A rectangle’s area and perimeter have the same numerical value. The length of the rectangle is 12 units. What is the width of the rectangle?
Answers
We can conclude that the length of the rectangle is 12 Units. The value of the width of a rectangle is 2.4 units.
What is the area of the rectangle?
The area of the rectangle is the product of the length and width of a given rectangle.
The area of the rectangle = length × Width
We have been given that a rectangle’s area and perimeter have the same numerical value also the length of the rectangle is 12 units.
The area of the rectangle = 12x2.4 = 28.8
Area = Perimeter
Length x Width = 2 (Length + Width)
Then Substituting the value of the width, we get the length,
12 x W = 2(12 + W)
12W = 24 + 2W
10W = 24
W = 2.4
Hence we can conclude that the length of the rectangle is 12 Units. The value of the width of a rectangle is 2.4 units.
To know more about the area and perimeter of a rectangle, follow the link given below.
brainly.com/question/26526597.
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Answer:
2.4
Step-by-step explanation:
12x2.4 = 28.8 (Area)
12+12+2.4+2.4 = 28.8 (Perimeter)
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Answer:
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Answers
(the same number)^(A - B) power
If 'A' = 'B', then the numerator and the denominator are both
(the same number)^to the same power,
and since (A - B = 0) , the quotient is (the same number)^to the ( 0 ) power.
But a fraction with the same thing in the numerator and the denominator is '1 '.
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Its undefined DUH like why would it be 1 or 0
The sum of its angle measures is 360°.
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It has four congruent sides.
Answers
A) first 80° and then 80°
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Answers
3y 2 z(2y 2 z + 4yz - y + z)
Answers
Answer: 48(y*z)^2 - 6z*y^2 - 6y*z^2
Step-by-step explanation: We want to find the product:
3y*2z*(2y*2z + 4yz - y - z)
First, distribute the product:
3y*2z*2y*2z + 3y*2z*4yz -*3y*2z*y - 3y*2z*z
now, let's simplify the equation:
(3*2*2*2)(y*z)^2 + (3*2*4)(y*z)^2 - (3*2)z*y^2 - (3*2)y*z^2
24(y*z)^2 + 24(y*z)^2 - 6z*y^2 - 6y*z^2
48(y*z)^2 - 6z*y^2 - 6y*z^2
If the equation you want to distribute is:
(3y^2z)*(2y^2z + 4yz - y - z)
the distribution is:
(3y^2z)´*(2y^2z) + (3y^2z)*4yz -(3y^2z)*y - (3y^2z)*z
6y^4z + 12y^(2z + 1)*z - 3y^(3z + 1) - (3y^2z)*z
=6y^(4z)+12y^(1+2z)z-3y^(1+2z)+3zy^(2z)