Geometry HW! PLS HELP!

If UVW =~(congruent symbol) EFC, what is the measure of

Answers

Answer 1

Answer:

The measure of angle FEC from the given triangle FCE is 51°. Therefore, option D is the correct answer.

Given that, ΔUVW≅ΔEFC.

What is the congruence theorem?

Triangle congruence theorem or triangle congruence criteria help in proving if a triangle is congruent or not. The word congruent means exactly equal in shape and size no matter if we turn it, flip it or rotate it.

From the given triangle UVW, the measure of ∠U=51° and ∠W=82°.

We know that, the corresponding parts of congruent triangle are equal.

Here, ∠FCE=∠W=82°

∠FEC=∠U=51°

The measure of angle FEC from the given triangle FCE is 51°. Therefore, option D is the correct answer.

To learn more about the congruent theorem visit:

brainly.com/question/24033497.

#SPJ2

Answer 2

Answer:

Answer:

D. 51

Step-by-step explanation:

If UVW is congruent to EFC then FEC must be congruent to VUW

VUW= 51 so FEC= 51

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While waiting for a video game to download you notice that 30% of 32,000 kilobytes have been dowloaded so far

Answers

30% of 32000 will be 32000 multiplied by 0.3 which would equal 9600 kilobytes

30% and 32 000 kb have been downloaded so far.

Let the total be x.

(30/100)*x = 32000

0.3x = 32000

x = 32000/0.3

x ≈ 106 666.667 kb

So the total is ≈ 106 666.667 kb

Hope this helps.

"At Truman Middle School, 2/3 of the girls surveyed preferred playing capture the flag at gym. If 600 girls responded to the survey, how many preferred playing something else?"

Answers

Answer:

200 girls

Step-by-step explanation:

Divide 600 by three in order to get two hundred. Add another two hundred as 2 thirds of the girls preferred capture the flag so the remaining 200 girls preferred other sports.

600/3= 200

200+200=400

600-400=200

Hope this helps

Find the value of the expression log27√3

Answers

$\log _( 27 ){ \left( \sqrt { 3 } \right) } \n \n =\frac { \log _( 3 ){ \left( \sqrt { 3 } \right) } }{ \log _( 3 ){ \left( 27 \right) } }$

$\n \n =\frac { \log _( 3 ){ \left( { 3 }^{ \frac { 1 }{ 2 } } \right) } }{ 3 } \n \n =\frac { \frac { 1 }{ 2 } \log _( 3 ){ 3 } }{ 3 } \n \n =\frac { \frac { 1 }{ 2 } }{ 3 }$

$\n \n =\frac { 1 }{ 2 } \cdot \frac { 1 }{ 3 } \n \n =\frac { 1 }{ 6 }$

$\log_(27)\sqrt3=(\log_3\sqrt3)/(\log_327)=((1)/(2))/(3)=(1)/(6)$