Answer:
C a position from which something is observed
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Explanation:
Answer: A system or frame of reference are those conventions used by an observer (usually standing at a point on the ground) to be able to measure the position and other physical magnitudes.
Answer:
Emf induced in the loop is 0.02V
Explanation:
To get the emf of induced loop, we have to use faraday's law
ε = - dΦ/dt
To get the flux, we use;
Φ = BA cos(θ)
B = The uniform magnetic field
A = Area of rectangular loop
θ = angle between magnetic field and normal to the plane of loop
substitute the flux equation (Φ) into the faraday's equation
we have ε = - d(BA cos(θ)) / dt
ε = BA sinθ dθ/dt
from the question;B = 0.18T, A=0.15m2, θ = π/2 ,dθ/dt = 0.75rad/s
Our equation will now look like this;
ε = (0.18T) (0.15m2) (sin(π/2)) (0.75rad/s)
ε = 0.02V
Answer:
0.9 cm
Explanation:
The computation in the increase in the length of the joined rod is shown below:
As we know that
Increase in length = increase in the length of aluminum rod + increase in The length of steel rod
= 0.9 cm
We simply added the length of aluminium rod and length of steel rod so that the length of the joined rod could come and the same is to be considered
The increase in length of the joined rod when the temperature is raised from 15°C to 90°C is 0.090 cm.
To determine the increase in length of the joined rod when the temperature is raised from 15°C to 90°C, we need to use the formula for linear expansion: AL = aLAT, where AL is the change in length, AT is the change in temperature, and a is the coefficient of linear expansion. First, we need to calculate the change in temperature for each rod: ΔT = 90°C - 15°C = 75°C. For the aluminum rod, using a linear expansion coefficient of 2.4 × 10-5 K-1 and a length of 10.0 cm, we can calculate the change in length using the formula: ALaluminum = (2.4 × 10-5 K-1)(10.0 cm)(75°C) = 0.018 cm. Similarly, for the steel rod, using a linear expansion coefficient of 1.2 × 10-5 K-1 and a length of 80.0 cm, we can calculate the change in length: ALsteel = (1.2 × 10-5 K-1)(80.0 cm)(75°C) = 0.072 cm. Since the rods are joined end-to-end, the total change in length of the joined rod is the sum of the individual changes: ΔL = ALaluminum + ALsteel = 0.018 cm + 0.072 cm = 0.090 cm. Therefore, the increase in the length of the joined rod is 0.090 cm.
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Answer:
The linear velocity is represented by the following expression:
Explanation:
From Rotation Physics we know that linear velocity of a point moving with uniform circular motion is:
(Eq. 1)
Where:
- Radius of rotation of the particle, measured in meters.
- Angular velocity, measured in radians per second.
- Linear velocity of the point, measured in meters per second.
But we know that angular velocity is also equal to:
(Eq. 2)
Where:
- Angular displacement, measured in radians.
- Time, measured in seconds.
By applying (Eq. 2) in (Eq. 1) we get that:
(Eq. 3)
From Geometry we must remember that circular arc (), measured in meters, is represented by:
The linear velocity is represented by the following expression:
Answer:
Explanation:
We can use Ohm's Law to find the resistance R of a wire that carries a current I under a given potential difference:
Answer:
Ohm's law states that I=V/R (Current=volts divided by resistance). Since we're looking for resistance, we'll rewrite it as R=V/I. Then just plug in the numbers; R=84/9, R= 9 1/3 or 28/3. The resistance of the wire is 9.33... or 9 1/3 ohm's, depending on how you wanna write it.
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B) All protons align opposite to the field.
C) Some protons align with the field and some align opposite to it.
D) All protons assume a random orientation.
On account of external magnetic field, the protons will align with the magnetic field. Hence, option (a) is correct.
The given problem is based on the concept of magnetic field. The region where the magnetic force is experienced is known as magnetic field. Generally, the protons are the charged entities carrying the positive polarity and are one of the major constituents of modern atomic structure.
Thus, we can conclude that on account of external magnetic field, the protons will align with the field.
Learn more about the magnetic field here:
Answer:
Some protons align with the field and some align opposite to it.
Explanation:
Majority align to the field because these protons tend to act like small magnets under the effect of this external field
Answer:
The answers to the questions are;
(a) The velocity of the truck right after the collision is 20.884 m/s
(b) The change in mechanical energy of the car truck system in the collision is -9076.4384 J
(c) The change in mechanical energy is due to energy consumed by the collision process.
Explanation:
(a) From the principle of conservation of linear momentum, we have
m₁·v₁+m₂·v₂ = m₁·v₃ + m₂·v₄
Where:
m₁ = Mass of the car = 1225.0 kg
m₂ = Mass of the truck = 9700.0 kg
v₁ = Initial velocity of the car = 25.000 m/s
v₂ = Initial velocity of the truck = 20.000 m/s
v₃ = Final velocity of the car right after collision = 18.000 m/s
v₄ = Final velocity of the truck right after collision
Therefore
1225.0 kg × 25.000 m/s + 9700.0 kg × 20.000 m/s = 1225.0 kg × 18.000 m/s + 9700.0 kg × v₄
That is 30625 kg·m/s + 194000 kg·m/s = 22050 kg·m/s + 9700.0 kg × v₄
Making v₄ the subject of the formula yields
v₄ = (202575 kg·m/s)÷9700.0 kg = 20.884 m/s
The velocity of the truck right after the collision to five significant figures = 20.884 m/s
(b) The change in mechanical energy of the car truck system in the collision can be found by
The change in kinetic energy of the car truck system
Change in kinetic energy, ΔK.E. = Sum of final kinetic energy - Sum of initial kinetic energy
That is ΔK.E. = ∑ Final K.E -∑ Initial K.E.
ΔK.E. =
= (·1225·18²+ ·9700·20.884²) - (·1225·25²+·9700·20²)
= 2313736.0616 kg·m²/s² - 2322812.5 kg·m²/s² = -9076.4384 kg·m²/s²
1 kg·m²/s² = 1 J ∴ -9076.4384 kg·m²/s² = -9076.4384 J
(c) The energy given off by way of the 9076.4384 J is energy transformed into other forms including
1) Frictional resistance between the tires and the road for the truck and car
2) Frictional resistance in the transmission system of the truck to increase its velocity
3) Sound energy, loud sound heard during the collision
4) Energy absorbed when the car and the truck outer frames are crushed
5) Heat energy in the form of raised temperatures at the collision points of the car and the truck.
6) Energy required to change the velocity of the car over a short distance.