PHYSICS COLLEGE

Suppose that a ball is dropped from the upper observation deck of the CN Tower in Toronto, 450 m above the ground. Find the velocity of the ball after 2 seconds.

Answers

Answer 1
Answer:

Answer:.

Required velocity = 6.26ms^-1

Explanation:

Given,

Distance, s = 450m

Time, t = 2 sec

Step 1. We obtain the distance covered within the given time under gravitational acceleration, g = 9.8ms^-2

S = ut + (1/2)gt^2. :; u = 0

: S = (1/2)gt^2

=(1/2) (9.8)(2^2)

= 19.6m

Step 2 :

We obtain the velocity using the formula.

V^2 = u^2 + 2gs.

Where u is initial velocity, v is final/ required velocity

Again u = 0

: V^2 = 2 (9.8)(19.6)

= 39.2

: V = 6.26ms^-1

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An 800-kHz sinusoidal radio signal is detected at a point 6.6 km from the transmitter tower. The electric field amplitude of the signal at that point is 0.780 V/m. Assume that the signal power is radiated uniformly in all directions and that radio waves incident upon the ground are completely absorbed. What is the amplitude of the magnetic field of the signal at that point

Answers

Answer:

0.0000000026 T

Explanation:

E_0 = Maximum electric field strength = 0.78 V/m

B_0 = Maximum magnetic field strength

c = Speed of light = 3* 10^8\ m/s

Relation between amplitudes of electric and magnetic fields is given by

E_0=B_0c\n\Rightarrow B_0=(E_0)/(c)\n\Rightarrow B_0=(0.78)/(3* 10^8)\n\Rightarrow B_0=0.0000000026\ T

The amplitude of the magnetic field is 0.0000000026 T

Burns produced by steam at 100°C are much more severe than those produced by the same mass of 100°C water. Calculate the quantity of heat in (Cal or kcal) that must be removed from 6.1 g of 100°C steam to condense it and lower its temperature to 46°C. Specific heat of water = 1.00 kcal/(kg · °C); heat of vaporization = 539 kcal/kg; specific heat of human flesh = 0.83 kcal/(kg · °C).

Answers

Final answer:

To calculate the quantity of heat that must be removed from 6.1 g of 100°C steam, we need to consider both the change in temperature and the phase change from steam to liquid. The specific heat of water is used to calculate the heat required to lower the temperature, while the heat of vaporization is used to calculate the heat required to condense the steam. Adding these two heat values together gives us the total amount of heat that must be removed from the steam, which is approximately 3.61164 kcal.

Explanation:

When steam at 100°C condenses and its temperature is lowered to 46°C, heat must be removed from the steam. To calculate the amount of heat, we can use the specific heat of steam and the latent heat of vaporization. First, we calculate the heat required to lower the temperature of the steam from 100°C to 46°C using the specific heat of water. We then calculate the heat required to condense the steam using the latent heat of vaporization. Finally, we add these two heat values together to obtain the total amount of heat that must be removed from the steam.

Given:

  • Mass of steam = 6.1 g
  • Temperature change = 100°C - 46°C = 54°C
  • Specific heat of water = 1.00 kcal/(kg · °C)
  • Heat of vaporization = 539 kcal/kg


Calculations:

  1. Heat required to lower the temperature of the steam:
    Q1 = mass × specific heat × temperature change
     = 6.1 g × (1.00 kcal/(kg · °C) ÷ 1000 g) × 54°C
  2. Heat required to condense the steam:
    Q2 = mass × heat of vaporization
      = 6.1 g × (539 kcal/kg ÷ 1000 g)
  3. Total heat required:
    Q = Q1 + Q2

Calculation:

  1. Q1 = 0.32874 kcal
  2. Q2 = 3.2829 kcal
  3. Q = Q1 + Q2 = 0.32874 kcal + 3.2829 kcal = 3.61164 kcal


Therefore, the quantity of heat that must be removed from 6.1 g of 100°C steam to condense it and lower its temperature to 46°C is approximately 3.61164 kcal.

Learn more about Heat transfer here:

brainly.com/question/13433948

#SPJ12

Final answer:

To condense and cool 6.1 g of 100°C steam to 46°C, 3.2879 kcal must be removed for condensation, and 0.3304 kcal for cooling, for a total of 3.6183 kcal.

