MATHEMATICS HIGH SCHOOL

The ground temperature at an airport is 13 °C. The temperature decreases by 7 °C for every increase of 1 kilometer above the ground. What is the temperature outside a plane flying at an altitude of 5 kilometers?The temperature outside a plane flying at an altitude of 5 kilometers is ____ c*?

Answers

Answer 1
Answer: I’m guessing it’s -22

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What is the value of this expression when x = -5 and y = -3 (2)/(3) x^(3) y^(2)

Answers

Answer:

y = - 750

Step-by-step explanation:

Given

y = (2)/(3) x³y² ← substitute x = - 5, y = - 3 into the expression

  = (2)/(3) × (- 5)³ × (- 3)²

  = (2)/(3) × - 125 × 9 ( cancel the 3 and 9 )

  = 2 × - 125 × 3

  = - 750

           HELP !!!!!!!!!!!!!!!!

Solve by applying the counting principle.

You have 5 shirts and 3 pairs of pants and 4 ties.


How many outfit are possible?

Answers

Well, it depends.
You can only wear 3 outfits unless you wear your pants twice. Then you will have five outfits because ties don't normally get washed til the second time you wear it.

If y varies directly as x, and y is 6 when x is 72, which is the value of y when x is 8 ?

Answers

(y)/(x) = k

(6)/(72) = k

(1)/(12) = k

********************************

(y)/(x) = k

(y)/(8) = (1)/(12)

   12y = 8

      y = (8)/(12)

      y = (2)/(3)

y = (2)/(3)

given y ∝ x

To convert to an equation multiply by k the constant of variation

y = kx

to find k use the given condition y = 6 when x = 72

y = kx ⇒ k = (y)/(x) = (6)/(72) = (1)/(12)

equation is → y = (1)/(12) x

when x = 8 then

y = (1)/(12) × 8 = (8)/(12) = (2)/(3)

What is the slope of -5/8 and goes through the point (2,-3)

Answers

The answer is -11/7 as a mixed number it is( -1 4/7)

A car rental agency charges $120 per week plus $.12 per mile driven. How many miles did you drive if the total charge is $162?

Answers

\boxed{y=120+0.12x}\n \n y=162\n \n 120+0.12x=162\n \n 0.12x=162-120\n \n 0.12x=42\n \n x=(42)/(0.12)\n \n \boxed{\boxed{x=350 \ miles}}

Why are circles so important to constructions?

Answers

Its a way to find a range of length without using exact measuments (if your using a compass)
Also you need to know constructions for the weekly tests so your school can get more money
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