Answer:
14.7 psi is equal to 19051.2 pounds per square yard.
Explanation:
Dimensionally speaking, a square yard equals 1296 square inches. Therefore, we need to multiply the atmospheric pressure by 1296 to obtain its equivalent in pounds per square yard. That is:
14.7 psi is equal to 19051.2 pounds per square yard.
Answer:
Consider a proton travelling due west at a velocity of 5×10^5m/s. Assuming that the rth magnetic field has a strength of 5x10^-5Tand is directed due south calculate li) the magnitude of the force on the proton (q= 1.6x10^-9C)
Explanation:
Collecting data and analyzing results
Designing and implementing systems
Maintaining and using diagnostic equipment
Designing and using laboratory equipment
Mark this and return
Another thing that Ernie put in the common section is collecting data and analyzing results.
A Venn diagram is used to show a representation of data. The center of the Venn diagram is often used to indicate the data set that is the same.
Looking at the Venn diagram, another thing that Ernie put in the common section is collecting data and analyzing results.
Learn more about Venn diagrams:brainly.com/question/1605100
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Answer:
n = 1.22 10⁴ turns/m
Explanation:
The magnetic field in a solenoid is proportional to the intensity of the current, the number of turns per unit length (n) and the magnetic permeability (myo), is described by the equation
B = μ₀ n I
Let's clear the density of turns
n = B / (μ₀ I)
Let's replace and calculate
n = 5.81 / (4pi 10-7 3.79 102)
n = 5.81 105 / 47.63
n = 1.22 10⁴ turns / m
Answer:
Good conductor of heat
Explanation:
Because metals are shiny, ductile, malleable, sonorous, good conductors of heat and electricity and have high melting and boiling points
Answer: mine is different so im sorry im here for points
Explanation:
To calculate the quantity of heat that must be removed from 6.1 g of 100°C steam, we need to consider both the change in temperature and the phase change from steam to liquid. The specific heat of water is used to calculate the heat required to lower the temperature, while the heat of vaporization is used to calculate the heat required to condense the steam. Adding these two heat values together gives us the total amount of heat that must be removed from the steam, which is approximately 3.61164 kcal.
When steam at 100°C condenses and its temperature is lowered to 46°C, heat must be removed from the steam. To calculate the amount of heat, we can use the specific heat of steam and the latent heat of vaporization. First, we calculate the heat required to lower the temperature of the steam from 100°C to 46°C using the specific heat of water. We then calculate the heat required to condense the steam using the latent heat of vaporization. Finally, we add these two heat values together to obtain the total amount of heat that must be removed from the steam.
Given:
Calculations:
Calculation:
Therefore, the quantity of heat that must be removed from 6.1 g of 100°C steam to condense it and lower its temperature to 46°C is approximately 3.61164 kcal.
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To condense and cool 6.1 g of 100°C steam to 46°C, 3.2879 kcal must be removed for condensation, and 0.3304 kcal for cooling, for a total of 3.6183 kcal.
Calculating the Quantity of Heat for Condensation and Cooling
To calculate the quantity of heat that must be removed from 6.1 g of 100°C steam to condense it and lower its temperature to 46°C, we need to consider two processes: condensation and cooling. For condensation, we use the heat of vaporization, and for cooling, we use the specific heat of water.
Total heat removed is the sum of the heat from both steps: 3.2879 kcal + 0.3304 kcal = 3.6183 kcal.
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To find the final pressure, use the ideal gas law equation PV = nRT, where P is the initial pressure, V is the initial volume, n is the number of moles of gas, R is the gas constant, and T is the initial temperature. Rearrange the equation and plug in the given values to find that the final pressure is 3.33 bar.
To find the final pressure, we can use the ideal gas law equation: PV = nRT, where P is the initial pressure, V is the initial volume, n is the number of moles of gas, R is the gas constant, and T is the initial temperature.
Since the volume and the amount of air are constant, we can rearrange the equation to solve for the final pressure:
P2 = P1 * (T2 / T1),
where P2 is the final pressure, T2 is the final temperature, and T1 is the initial temperature.
By plugging in the values from the problem, we can find that the final pressure is 3.33 bar.
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