Answer:
3003
Step-by-step explanation:
We want to find out how many ways we can choose 10 players among 15 players (since the goalie is not interchangeable)
The number of different lineups you can have can be found by using combination:
There are 3003 different lineups that can be chosen.
To determine the number of starting lineups, we use combinations in probability. We first choose a goalie from 16 players, then 10 regular players from the remaining 15, giving us 48048 unique lineups.
This problem can be solved by using the concept of combinations in probability and statistics. The formula for combinations is C(n, k) = n! / [k!(n-k)!], where n is the total number of items, k is the number of items to choose, and ! denotes factorial, which is the product of all positive integers up to that number.
Firstly, we need to choose a goalie. There are 16 players, so the number of ways to choose a goalie is C(16, 1) = 16.
After choosing the goalie, we are left with 15 players. Then we need to choose 10 players to fill in the rest of the team. Thus, the number of ways to choose the 10 regular players is C(15, 10).
The total number of unique starting lineups is then the product of these two results. Hence, the solution would be C(16, 1) * C(15, 10) = 16 * 3003 = 48048 different starting lineups.
#SPJ3
Answer:
406
Step-by-step explanation:
We need to find the unit rate or how many miles can they drive in 1 hour. So we do 696/12 which is 58. So we have 58 miles in 1 hour. Now we multiply the number of desired hours, 7 and multiply it by 696. Which is 406
Answer: it think its 60
Step-by-step explanation:
Answer:...
Step-by-step explanation:
Answer:
Let fertilizer be F
and peat moss be P
since F is proportional to P
F = kP
where, k = constant of proportionality
k = F/P
putting in the values,
k = (3/4) /12
k = 3/4 * 1/12
k = 1/16
Therefore the constant of proportionality is 1/16.
Answer: z= 1.51
Step-by-step explanation:
Test statistic for proportion is given by :-
Where n is sample size ,p is the sample proportion , P Is the population proportion and Q =1 - P.
Given : P=57% = 0.57
Q= 1- P = 1-0.57=0.43
n = 25
Test statistic for proportion will be :-
We should report the value of test statistic z= 1.51