The breakfast cafe uses 3 1/4 lb of coffee per day. How much coffee does it use ina 7 day week?​

Answers

Answer 1
Answer:

Quantity of coffee used per day by breakfast cafe =

= 3 (1)/(4)  \: lb

Quantity of coffee it will use in a seven day week =

= 3 (1)/(4)  * 7

=  ((4 * 3) + 1)/(4)  * 7

=  (13)/(4)  *  (7)/(1)

=  (91)/(4)

= 22 (3)/(4)  \: lb

Therefore , a breakfast cafe will use =

22 (3)/(4)  \: lb \: of \: coffee \: in \: a \: seven \: day \: week \: .

Answer 2
Answer:

Final answer:

By multiplying the daily coffee consumption of 3 1/4 lbs by 7, we find that the cafe uses 22 3/4 lbs of coffee in a week.

Explanation:

In a week, the cafe's coffee consumption is calculated by multiplying its daily usage of 3 1/4 lbs by 7 (the number of days in a week). This computation yields 22 3/4 lbs as the total weekly coffee consumption. This process involves multiplying the daily quantity by the number of days to obtain the weekly total. Therefore, the cafe utilizes 22 3/4 lbs of coffee throughout a 7-day week. This method of determining weekly coffee usage is crucial for managing inventory and ensuring that the cafe meets the demands of its customers efficiently. By understanding their weekly consumption, the cafe can effectively plan and stock their coffee supply.

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What is 2 3 of 99kg?

Answers

Step-by-step explanation:

(2)/(3)  *  (99)/(1)  = 66 \: kg

A box of cereal weighs 0.75 pounds. how many ounces are in 0.75 pounds? (1 lb = 16oz)

Answers

So we want to perform a change of units for the weight of a box of cereal. We will see that it weighs 12 ounces.

We know that it weighs 0.75 pounds, and we want to know how many ounces it weighs.

And we know that:

  • 1 lb = 16 oz.

Then we can rewrite the weight as:

W = 0.75 lb = 0.75*( 1 lb) = 0.75*(16 oz) = 12 oz

So the box of cereal weighs 12 ounces.

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Answer:

24

Step-by-step explanation:

one cup is 8 ounces times three is 24

A fisherman uses a spring scale to weigh a tilapia fish. He records the fish weight as a kilograms and notices that the spring stretches b centimeters. Which expression represents the spring constant (1 =9.8 )? A). 980ab B). 9.8ab C). 9.8ab D). 980ab

Answers

Answer:

k = (980a)/(b)

Step-by-step explanation:

Fisherman noticed a stretch in the spring = 'b' centimetres

Weight of the fish = a kilograms

If force applied on a spring scale makes a stretch in the spring then Hook's law for the force applied is,

F = kΔx

Where k = spring constant

Δx = stretch in the spring

F = weight applied

F = mg

Here 'm' = mass of the fish

g = gravitational constant

F = a(9.8)

  = 9.8a

Δx = b centimetres = 0.01b meters

Therefore, 9.8a = k(0.01b)

k = (9.8a)/(0.01b)

k = (980a)/(b)

Therefore, spring constant of the spring will be determined by the expression, k = (980a)/(b)

jack spends 15 of his pocket money on sweets and 35% on magazines. he saves the rest.Work out how much he spends each week

Answers

Jack spends 15% on sweets each week and 35% on magazines. His total spendings(15%+35%=50%)equals 50%.Savings is 100% - 50%= 50%.So, if jack gets $100 each week, he spends $15 on sweets, $35 on magazines, and $50 goes towards savings. Hope this helps!

Final answer:

Jack spends $50 each week.

Explanation:

To calculate how much Jack spends each week, we need to find the amount he spends on sweets and magazines and subtract it from his pocket money. First, we calculate the amount Jack spends on magazines. Let's assume his pocket money is $100:

  1. Amount spent on sweets = 15% of $100 = $15
  2. Amount spent on magazines = 35% of $100 = $35

To find the amount Jack saves, we subtract the amount spent on sweets and magazines from his pocket money:

Total spent on sweets and magazines = $15 + $35 = $50

Amount saved each week = Pocket money - Total spent on sweets and magazines = $100 - $50 = $50

Therefore, Jack saves $50 each week.

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A particular concentration of a chemical found in polluted water has been found to be lethal to 40% of the crayfish that are exposed to the concentration for 24 hours. 22 crayfish are placed in a tank containing this concentration of chemical in the water. (a) What is the probability that 13 or 17 survive?
(b) What is the probability that at least 17 survive?
(c) What is the probability that at most 16 survive?
(d) What number of crayfish are expected to survive?
(e) What is the variance in the number of crayfish that are expected to survive? No actual crayfish were harmed in the making of this question.

Answers

Answer:

a) P(X=13)=(24C13)(0.4)^(13) (1-0.4)^(24-13)=0.0608

P(X=17)=(24C17)(0.4)^(17) (1-0.4)^(24-17)=0.0017

P(X=13 U X=17) = 0.0608+0.0017=0.0624

b) P(X \geq 17)=0.000427

c) P(X \geq 16)= 1-0.000427=0.9996

d) E(X)= np = 22*0.4=8.8

e) Var(X) = np(1-p)= 22*0.4*(1-0,4)=5.28

Step-by-step explanation:

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=24, p=0.4)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^(n-x)

Where (nCx) means combinatory and it's given by this formula:

nCx=(n!)/((n-x)! x!)

3) Part a

P(X=13)=(22C13)(0.4)^(13) (1-0.4)^(22-13)=0.0336

P(X=17)=(22C17)(0.4)^(17) (1-0.4)^(22-17)=0.00035

P(X=13 U X=17) = 0.0336+0.00035=0.0340

4) Part b

P(X \geq 17)=P(X=17)+P(X=18)+P(X=19)+P(X=20)+P(X=21)+P(X=22)

P(X=17)=(22C17)(0.4)^(17) (1-0.4)^(22-17)=0.00035

P(X=18)=(22C18)(0.4)^(18) (1-0.4)^(22-18)=0.0000651

P(X=19)=(22C19)(0.4)^(19) (1-0.4)^(22-19)=0.00000914

P(X=20)=(22C20)(0.4)^(20) (1-0.4)^(22-20)=0.000000914

P(X=21)=(22C21)(0.4)^(21) (1-0.4)^(22-21)=5.81x10^(-8)

P(X=22)=(22C22)(0.4)^(22) (1-0.4)^(22-22)=1.76x10^(-9)

P(X \geq 17)=0.000427

5) Part c

P(X \leq 16)=1-P(X>16)=1-P(X\geq 17) = 1-[P(X=17)+P(X=18)+P(X=19)+P(X=20)+P(X=21)+P(X=22)]

P(X \geq 16)= 1-0.000427=0.9996

6) Part d

The expected value is:

E(X)= np = 22*0.4=8.8

7) Part e

The variance is given by:

Var(X) = np(1-p)= 22*0.4*(1-0,4)=5.28

Solve by graphing

y+5 = 2x
3y + 6x = -3

Answers

Answer:

(1, -3)

Step-by-step explanation:

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