Answer:
210
I am divisible by 5.
So your ones digit is 0 or 5
I am an even number.
So your ones digit is 0. We fill that in.
_ _ 0
My tens digit is 1.
So we fill that in.
_ 1 0
My tens digit is greater than my ones digit.
Well, of course 1 is greater than 0. We didn't need to be told that.
I have only one odd digit.
Since the 1 is odd, the hundreds digit is even, 2,4, or 8
I am less than 400.
So your hundreds digit is 2. Fill that in and we're done.
2 1 0
My hundreds digit is greater than my tens digit.
Of course 2 is greater than 1, we didn't need to be told that.
I am divisible by 3.
Of course 210 is divisible by 3. We didn't need to be told that.
Too much information!
Answer: 210
Answer: 20/3
Step-by-step explanation:
3 times b
Answer:
3b
Step-by-step explanation:
It`s just . . . 3b lol
When numbers and variables multiply, they are put in the form of (integer)(variable). They phrase can only be further simplified if there is a number substitution for b.
Each parking lot can hold 185 cars.
Math operations include division as one of its types. This technique involves splitting the phrases or numbers into the same amount of components.
Let's denote the number of cars each parking lot can hold as x.
Since there are six identicalparking lots, the total number of cars they can hold is 6x.
According to the problem, the total number of cars that can be parked in these six lots is 1110.
So we can write:
6x = 1110
This equation relates the number of cars each parkinglot can hold (x) to the total number of cars that can be parked in all six lots (1110).
To solve for x, we can divide both sides of the equation by 6:
x = 185
Therefore, the required number is 185 cars.
To learn more about the division;
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