2. ClO3-
3. ClO2-
4. ClO-
Answer:
4 ClO-
Explanation:
Bond length ∝ 1/ Bond order
Bond order of ClO − =1,
Bond order of ClO 2− =1.5,
Bond order of ClO 3− =1.66 ,
Bond order of ClO 4− =1.75.
Thus the order of bond length is
ClO 4− <ClO3− <ClO2−
<ClO −
b. C
c. Si
d. P
Answer: Option (a) is the correct answer.
Explanation:
A metal is a substance which loses electron(s) in order to attain stability.
For example, sodium is an alkali metals with atomic number 11 and its electronic distribution is 2, 8, 1.
So, in order to attain stability sodium will readily lose 1 electron and forms ion.
Whereas non-metals are the substances which gain electron(s) in order to attain stability.
For example, atomic number of carbon is 6 and its electronic configuration is 2, 4.
To attain stability a carbon atom shares it 4 valence electrons with another atom.
Thus, we can conclude that out of the given options, Na is a metal.
The volume of 0.44 moles of ethylene gas at STP is approximately 10.33 liters.
To calculate the volume of gases at Standard Temperature and Pressure (STP), we can use the ideal gas law:
PV = nRT
Where:
P = Pressure (at STP, it's 1 atmosphere, or 1 atm)
V = Volume (in liters)
n = Number of moles
R = Ideal gas constant (0.0821 L·atm/mol·K)
T = Temperature (at STP, it's 273.15 K)
Let's calculate the volume for each gas:
For 7.6 moles of Ar (argon):
P = 1 atm
n = 7.6 moles
R = 0.0821 L·atm/mol·K
T = 273.15 K
Now, plug these values into the ideal gas law:
V = (nRT) / P
V = (7.6 moles * 0.0821 L·atm/mol·K * 273.15 K) / 1 atm
V ≈ 172.75 liters
So, the volume of 7.6 moles of argon gas at STP is approximately 172.75 liters.
For 0.44 moles of C2H3 (ethylene):
P = 1 atm
n = 0.44 moles
R = 0.0821 L·atm/mol·K
T = 273.15 K
Now, plug these values into the ideal gas law:
V = (nRT) / P
V = (0.44 moles * 0.0821 L·atm/mol·K * 273.15 K) / 1 atm
V ≈ 10.33 liters
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