Answer:
1.4 g H₂O
Explanation:
In a reaction, the reactants are usually not present in exactstoichiometric amounts, that is, in the proportions indicated by the balanced equation. Frequently a large excess of one reactant is supplied to ensure that the more expensive reactant is completely converted to the desired product. Consequently, some reactant will be left over at the end of the reaction. The reactant used up first in a reaction is called the limiting reagent, because the maximum amount of product formed depends on how much of this reactant was originally present. When this reactant is used up, no more product can be formed.
Answer:
1 litre of 1.0 M NaCl
Explanation:
When an ionic compound dissolves in water, it dissociates into ions. Consider the dissolution of sodium chloride in water;
NaCl(s) ------> Na^+(aq) + Cl^-(aq)
Hence, two solute particles are obtained from each formula unit of NaCl, a greater concentration of NaCl will contain a greater number of sodium an chloride ion particles.
Glucose is a molecular substance and does not dissociate in solution hence it yields a lesser number of particles in solution even at the same concentration as NaCl
The solution with the greatest number of solute particles is 1 litre of 1.0 M NaCl, as ionic compounds dissociate into individual ions, thus providing more particles per litre.
Given the details of the question, the solution that would be expected to contain the greatest number of solute particles would be 1 litre of 1.0 M NaCl. This is because when ionic compounds like sodium chloride are placed in water, they dissociate into individual ions. In the case of NaCl, it splits into two ions, sodium (Na+) and chloride (Cl-). Thus, a 1.0 M solution of NaCl would actually contain 2.0 moles of particles per litre because each formula unit of NaCl gives two particles. Covalently bonded molecules like glucose do not dissociate in solution, therefore, a 1.0 M glucose solution would have 1.0 mole of particles per litre.
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B. atom
C. neutron
D. electron
Answer:
D. electron
Explanation:
Electrons have a negative charge
The second option 1,870.4 Joules
highland
it is actually science on the subject but it doesn't have that option.
marine west coast
Mediterranean
subarctic
tropical wet-dry
Marine west coast and Mediterranean are the types of temperate climates, due to the dispersion of precipitation throughout the year, temperate marine climates are typically distinguished by a notable lack of dry season, hence options D and E are correct.
Temperate climates are regions with moderate annual or seasonal rainfall, intermittent drought, mild to warm summers, and cool to cold winters.
Humid subtropical, marine west coast, Mediterranean are the phrases that clearly identified with temperate marine climates.
Geographically speaking, the moderate climates of Earth are found in the middle latitudes, which are halfway between the tropics and the poles.
Therefore, options D and E are correct.
Learn more about temperate climates, here:
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Answer:
Humid Continental
Marine west coast
Mediterranean
subarctic
Explanation:
just did assignment on edge
Answer
Density = 7.87g/cm^3
Explanation:
Density is the ratio of mass of the given object to the volume of the object, in this question iron is the given object, then we make use of atomic number of iron
Given:
Length= 287pm = 287*10^-10cm
Atomic mass of Fe= 56.0u
Z=2(for body centered cubic unit cell)
Avogadro number (N 0)=6.022× 10^23
Density= ZM/a^3 × N
Where
Z= body centered cubic unit cell
Then substitute
N= Avogadro's number
a=Length
Density = (2× 56)/(287*10^-10cm)^3 × (6.022 × 10^23)
Density = 7.87g/cm^3
The density of iron in a body-centered cubic unit cell can be calculated using the mass and volume of the unit cell.
The density of iron can be calculated using the formula: density = mass/volume. To determine the mass of the unit cell, we need to know the molar mass of iron and the number of atoms in the unit cell. The molar mass of iron is 55.845 g/mol, and there are two iron atoms in the body-centered cubic unit cell of iron. The volume of the unit cell can be calculated using the formula: volume = (edge length)^3.
Putting these values into the formula, we get:
density = (2 * 55.845 g/mol) / ((287 pm)^3)
Converting the edge length to meters (1 pm = 1e-12 m) and calculating, we find that the density of iron is approximately 7.86 g/cm³.
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