Answer:
two atoms of oxygen. For H2O, there is one atom of oxygen and two atoms of hydrogen.
Answer:
1.7 × 10⁴ J
Explanation:
Step 1: Calculate the heat required to raise the temperature of ice from -15 °C to 0°C
We will use the following expression.
Q₁ = c(ice) × m × ΔT
Q₁ = 2.03 J/g.°C × 25 g × [0°C - (-15°C)] = 7.6 × 10² J
Step 2: Calculate the heat required to melt 25 g of ice
We will use the following expression.
Q₂ = C(fusion) × m
Q₂ = 80. cal/g × 25 g × 4.184 J/1 cal = 8.4 × 10³ J
Step 3: Calculate the heat required to raise the temperature of water from 0°C to 75 °C
We will use the following expression.
Q₃ = c(water) × m × ΔT
Q₃ = 4.184 J/g.°C × 25 g × (75°C - 0°C) = 7.8 × 10³ J
Step 4: Calculate the total heat required
Q = Q₁ + Q₂ + Q₃
Q = 7.6 × 10² J + 8.4 × 10³ J + 7.8 × 10³ J = 1.7 × 10⁴ J
B. ribose sugar, cytosine, guanine, adenine, uracil, and phosphate group
C. deoxyribose sugar, cytosine, guanine, adenine, thymine, and phosphate group
D. deoxyribose sugar, cytosine, guanine, adenine, uracil, and phosphate group
Answer:
C
Explanation:
A-T G-C
Answer:
The human cheek cell is a good example of a typical animal cell. It has a prominent nucleus and a flexible cell membrane which gives the cell its irregular, soft-looking shape.
Answer:
The reaction will shift to the left in the direction of reactants.
Explanation:
According to Le Chatelier's principle, when an external constraint is applied to a chemical system in equilibrium, the system adjust in order to annul the effect impose on it by the external system.
Also, from the principle, the addition of an inert gas can affect the equilbrium of a gaseous system, but only if the volume is allowed to change.
There are two cases on which equilibrium depends. These are:
1. Addition of an inert gas at constant volume:
When an inert gas is added to the system in equilibrium at constant volume, the total pressure will increase. But the concentrations of the products and reactants (i.e. ratio of their moles to the volume of the container) will not change. Hence, there will be no effect on the equilibrium.
2. Addition of an inert gas at constant pressure:
When an inert gas is added to a system in equilibrium at constant pressure, then the total volume will increase(i.e. the number of moles per unit volume of various reactants and products will decrease). Hence, the equilibrium will shift towards the direction in which there is increase in number of moles of gases.
Considering the given reaction in equilibrium:
2H₂S(g) + 3O₂(g) ⇌ 2H₂O(g) + 2SO₂(g)
The addition of an inert gas at constant pressure to the above reaction will shift the equilibrium towards the backward direction because the number of moles of reactants is more than the number of moles of the products.
Adding 1.4 moles of He to the reaction mixture will have no effect on the equilibrium of the system.
Adding 1.4 moles of He to the reaction mixture will have no effect on the system. The equilibrium of the reaction will not shift to the left or right, and there will be no change in the equilibrium constant. This is because He is considered an inert gas and does not participate in the reaction.
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Number of moles is defined as the ratio of given mass in grams to the molar mass of compound.
Number of moles =
Now, put the value of given mass of in grams and molar mass of in g/mol i.e. 13 g/mol.
Thus,
number of moles =
= 0.692 mol
Hence, number of moles of = 0.692 mol
Solution:
After the reaction of mixture is worked-up Washing three times the organic with sodium carbonate helps to decrease the solubility of the organic layer into the aqueous layer. This allows the organic layer to be separated more easily.
And then the reaction washed by saturated NACL we have The bulk of the water can often be removed by shaking or "washing" the organic layer with saturated aqueous sodium chloride (otherwise known as brine). The salt water works to pull the water from the organic layer to the water layer.