Explanation:

Calculating the Quantity of Heat for Condensation and Cooling

To calculate the quantity of heat that must be removed from 6.1 g of 100°C steam to condense it and lower its temperature to 46°C, we need to consider two processes: condensation and cooling. For condensation, we use the heat of vaporization, and for cooling, we use the specific heat of water.

  1. Calculate the heat released during condensation of steam into water at 100°C:
     Heat = mass × heat of vaporization
     Heat (in kcal) = (6.1 g) × (539 kcal/kg) × (1 kg / 1000 g)
     Heat = 3.2879 kcal
  2. Calculate the heat released when the water cools from 100°C to 46°C:
     Heat = mass × specific heat × change in temperature
     Heat (in kcal) = (6.1 g) × (1.00 kcal/kg°C) × (1 kg / 1000 g) × (100°C - 46°C)
     Heat = 0.3304 kcal

Total heat removed is the sum of the heat from both steps: 3.2879 kcal + 0.3304 kcal = 3.6183 kcal.

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The pedals on a bicycle give a mechanical advantage by allowing you to turn the pedals a __________ distance to turn the __________ circumstance of the wheels.

Answers

Answer:

C. Short, larger

Explanation:

It's the correct answer on USA test prep.

short distance to turn the circumference of the wheels. Mechanical advantage is load/effort I think

Convert this measurement
664.2 km=____cm

Answers

(664.2 km) · (1,000 m/km) · (100 cm/m) =

(664.2 · 1,000 · 100) (km·m·cm/km·m) =

66,420,000 cm

For metric conversion, you can remember this acronym for help:

King Henry died unusually drinking chocolate milk. Which stand for:

Kilo - unit * 1000

Hecto - unit * 100

Deca - unit * 10

Unit - unit * 1

Deci - unit * (1)/(10)

Centi - unit * (1)/(100)

Milli - unit * (1)/(100)

Kilometers and centimeters are five places apart apart, so you move the decimal point in 664.2 to the right five times, which means 664.2 km = 66420000 cm.

To avoid confusion on which direction to move the decimal point, imagine two shapes on each end of a scale. On each end, there is one large shape and one small shape. There has to be one of each on either side for it to balance. For this problem, a kilometer is a larger unit than a centimeter, so this means that the blank space needs to have a number greater than 664.2, or else the scale won't balance. Hope this helped.

Make the following conversion.56.32 kL = _____ L

0.056320
0.56320
5,632
56,320

Answers

Answer:

The answer would be D 56,320

Explanation:

Each shot of the laser gun most favored by Rosa the Closer, the intrepid vigilante of the lawless 22nd century, is powered by the discharge of a 1.89 Fcapacitor charged to 60.9 kV. Rosa rightly reckons that she can enhance the effect of each laser pulse by increasing the electric potential energy of the charged capacitor. She could do this by replacing the capacitor's filling, whose dielectric constant is 431, with one possessing a dielectric constant of 947.Required:
a. Find the electric potential energy of the original capacitor when it is charged. (in Joules)
b. Calculate the electric potential energy of the upgraded capacitor when it is charged. ( In Joules)

Answers

Answer:

a

U  =  3.505 *10^9 \  J

b

U_1 = 7.696 *10^9 \ J

Explanation:

From the question we are told that

The capacitance is C = 1.89 \ F

The voltage is V = 60.9 \ k V = 60.9 *10^(3) \ V

The first dielectric constant is \epsilon_1 = 431

The second dielectric constant is \epsilon_2 = 947

Generally the electric potential energy is mathematically represented as

U = (1)/(2) * C * V^2

=> U = (1)/(2) * 1.89 * (60.9 *10^(3))^2

=> U = 3.505 *10^9 \ J

Generally the capacitance when the capacitor's filling was changed is

C_n = 1.89 * (947)/(431)

=>   C_n  =  4.15

Generally the electric potential energy when the capacitor's filling  was changed is

       U_1  =  (1)/(2)  *  C_1  * V^2

=>  U_1  =  (1)/(2)  *   4.15  * (60.9 *10^(3))^2

=>  U_1  = 7.696 *10^9 \  J
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Go to his profile and roast the mess out of him plzz 403665fl 50 points