Solve each equation by finding all roots x^4-16=0

Answers

Answer 1
Answer: { x }^( 4 )-16=0\n \n { x }^( 4 )=16\n \n x=\pm \sqrt [ 4 ]{ 16 } \n \n \therefore \quad x=\pm 2
Answer 2
Answer: add both sides by 16
so you'll have x^4 =16
take the 4th root of both sides and you'll get x=  2

Related Questions

6x - 5y= 0 and x - 5y= -25
Write the explicit formula for the geometric sequence. Then find the fifth term in the sequence. a1 = –4, a2 = 8, a3 = –16
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-2 + (-1/3) equals what?
Show that (4-√3)(4+√3)/√13 simplifies to root 13

Simplify 4/7 / 3 over negative 8

Answers

Answer:

(4/7)÷ (3/-8). Division of fractions is the same as multiplying their reciprocals. So (4/7) x (-8/3). Now multiply the numerators together and denominators together (make sure you only use the negative sign once). (4 x -8) / (7 x 3) = -32/21.

Mike bought a lunch that cost $9.00. He also paid 5% for sales tax.How much change did he receive from $20.00?

Answers

Answer:

$10.55

Step-by-step explanation:

First, add 5% of 9 to nine.

5% of 9 :.45

.45+9=9.45

So, then, subtract 9.45 from 20, which leads to 10.55 as your answer

Round to the place value of the less precise measurement.
2.13 m + 8.6 m

Answers

The answer would be 10.19m. If you want to round it of to a less precise measurement it would be 10 m. That is rounding of the decimal value to the ones place. the rule of rounding of is form 6 t0 9 it would add 1 to the nearest place value next to it and 0 - 5 will not.

Solve the following system of equations using substitution.u = 6 + t
36 = 2t + u
A. t = 10, u = 16
B. t = 10, u = 4
C. t = 14, u = 20
D. t = 16, u = 22

Answers

It's A. If U=16, 6+10=16
and if you plug in the numbers for the second equation it's 36=2(10)+16

The following are the last 10 run scores Colin got in cricket: 5, 3, 9, 11, 4, 28, 0, 30, 0, 23 a) Work out Colin's mean score.

Answers

Answer:in  pula mea dute si invata nu mai venii aici\

Step-by-step explanation:vezii ca daca nu invetii ii zic lu mata aia creata ca folosesti brainly bai nesimtitule mars la munca nu la frecat ou bai labare.

√(x)

A contractor has 48 meters of fencing to use as the perimeter of a rectangular garden. The length of one side of the garden is represented by x, and the area of the garden is 108 square meters. Determine, algebraically, the dimensions of the garden in meters

Answers

if we let y be the dimension of the other side, then the perimeter has the formula
P = 2x + 2y
48 = 2x + 2y

The area of the rectangle has the formula
A = xy
108 = xy

So,
x = 108/y

Substituting this to the first equation
48 = 2(108/y) + 2y
48y = 216 + 2y^2
2y^2 - 48y + 216 = 0

Solving the quadratic equation:
y = 18 or 6

Either of the two is the correct answer for y, the value of x would just be the other. So, the dimensions of the garden is
18 m x 6 m