evaporating a liquid
cooling a solid
cooling a liquid
What volume of oxygen gas is released at STP if 10.0 g of potassium chlorate is decomposed? (The molar mass of KClO3 is 122.55 g/mol.)
Your answer is 2.74.
calcium
titanium
scandium
Answer:
Scandium
Explanation:
Answer: grams
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number of particles.
To calculate the moles, we use the equation:
Now 1 mole of gas weighs = 28 grams
of gas weighs = grams
Thus the mass will be grams.
Hey there!
Molar mass N2 = 28.01 g/mol
Therefore:
28.01 g N2 -------------- 6.02*10²² molecules N2
( mass N2 ?? ) ----------- 25,000 molecules N2
mass N2 = ( 25,000 * 28.01 ) / ( 6.02*10²³ )
mass N2 = 700250 / 6.02*10²³
mass N2 = 1.163*10⁻¹⁸ g
Hope that helps!
Answers:
Bohr's model agrees with Thompson's model as both hold the fact that there are three sub=atomic particles which makes up an atom and there are equal number of protons and electron in a neutral atom
Explanation:
Bohr's model describes an atom as a planetary like shape in which the electrons revolve round the nucleus which is composed of protons and neutrons.
Thompson's model states an atom as a sphere which is composed of electrons surrounded by positively charged ions.
B. Calcium chloride (CaCl2)
C. Potassium Iodide (KI)
D. Glucose (C6H12O6)
Answer:
Explanation:
The colligative properties depend on the concentration of particles (molecules or ions) of solute dissolved and not on the identity of the solute.
For your reference the colligative properties are: i) boiling point increase, ii) freezing point depression, iii) vapor pressure lowering, and iv) osmotic pressure.
When the solute is a ionic compound the ionization yields several ions, so for ionic solutes you must predict first the number or ions formed per unit of compound and then predict the effect on the colligative properties: the greater the number of ions per unit of compound the greater the effect on colligative properties.
So, just set the ionization equations for each compound:
Then, since calcium chloride, CaCl₂, produces the greater number of ions it is the solute that productes the greatest effect on colligative properties.
Answer:
D. Calcium chloride (CaCl2)
Explanation:
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