Answer:
1 = 5.4 J
2 = 0.1979 C
3 = 5
Explanation:
Energy in a capacitor, E is
E = 1/2 * C * V²
E = 1/2 * 3000*10^-6 * 60²
E = 1/2 * 3000*10^-6 * 3600
E = 1/2 * 10.8
E = 5.4 J
E = Q²/2C = 6.53 J
E * 2C = Q²
Q² = 6.53 * 2 * 3000*10^-6
Q² = 13.06 * 3000*10^-6
Q² = 0.03918
Q = √0.03918
Q = 0.1979 C
The Capacitor, C is inversely proportional to the distance of separation, D. Thus, if D is increased by 5 to be 5D, then C would be C/5. And therefore, our energy stored in the capacitor is increased by a factor of 5.
The correct option is option (1)
The faster movement of air on the upper surface of the paper creates lower pressure above the paper.
The movement of air is always from a region of higher pressure to a region of lower pressure.
As we blow air above the paper strip a low pressure is created above the strip due to the fast movement or high speed of the air. And the pressure below the strip is higher in comparison to the pressure above since the air below is not moving.
So, due to the pressure difference, a force is generated on the paper strip by the air from the lower surface to the upper surface.
Learn more about pressure difference:
This is happened because "the air" above "moves faster" and "the pressure" is "lower".
Option: 1
Explanation:
Air movement take place from the region where air pressure is more than the region where the pressure is low. When we "blow" air above the "paper strip" paper rises because "low pressure" is created above the strip as high speed winds always travel with reduced air pressure. Hence due to higher air pressure below the strip, it is pushed upwards. This difference in pressure results into fast air moves. This happen because "speed" of the wind depends on "the difference between the pressures" of the air in the two regions.
Answer:
Explanation:
Using Conservation of momentum (total final momentum of system is)
m1•v1f + m2•v2 f + m3•v3 f=0
and it must be zero to equal the original momentum( since the original body is at rest).
Given that
original mass M=1.82×10^-26
First disintegrate mass m1=5.18×10^-27kg
In y direction V1f=6×10^6 I'm/s
Second disintegrate mass m2=8.5×10^-27kg
In x direction V2f=4×10^6 im/s
Then the third disintegrate will be
m3=M-m1-m2
m3=1.82×10^-26-5.18×10^-27-8.5×10^-27
m3=4.52×10^-27
And the velocity is unknown
Now using the formula above
m1•v1f + m2•v2 f + m3•v3 f=0
m3•V3f= - m1•v1f - m2•v2 f
4.52E-27V3f=-5.18E-27×6E6j - 8.5E-27×4E6 i
Divide thorough by 4.52E-27
V3f= - 6.88×10^6j - 7.52×10^6i
V3f= - 7.52×10^6i - 6.88×10^6j
The final velocity of the third mass disintegrate is 6.88×10^6j - 7.52×10^6i m/s
Answer:
projectiles
electromagnetic
Answer:
Explanation:
física cuántica y Quantum Moves
Answer:
Moment of inertia will be
Explanation:
We have given mass of the person m = 72 kg
Radius r = 0.8 m
Force is given F = 5 N
Angular acceleration
Torque is given by
We know that torque is also given by
, here I is moment of inertia and
is angular acceleration
So
The average wavelength of radio waves ranges from roughly two millimeters to more than 150 kilometers. The wavelengths of radio waves are the longest in the electromagnetic spectrum
It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.
It is the total length of the wave for which it completes one cycle.
The wavelength is inversely proportional to the frequency of the wave as from the following relation.
C = νλ
They also have the lowest frequencies, ranging from around 4,000 cycles per second, or 3 kilohertz, to roughly 280 billion hertz, or 280 gigahertz.
The wavelengths of radio waves are the longest in the electromagnetic spectrum, ranging from roughly two millimeters to more than 150 kilometers.
To learn more about wavelength from here, refer to the link given below;
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Answer:
Radio waves have frequencies as high as 300 gigahertz(GHz)to as low as 30 hertz(Hz).At 300 GHz the corresponding wavelength is 1mm and at 30Hz is 10,000 km
The initial kinetic energy of the 3.00-kg object traveling at a velocity of 2.00 m/s is 6.00 Joules. When the object's velocity changed to 4.47 m/s, its kinetic energy became 30.02 Joules. Hence, the net work done on the object is 24.02 Joules.
The kinetic energy of any object can be calculated using the formula KE = 0.5 * m * v^2, where m is the object's mass and v is its velocity. For the 3.00-kg object with a velocity of 6.00 i ^ 2 and 2.00 j ^2 m/s, its velocity magnitude would be the square root of (6.00^2 + 2.00^2), which is 2.00 m/s. Plugging the values into the formula, the kinetic energy (a) would be 0.5 * 3.00 * 2.00^2 = 6.00 Joules.
The net work done on an object (b) can be obtained by finding the change in kinetic energy when the object’s velocity changes to 8.00 I and 4.00 j. The final velocity's magnitude would be the square root of (8.00^2 + 4.00^2), which is 4.47 m/s. Hence, the final kinetic energy is 0.5 * 3.00 * 4.47^2 = 30.02 Joules. Therefore, the net work done equals the change in kinetic energy, which is 30.02 - 6.00 = 24.02 Joules.
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