Answer:
-9Q
Explanation:
Electric field at origin is:
Electric field due to first charge at origin would be:
Electric field due to second charge would be:
If the second charge is Q', then should be:
compare the above two values to find the possible values of Q':
The net electric field at origin is greater than the one due to first charge. It means the second charge adds on to the electric field at the origin. Thus, it should be a negative charge.
Thus, Q' = -9Q
One value is possible as the location of the second charge is given to be on the positive x-axis.
The possible values for the unknown charge are 1/9 of the magnitude of the known charge.
To find the possible values for the unknown charge, we need to use the principle of superposition. The net electric field at the origin is given by the sum of the electric fields due to each charge. We know that the magnitude of the net electric field is 2keQ/a^2, so we can set up the equation:
2keQ/a^2 = keQ/(-a)^2 - keq/(3a)^2
By solving this equation, we can find the possible values for the unknown charge. Simplifying the equation, we get:
2 = 1 - 1/9
1/9 = 1
After solving the equation, we find that the possible value for the unknown charge is 1/9 of the magnitude of the known charge.
#SPJ3
Answer: i think you should place it on the red line
Explanation:
hope this helps
and need brainliest
Answer:
Globel warming
Explanation:
hope this helpex
Answer:
the second derivative of y with respect to time gives the transverse acceleration of an element on a string as a wave moves along an x axis along the string
Explanation:
This is because the transverse wave movement of particles take place in direction 90° to direction of movement of the wave (x) itself, so second derivative of y with respect to time (t)is what will be required
Answer:
The add mass = 5.465 kg
Explanation:
Note: Since the spring is the same, the length and Tension are constant.
f ∝ √(1/m)........................ Equation 1 (length and Tension are constant.)
Where f = frequency, m = mass of the spring.
But f = 1/T ..................... Equation 2
Substituting Equation 2 into equation 1.
1/T ∝ √(1/m)
Therefore,
T ∝ √(m)
Therefore,
T₁/√m₁ = k
where k = Constant of proportionality.
T₁/√m₁ = T₂/√m₂ ........................ Equation 3
making m₂ the subject of the equation
m₂ = T₂²(m₁)/T₁²........................... Equation 4
Where T₁ = initial, m₁ = initial mass, T₂ = final period, m₂ = final mass.
Given: T₁ = 1.18 s m₁ = 0.50 kg, T₂ = 2.07 s.
Substituting into equation 4
m₂ = (2.07)²(0.5)/(1.18)²
m₂ = 4.285(1.392)
m₂ = 5.965 kg.
Added mass = m₂ - m₁
Added mass = 5.965 - 0.5
Added mass = 5.465 kg.
Thus the add mass = 5.465 kg
b.) they only fish during the warmest times of the day
c. they must know the right time of year for Gathering certain foods
d.) they still catch walleye with the steering method
The Ojibwe people pay close attention to the seasons in order to know right
time of year for gathering certain foods.
The Ojibwe mostly hunt for fishes through the use of various techniques
such as:
They hunt for fishes at night because they are usually docile during that time
which enables them to catch them easily as against during the day when
they are much active.
Read more about Ojibwe people here brainly.com/question/24963033
Answer:C. They must know the right time of year for gathering certain foods
Explanation:
I got it correct