ans) 115/100=1.15 hours
binary fission
detection of light
detection of danger
The euglena's red eyespot is used for detection of light.
Answer:
binary fission
Explanation:
b. neutral
c. positive
d. negative
Answer: The correct answer is Option c.
Explanation:
Ions are formed when an atom looses or gains electrons.
If an atom gains electrons, it leads to the formation of negative ions known as anions. For Example: Fluorine gains 1 electron to form ions.
If an atom looses electrons, it leads to the formation of positive ions known as cations. For Example: Sodium looses 1 electron to form ions.
Hence, the correct answer is Option c.
A ________ ion is created when an electron is removed.
a. stable
b. neutral
c. positive
d. negative
A cation or positive ion is created when an electron is removed. The answer is letter C.
Radical chlorination of pentane and neopentane results in different yields of the desired products due to the selectivity of the reaction. With neopentane, the reaction is very selective, producing a higher yield of neopentyl chloride, while with pentane, the reaction isn't selective, leading to various isomers and a lower yield of 1-chloropentane.
Radical chlorination of pentane isn't an efficient method to prepare 1-chloropentane because it doesn't give a high yield of the desired product. This is due to it being a non-selective process, leading to the formation of several isomeric products. In the case of pentane, several different hydrogens can be replaced creating many possible isomers of chloropentane.
On the other hand, radical chlorination of neopentane or (CH3)4C is a good way to prepare neopentyl chloride or (CH3)3CCH2Cl. This is because neopentane has a far greater proportion of equivalent tertiary hydrogens. When chlorination occurs, it's most likely to happen at these sites, producing a higher yield of the desired neopentyl chloride product with less chance of isomer formation.
This difference is due to the selectivity and specificity of the radical chlorination reaction on neopentane versus pentane. Radical chlorination is not very selective with pentane but is quite selective with neopentane due to the type of hydrogens present, thus making it a more ideal reaction.
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b. The concentration of Cl⁻ ion will be 0.1M.
c. The concentration of undissociated H₂O molecules remains unchanged.
d. The pH of the beaker's contents will be neutral.
e. The pH of the beaker's contents falls.
Answer: Option (e) is the correct answer.
Explanation:
Since, the beaker contains NaOH solution whose pH is 13. As pH of NaOH is greater than 7 so, it means that this solution is basic in nature.
Whereas pH of HCl solution is equal to 1. As its pH is less that 7 so, it is acidic in nature.
Hence, when we add 10 ml of HCl into 100 mL of NaOH then there will be a slight decrease in pH of the solution because an acid is being added into the NaOH solution.
Thus, we can conclude that the statement pH of the beaker's contents falls, correctly describes the results of this mixing.