Suppose you were exploring the hypothesis that there is a relationship between parents’ and children’s party identification. Would we be correct in inferring that such a relationship also exists in the population? Explain your answer. What is the probability that any relationship we found is due to pure chance?

Answers

Answer 1

Answer:

Answer:

It could be purely due to chance.

Step-by-step explanation:

A population is defined as the whole group which has the same characteristics. For example a population of the college belongs to the same college . But a sample may be an element of a population.

So it is not necessary for a population to have the same characteristics as the sample.

But it is essential for the sample to have at least one same characteristics as the population.

So we would not be correct in inferring that such a relationship also exists in the population.

It is a hypothesis which can be true or false due to certain conditions or limitations as the case maybe.

For example in a population of smokers some may be in the habit of taking cocaine. But a sample of cocaine users does not mean the whole population uses it.

It could be purely due to chance if we find out that there is a relationship between parents’ and children’s party identification in the population.

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The table shows the height of water in feet at different times. The water rises and falls in a cyclical pattern.A 2-column table with 5 rows. Column 1 is labeled x with entries 12 a m, 3 a m, 6 a m, 9 a m, 12 p m. Column 2 is labeled y with entries 6, 10, 6, 2, 6.

Which equation models the data in the table?

y = 6 sine (StartFraction pi Over 6 EndFraction x) + 2
y = 6 sine (StartFraction pi Over 6 EndFraction x) + 4
y = 4 sine (StartFraction pi Over 6 EndFraction x) + 6
y = 4 sine (StartFraction pi Over 6 EndFraction x) + 10

Answers

Modeling the data in the table is done via the equation y = 4 sine (pi/6x) + 6.

What is a cyclic pattern?

Over a period of years, a cyclical pattern recurs with considerable regularity. Cyclical patterns are distinct from seasonal patterns in that they last across a number of years as opposed to only one year for seasonal trends.

Given, The table shows the height of water in feet at different times. The water rises and falls in a cyclical pattern.

Table:

12 AM 6

3 AM 10

6 AM 6

9 AM 2

12 PM 6

from the general formula of wave

y = A sin(bx + c)

Substituting values in the equation from the graph attached below:

6 = A sin(0*b + c)......(1)

10 = A sin3b + c...(2)

6 = A sin6b + c......(3)

2 = A sin9b +c........(4)

Since -c/b is a phase shift of the graph

Thus

-c/b = 6

c = -6b

from equations 2 and 1

2* 6 = Asin(-3b) = -Asin3b

2 * 6 = Asin(-6b) = -Asin6b

2* 6/6 =sin6b/sin3b

1 = Cos3b

Thus b = π/6

from substitution in equations 3

6 = A sin6b + c

=> 6 = Asin 6* pi/6 + c

=> c = 6

$\begin{table}[]\begin{tabular}{ll}12 AM & 6 \n3 AM & 10 \n6 AM & 6 \n9 AM & 2 \n12 PM & 6 \end{tabular}\end{table}$ from substitution in equations 2

10 = A sin3b + c

A = 4

therefore, The equation that models data in the table is y = 4 sine (pi/6x) + 6.

Learn more about cyclic patterns here:

brainly.com/question/15223077

#SPJ3

Answer:

Step-by-step explanation:

You are given the probability generating function of X: PX(z)=(0.8z+0.2)10 Calculate the coefficient of variation of X.

Answers

Answer:

Var(X)=1.6

Step-by-step explanation:

Formula for calculating the coefficient of variation for a probability generating function:

Var(X)= PX''(1) + PX'(1) - [PX'(1)]² ........... eq(1)

Now compute each individual term in the above formula.

PX'(z) = $(10) (0.8) (0.8z + 0.2)^9$

PX'(1) = $8 (1)^9$ = 8

[PX'(1)]² = 64

PX''(z) = $(9) (8) (0.8) (0.8z + 0.2)^8$

PX''(1) = $57.6 (1)^8$ = 57.6

Substitute all terms back in eq(1)

Var(X)= 57.6 + 8 - 64

Var(X)= 1.6

What is 4x-5x= x- 20

Answers

Answer: the answer is x=10

Answer: −2x + 20 = 0

Step-by-step explanation:

The metal day fair has a recycling center that will a pay 10% early fee on the amount collected plus $2.75 for each metal collected to be recycled .If Isa brings 12.5 kilograms of metal to be recycled which is the closet amount of money she will receive.

Answers

Answer:

$37.8125

Step-by-step explanation:

$2.75 x 12.5 = 34.375

34.375 x 10% = 3.4375

$34.375 + 3.4375 = 37.8125

The cost of advertising in a local paper for one week is:28 cents per word plus 75 cents
a) What is the cost of an advertisement of 15 words for one week?
b) What is the greatest number of words in an advertisement costing up to $8 for one week?
c) If an advertisement is run for two weeks, the cost for the second week is reduced by 30%. Calculate the total cost for an advertisement of 22 words for two weeks.

Answers

Answer:

a) 495 cents

b) 25 words

c) 1174.7 cents

Step-by-step explanation:

a) The cost is equal to 28 x 15 + 75 which equals 420 + 75 which equals 495 cents.

b) (800 cents - 75) divided by 28

= 725 / 28

= 25.9

Since you cannot have 0.9 of a word it is rounded down to 25.

c) 22 words in the first week will cost 22 x 28 + 75 = 616 + 75 = 691 cents

In the second week it will cost 30% less which means it will only cost 70% of the ordinary price. Therefore the second week will cost:

0.7 x 691 = 483.7 cents

Total = 483.7 + 691

= 1174.7 cents

Hope this helps :)

The principal is Rs.30,000 the interest rate is 12%. Calculate the total value after 2 yearusing compound interest.

Answers

Total value=
112/100 x 112/100 x 30,000
= 37632 Rs

Answer:

37632

Step-by-step explanation:

An=A(1+12%)²

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