At what distance from a long, straight wire carrying a current of 8.7 A is the magnetic field due to the wire equal to the strength of Earth’s field, approximately 5.4 × 10−5 T? The permeabilty of free space is 1.25664 × 10−6 T · m/A. Answer in units of cm.
Answers
Answer:
r= 3.2 cm
Explanation:
Given that
I= 8.7 A
B= 5.4 x 10⁻⁵ T
μo=1.25664 x 10⁻⁶
We know that magnetic filed in wire at a distance r given as
By putting the values
r=0.032 m
r= 3.2 cm
Final answer:
The distance from a long straight wire at which the magnetic field equals the strength of Earth’s field, given a current of 8.7 A and Earth's field of 5.4 × 10−5 T, can be calculated using the formula for the magnetic field around a current-carrying wire. Substituting the given values, the answer is approximately 37.22 cm.
Explanation:
To solve this physics problem, we will use the formula for the magnetic field produced by a current carrying long, straight wire. The formula is: B = μI / (2πr), where 'B' is the magnetic field strength, 'μ' is the permeability of free space, 'I' is the current, and 'r' is the radial distance away from the wire.
In this case, Earth’s magnetic field, 'B', is given as 5.4 × 10−5 T, the current, 'I', is given as 8.7 A, and the permeability of free space, 'μ', is given as 1.25664 × 10−6 T · m/A. We need to find 'r', the distance away from the wire, and we want this answer in centimeters.
So, rearrange the formula to solve for 'r': r = μI / (2πB).
Substitute our known values into the equation: r = (1.25664 × 10−6 T · m/A × 8.7 A) / (2π × 5.4 × 10^-5 T). After calculating, we need to convert from meters to centimeters by multiplying by 100. The final answer is approximately 37.22 cm.
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An ultrasound unit is being used to measure a patient's heartbeat by combining the emitted 2.0 MHz signal with the sound waves reflected from the moving tissue of one point on the heart. The beat frequency between the two signals has a maximum value of 560 Hz . What is the maximum speed of the heart tissue? The speed of ultrasound waves in human tissue is 1540 m/s.Express your answer to two significant figures and include the appropriate units.
Answers
Answer:
To decrease the current;
1) Use fewer loops or number of turns
2) Use a lower speed of rotation of the coil in the magnetic field
3) Use a weaker magnetic
Explanation:
According to Faraday's Law of induction, which is the basis of the electromagnetism, electromagnetic induction and therefore the basis of the electric generator, can be written as follows;
Where;
ε = The induced voltage
N = The number of turns (loops)
ΔФ = The change in the magnetic flux
Δt = The change in the time (the duration)
Given that voltage is directly related to the current, decreasing the voltage, decreases the current
To decrease the voltage, and therefore, the current we can;
1) Reduce the number of loops in the coil
2) Increase the time change per unit change in flux by slowing down the speed of rotation of the generator
3) Decrease the amount of change in the magnetic field per turn, by using a weaker magnetic
B. A feather will fall slower than a bowling ball.
C. A feather and a bowling ball will fall at the same rate.
D. Both a feather and a bowling ball can't fall, but will always remain motionless.
Answers
Answers
The correct answer to the question is : 9375 N.
CALCULATION:
As per the question, the mass of the car m = 1500 Kg.
The diametre of the circular track D = 200 m.
Hence, the radius of the circular path R =
=
= 100 m.
The velocity of the truck v = 25 m/s.
When a body moves in a circular path, the body needs a centripetal force which helps the body stick to the orbit. It acts along the radius and towards the centre.
Hence, the force acting on the car is centripetal force.
The magnitude of the centripetal force is calculated as -
Force F =
=
= 9375 N. [ANS}
The centripetal force is provided to the car in two ways. It is the friction which provides the necessary centripetal force. Sometimes friction is not sufficient. At that time, the road is banked to some extent which provides the necessary centripetal force.
Final answer:
The magnitude of the net force on the car is 9375 N, directed towards the center of the track. The net force is caused by the combination of the car's weight and the normal force of the road. These forces provide the necessary centripetal force to keep the car in its circular path.
Explanation:
The magnitude of the net force on the car can be calculated using the formula F = m×a, where m is the mass of the car and a is its acceleration. Since the car is moving in a circular path, its acceleration can be determined using the formula a = v^2/r, where v is the velocity of the car and r is the radius of the circular track. The direction of the net force is towards the center of the circular track, as it provides the necessary centripetal force to keep the car moving in a circular path.
Using the given values, the magnitude of the net force on the car is F = (1500 kg) × (25 m/s)^2 / (100 m) = 9375 N. The direction of the net force is towards the center of the circular track since it provides the centripetal force required to keep the car in its circular path.
The net force on the car is caused by two external forces: the weight of the car and the normal force of the road. The weight of the car acts vertically downwards, while the normal force of the road acts perpendicular to the surface. These two forces combine to provide the net force that keeps the car moving in a circular path.
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Answers
Answer:
4.17 A
Explanation:
Charge is given as the product of current and time hence expressed as
Q=It
Where Q is charge in Cuolombs, I is current in Amperes and t is time in seconds
Making current, I the subject of the formula then
I=Q/t
Conversion
1 minute has 60 seconds
2 minutes will have 2*60=120 seconds
Substituting 120 s for t and 500 C for Q then
I=500÷120=4.1666666666666666666666666666666666666666
Rounded off, current is approximately 4.17A
G, the constant of universal gravitation
g, the constant of acceleration due to gravity
F, the magnitude of the net force acting on the object
Answers
B. changes the direction of the satellite.
C. is a center-directed force.
D. all of the above
Answers
The centripetal force (of gravity) on a satellite in orbit is an
unbalanced force (because there's no equal force pulling
the satellite away from Earth), changes the direction of the
satellite (into a closed orbit instead of a straight line), and
always acts toward the center of whatever curve the satellite
happens to be on at the moment.
Answer : (D) " all of the above "
Explanation :
The forces acting on a satellite are Earth's gravitational force and centripetal force. The properties of centripetal force acting on a satellite in orbit are as follows :
(1) It acts as an unbalanced force on the satellite. This is due to the reason that there is no same force present which pulls the satellite away from the earth.
(2) It changes the direction of the satellite. The satellite is revolving with a constant speed while the direction is kept on changing (in a circular motion).
(3) Centripetal force always acts towards the center.
So, the correct option is (D) " all of the above "