PHYSICS COLLEGE

A physicist is creating a computational model of a falling person before and after opening a parachute. What boundary conditions would be important here?the air resistance encountered as the person falls

the speed at which the person falls

the change in kinetic and potential energy

the location where potential energy is zero

Answers

Answer 1

Answer:

the location where potential energy is zero

Explanation:

Answer 2

Answer:

Answer:

Air resistance

Explanation:

Air resistance encountered as the person falls

Related Questions

A car turns from a road into a parking lot and into an available parking space. The car’s initial velocity is 4 m/s [E 45° N]. The car’s velocity just before the driver decreases speed is 4 m/s [E 10° N]. The turn takes 3s. What's the average acceleration of the car during the turn? The answer should have directions with an angle.
A baseball player throws a ball into the stands at 15.0 m/s and at an angle 45.0° above the horizontal. On its way down, the ball is caught by a spectator 4.10 m above the point where the ball was thrown. How much time did it take for the ball to reach the fan in the stands?
A metal block of mass 3 kg is falling downward and has velocity of 0.44 m/s when it is 0.8 m above the floor. It strikes the top of a relaxed vertical spring of length 0.4 m. The spring constant is 2000 N/m. After striking the spring, the block rebounds. What is the maximum height above the floor that the block reaches after the impact
A capacitor consists of two closely spaced metal conductors of large area, separated by a thin insulating foil. It has an electrical capacity of 3000.0 μF and is charged to a potential difference of 60.0 V. Calculate the amount of energy stored in the capacitor. Tries 0/20 Calculate the charge on this capacitor when the electrical energy stored in the capacitor is 6.53 J. Tries 0/20 If the two plates of the capacitor have their separation increased by a factor of 5 while the charge on the plates remains constant, by what factor is the energy stored in the capacitor increased?
Convert 7 (gcm^2)/(min^2) into a value in standard S.I. units. Be sure to use scientific notation if necessary. You do not need to answer units.

The speed of light is 3 x 10 m/s.Calculate the frequency of light that is absorbed the most by the 100m length of fibre.
Give your answer in standard form.

Answers

Answer:

$3 * 10 {}^6$

a painting in an art gallery has height h and is hung so that its lower edge is a distance d above the eye of an observer. How far from the wall should the observer stand to get the best view?

Answers

Solution:

With reference to Fig. 1

Let 'x' be the distance from the wall

Then for $\Delta$ DAC:

$tan\theta = (d)/(x)$

⇒ $\theta = tan^(-1) (d)/(x)$

Now for the $\Delta$ BAC:

$tan\theta = (d + h)/(x)$

⇒ $\theta = tan^(-1) (d + h)/(x)$

Now, differentiating w.r.t x:

$(d\theta )/(dx) = (d)/(dx)[tan^(-1) (d + h)/(x) - tan^(-1) (d)/(x)]$

For maximum angle, $(d\theta )/(dx)$ = 0

Now,

0 = [/tex]\frac{d}{dx}[tan^{-1} \frac{d + h}{x} - tan^{-1} \frac{d}{x}][/tex]

0 = $(-(d + h))/((d + h)^(2) + x^(2)) -(-d)/(x^(2) + d^(2))$

$(-(d + h))/((d + h)^(2) + x^(2)) = \frac{{d}{x^(2) + d^(2)}$

After solving the above eqn, we get

x = $\sqrt{(d)/(d + h)}$

The observer should stand at a distance equal to x = $\sqrt{(d)/(d + h)}$

Final answer:

For optimum viewing of a painting in a gallery, an observer should position themselves a distance away from the painting calculated using Pythagoras theorem, forming a right-angled triangle with the painting and the floor. This distance can be expressed as c = √[(h/2 + d)² + (h/2)²], where h is the height of the painting and d is the height from the observer's eye to the bottom of the painting.

Explanation:

In the physics of optics, the viewer should position themselves to where they form a right-angled triangle with the ceiling and the painting leading to the best viewing experience. This is widely known as the 'normal viewing distance'.

Given that the painting has a height h and its lower edge is at a distance d above the observer's eye, the observer should stand a distance away from the wall, which can be calculated using Pythagoras' theorem in right triangles, which states that the square of the hypotenuse (c) is equal to the sum of the square of the other two sides (a and b), i.e., c² = a² + b²

Since the painting height and viewer height forms the right-angle in this case, we have: a = (h/2 + d), and b = h/2. Substituting a and b in Pythagoras equation, we can solve for c which is the required distance: c = √[(h/2 + d)² + (h/2)²]

Learn more about Optimum viewing distance here:

brainly.com/question/31544283

#SPJ3

Which wave diagram BEST represents a dim red sunset on the right side to the light from an intense ultraviolet bug light on the left side?

Answers

Diagram-A satisfies. High amplitude (bright) and long wavelengths are present on the left (red). & The right side has a short wavelength and low amplitude (dim) (violet).

What are light waves?

Light comes from a source as waves. Each wave has an electric and a magnetic component. Light is hence sometimes referred to as electromagneticradiation.

A large portion of the light in the universetravels with wavelengths that are too short or too long for the human eye to detect, yet our brains interpret light waves by giving distinct colours to the various wavelengths.

The infrared, microwave, and radio spectrum bands have the longest wavelengths. The ultraviolet, x-ray, and gammaradiation have the shortest wavelengths in the electromagnetic spectrum.

Diagram A is therefore satisfactory. On the left, there are long wavelengths with high amplitude (bright) (red). & The right side is dark and has a short wavelength (violet).

For more details regarding waves, visit:

brainly.com/question/29334933

#SPJ5

The wave that best represents it is c.

A wheel starts at rest, and has an angular acceleration of 4 rad/s2. through what angle does it turn in 3.0 s?