of combinations is thus: 24 x 23 x 22= 12,144
slot method

1st slot=24 options
2nd slot=23 options (1 went to 1st slot)
3rd slot=22 options (another to previous slot)

multiply them
24*23*22=12144 ways

B