Answer:
Option C. 140
Step-by-step explanation:
Base of a pyramid which has four triangular sides is four sided.
If pyramid contains seven layers of oranges then the layer at the bottom will have 7 oranges.
Since base is a square then other side of the square base will have the same number of oranges = 7.
Therefore number of oranges at the first layer will be = 7×7
Similarly other layers above this layer will have the same sequence
6×6, 5×5, 4×4, 3×3, 2×2, 1×1
Therefore total number of oranges = 7×7 + 6×6 + 5×5 + 4×4 + 3×3 + 2×2 + 1×1 = 49 + 36 + 25 + 16 + 9 + 4 + 1 = 140
Option C. 140 is the answer.
A grocer stacks oranges in a four-sided pyramid that is 7 layers high. Many oranges are in the pile are C.140
The orange is the fruit of the citrus species Citrus and sinensis in the family Rutaceae, native to China. Orange is also called sweet orange, to distinguish it from the related Citrus and aurantium, referred to as bitter orange.
The proper name of four-sided pyramid is a "tetrahedron". The tetrahedron has the extra interesting property of having all four triangular sides congruent
1st Layer: The 1st layer contains only 1 orange so it has only 1 orange
2nd layer: The 2nd layer has total 4 oranges. Calculation:
3rd layer: The 3rd layer has total 9 oranges. Calculation:
4th Layer: The 4th layer has total 16 oranges. Calculation: .
5th layer: The 5th layer has total 25 oranges. Calculation:
6th layer: The 6th layer has total 36 oranges. Calculation:
7th layer: The 7th layer has total 49 oranges. Calculation: .
Sum of all layers:
Grade: 9
Subject: mathematics
Chapter: pyramid
Keywords: oranges, pyramid, four-sided, layers, pile
Factored form
Answer:
2(2x + 1)(3x - 5)
Step-by-step explanation:
Answer:
Step-by-step explanation:
Class limits are the minimum data value(lower) and maximum data value (upper) that a class can contain. They usually have the same numerical accuracy as the original data values.
Class boundaries are boundary lines that mark or separate where one class stops and the other begins. The lower class boundary of a given class is got by finding the average of the previous upper class limit and the given lower class limit while the upper class boundary is got by finding the average of the given upper class limit and the next lower class limit.
Class limits and class boundaries are statistical terms used in frequency distributions. Class limits are the smallest and largest values of a class, while class boundaries are the points separating one class from another.
The terms class limits and class boundaries are used in the field of statistics, particularly in the context of frequency distributions. Class limits are the smallest and largest values that can fall within each class in a frequency distribution, whereas class boundaries are the points that separate one class from another, and each boundary forms the end of one class and the start of the next.
For example, imagine you are analyzing the frequency of test scores and you have a class with limits of 80 and 89. These limits are the smallest and largest scores that fit into that class. However, the class boundaries are 79.5 and 89.5, serving as the dividing lines between this class and the next ones.
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Answer:
Factored form is 4x(2x+3)
Step-by-step explanation:
The factors are
8x^2 ----> 2*2*2*x*x
12x -------> 2*2*3*x
GCF is 2 * 2 * x= 4x
Now we factor out GCF from 8x^2 + 12x
When we factor out GCF, divide each term by 4x
4x(2x +3)
Factored form is 4x(2x+3)
When 10 and 11 (or -10 and -11) are multiplied, they equal 110.
You can find the answer by solving the following equation:
x(x+1)=110
x^2+x-110=0
(x-10)(x+11)=0
Therefore 10*11 and -10*-11 can be the possible answers to your question.