Answer:
Question 1
Answer ;
in photosynthesis process, the plant have the ability to absorb the light using their pigment called as chlorophyll. this light energy with the help of many enzymes will help the conversion of CO2 and water in to glucose which is then transported to different parts of the plants for its usage in different cellular processes and growth. The excess of glucose which is not utilized and metabolized immediately is converted to complex sugar molecules and stored in the plant in the form of Starch to fulfill the future needs.
Question 2
Answer ;
starch are stored for many purpose. the pathway used to create and store glucose in the form of starch is a reversible process. if potato plant have not made enough glucose for the day to feed itself, the starch which was stored will be catabolized using different cellular enzymes in to glucose.the starch which is stored is broken down and needed in those conditions and days when there is no sunlight or cloudy weather for days.
Lower mantle
Outer core
Inner core
The movement of the upper mantle and the tectonic plates of the Earth's lithosphere results in the movement of the Earth's crust. The tectonic plates float on the asthenosphere, a semi-fluid part of the upper mantle, and are driven by convection currents.
The movement of Earth's plates is driven by the upper mantle. The Earth's lithosphere, which is the topmost layer consisting of the crust and the rigid upper part of the mantle, is broken up into tectonic plates. These tectonic plates float on the semi-fluid layer of the mantle known as the asthenosphere. Convection currents in the asthenosphere, which is part of the upper mantle, move these plates. Thus, the upper mantle has a significant role in the movement of the Earth's crust.
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Jessim should not move except to slowly spin the globe
Jesim should slowly spin the globe and walk away from Nancy
Jessim should have Nancy walk around him while spinning the ball
Jessim should spin the globe quickly while walking in a circle around Nancy
Answer:
The answer is D jessim should spin the glove quickly while walking in a circle around nancy.
Explanation:
Answer:
Mass of nitrogen dioxide produced = 4.6 g
Explanation:
Given data:
Volume of ammonia = 2.30 L
Mass of nitrogen dioxide produced = ?
Solution:
Chemical equation:
4NH₃ + 7O₂ → 4NO₂ + 6H₂O
Number of moles of ammonia at STP:
PV = nRT
n = PV/RT
n = 1 atm × 2.30 L / 0.0821 atm.L/K.mol × 273 K
n = 2.30 atm .L / 22.414 atm.L/mol
n = 0.1 mol
Now we will compare the moles of ammonia with nitrogen dioxide from balance chemical equation.
NH₃ : NO₂
4 : 4
0.1 : 0.1
Mass of NO₂:
Mass = number of moles × molar mass
Mass = 0.1 mol × 46 g/mol
Mass = 4.6 g
Answer:
-68.4 kJ
Explanation:
The standard enthalpy of vaporization = 23.3 kJ/mol
which means the energy required to vaporize 1 mole of ammonia at its boiling point (-33 °C).
To calculate heat released when 50.0 g of ammonia is condensed at -33 °C.
This is the opposite of enthalpy of vaporization which means that same magnitude of heat is released.
Thus, Q = -23.3 kJ/mol
Where negative sign signifies release of heat
Given: mass of 50.0 g
Molar mass of ammonia = 17.034 g/mol
Moles of ammonia = 50.0 /17.034 moles = 2.9353 moles
Also,
1 mole of ammonia when condenses at -33 °C releases 23.3 kJ
2.9412 moles of ammonia when condenses at -33 °C releases 23.3×2.9353 kJ
Thus, amount of heat released when 50 g of ammonia condensed at -33 °C= -68.4 kJ, where negative sign signifies release of heat.
The heat released when 50.0 g of ammonia condenses at its boiling point is -68.4 kJ. This is calculated by multiplying the moles of ammonia by the enthalpy of vaporization and recognizing that heat is released in condensation.
To solve this problem, we need to understand the concept of enthalpy of vaporization, which is the heat needed to convert 1 mole of a substance from a liquid to a gas at constant pressure and temperature. For ammonia (NH3), which boils at -33 °C, the enthalpy of vaporization is 23.3 kJ/mol. However, we want the heat released when 50.0 g (around 2.94 moles) of ammonia condenses, which is the reverse process of vaporization. Thus, the energy would be released rather than absorbed.
Now, let's calculate this value. We multiply the number of moles of ammonia by the enthalpy of vaporization:
2.94 moles x 23.3 kJ/mol = 68.4 kJ
Since this is the reverse of the process of vaporization, heat is released, so the enthalpy change is negative (-68.4 kJ). Therefore, the correct answer is -68.4 kJ.
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