The surface pressure of the atmosphere is about 14.7 psi (pounds per square inch). How many pounds per square yard does that amount to

Answers

Answer 1
Answer:

Answer:

14.7 psi is equal to 19051.2 pounds per square yard.

Explanation:

Dimensionally speaking, a square yard equals 1296 square inches. Therefore, we need to multiply the atmospheric pressure by 1296 to obtain its equivalent in pounds per square yard. That is:

p = 14.7\,(lbf)/(in^(2))* 1296\,(in^(2))/(yd^(2))

p = 19051.2\,(lbf)/(yd^(2))

14.7 psi is equal to 19051.2 pounds per square yard.


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Consider a proton travelling due west at a velocity of 5×10^5m/s. Assuming that the rth magnetic field has a strength of 5x10^-5Tand is directed due south calculate li) the magnitude of the force on the proton (q= 1.6x10^-9C)​

Answers

Answer:

Consider a proton travelling due west at a velocity of 5×10^5m/s. Assuming that the rth magnetic field has a strength of 5x10^-5Tand is directed due south calculate li) the magnitude of the force on the proton (q= 1.6x10^-9C)​

Explanation:

In a Venn diagram, the separate circles contain characteristics unique to each item being compared and the intersection contains characteristics that are common to both items being compared. Ernie is working on the Venn diagram below to compare the career pathways of Biotechnology Research and Development and Diagnostic Services.What else could Ernie put in the common section?

Collecting data and analyzing results
Designing and implementing systems
Maintaining and using diagnostic equipment
Designing and using laboratory equipment
Mark this and return

Answers

Another thing that  Ernie put in the common section is collecting data and analyzing results.

What is a Venn diagram?

A Venn diagram is used to show a representation of data. The center of the Venn diagram is often used to indicate the data set that is the same.

Looking at the Venn diagram, another thing that  Ernie put in the common section is collecting data and analyzing results.

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I think its- Collecting data and analyzing results
Thats what I put.

The magnetic field produced by the solenoid in a magnetic resonance imaging (MRI) system designed for measurements on whole human bodies has a field strength of 5.81 T, and the current in the solenoid is 3.79 × 102 A. What is the number of turns per meter of length of the solenoid?

Answers

Answer:

n = 1.22 10⁴ turns/m

Explanation:

The magnetic field in a solenoid is proportional to the intensity of the current, the number of turns per unit length (n) and the magnetic permeability (myo), is described by the equation

      B = μ₀ n I

Let's clear the density of turns

     n = B / (μ₀ I)

Let's replace and calculate

     n = 5.81 / (4pi 10-7 3.79 102)

     n = 5.81 105 / 47.63

     n = 1.22 10⁴ turns / m

An object is made from a material that is hard, shiny, and can be hammered into thin sheets. Which of these is another likely property of the material?

Answers

Answer:

Good conductor of heat

Explanation:

Because metals are shiny, ductile, malleable, sonorous, good conductors of heat and electricity and have high melting and boiling points

Answer: mine is different so im sorry im here for points

Explanation:

Burns produced by steam at 100°C are much more severe than those produced by the same mass of 100°C water. Calculate the quantity of heat in (Cal or kcal) that must be removed from 6.1 g of 100°C steam to condense it and lower its temperature to 46°C. Specific heat of water = 1.00 kcal/(kg · °C); heat of vaporization = 539 kcal/kg; specific heat of human flesh = 0.83 kcal/(kg · °C).

Answers

Final answer:

To calculate the quantity of heat that must be removed from 6.1 g of 100°C steam, we need to consider both the change in temperature and the phase change from steam to liquid. The specific heat of water is used to calculate the heat required to lower the temperature, while the heat of vaporization is used to calculate the heat required to condense the steam. Adding these two heat values together gives us the total amount of heat that must be removed from the steam, which is approximately 3.61164 kcal.

Explanation:

When steam at 100°C condenses and its temperature is lowered to 46°C, heat must be removed from the steam. To calculate the amount of heat, we can use the specific heat of steam and the latent heat of vaporization. First, we calculate the heat required to lower the temperature of the steam from 100°C to 46°C using the specific heat of water. We then calculate the heat required to condense the steam using the latent heat of vaporization. Finally, we add these two heat values together to obtain the total amount of heat that must be removed from the steam.

Given:

  • Mass of steam = 6.1 g
  • Temperature change = 100°C - 46°C = 54°C
  • Specific heat of water = 1.00 kcal/(kg · °C)
  • Heat of vaporization = 539 kcal/kg


Calculations:

  1. Heat required to lower the temperature of the steam:
    Q1 = mass × specific heat × temperature change
     = 6.1 g × (1.00 kcal/(kg · °C) ÷ 1000 g) × 54°C
  2. Heat required to condense the steam:
    Q2 = mass × heat of vaporization
      = 6.1 g × (539 kcal/kg ÷ 1000 g)
  3. Total heat required:
    Q = Q1 + Q2

Calculation:

  1. Q1 = 0.32874 kcal
  2. Q2 = 3.2829 kcal
  3. Q = Q1 + Q2 = 0.32874 kcal + 3.2829 kcal = 3.61164 kcal


Therefore, the quantity of heat that must be removed from 6.1 g of 100°C steam to condense it and lower its temperature to 46°C is approximately 3.61164 kcal.

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Final answer:

To condense and cool 6.1 g of 100°C steam to 46°C, 3.2879 kcal must be removed for condensation, and 0.3304 kcal for cooling, for a total of 3.6183 kcal.

Explanation:

Calculating the Quantity of Heat for Condensation and Cooling

To calculate the quantity of heat that must be removed from 6.1 g of 100°C steam to condense it and lower its temperature to 46°C, we need to consider two processes: condensation and cooling. For condensation, we use the heat of vaporization, and for cooling, we use the specific heat of water.

  1. Calculate the heat released during condensation of steam into water at 100°C:
     Heat = mass × heat of vaporization
     Heat (in kcal) = (6.1 g) × (539 kcal/kg) × (1 kg / 1000 g)
     Heat = 3.2879 kcal
  2. Calculate the heat released when the water cools from 100°C to 46°C:
     Heat = mass × specific heat × change in temperature
     Heat (in kcal) = (6.1 g) × (1.00 kcal/kg°C) × (1 kg / 1000 g) × (100°C - 46°C)
     Heat = 0.3304 kcal

Total heat removed is the sum of the heat from both steps: 3.2879 kcal + 0.3304 kcal = 3.6183 kcal.

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Air contained in a rigid, insulated tank fitted with a paddle wheel, initially at 300 K, 2 bar, and a volume of 2 m3 , is stirred until its temperature is 500 K. Assuming the ideal gas model for the air, and ignoring kinetic and potential energy, determine (a) the final pressure, in bar, (b) the work, in kJ, and (c) the amount of entropy produced, i

Answers

Final answer:

To find the final pressure, use the ideal gas law equation PV = nRT, where P is the initial pressure, V is the initial volume, n is the number of moles of gas, R is the gas constant, and T is the initial temperature. Rearrange the equation and plug in the given values to find that the final pressure is 3.33 bar.

Explanation:

To find the final pressure, we can use the ideal gas law equation: PV = nRT, where P is the initial pressure, V is the initial volume, n is the number of moles of gas, R is the gas constant, and T is the initial temperature.

Since the volume and the amount of air are constant, we can rearrange the equation to solve for the final pressure:

P2 = P1 * (T2 / T1),

where P2 is the final pressure, T2 is the final temperature, and T1 is the initial temperature.

By plugging in the values from the problem, we can find that the final pressure is 3.33 bar.

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