Hello!
A race car starting from rest accelerates uniformly at a rate of 3.90 m/s² what is the cars speed after it has traveled 200 m.
We have the following data:
Vf (final velocity) = ? (in m/s)
Vi (initial velocity) = 0 m/s (accelerated from rest)
d (displacement) = 200 m
a (acceleration) = 4.90 m/s²
Since we do not need to know the time elapsed during the movement, we apply the data of the question to the Equation of Torricelli, let us see:
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-Electrons are added to two negatively charged objects.
-Two oppositely charged objects are moved farther apart.
-The charge on two positively charged objects is reduced.
The change that will increase the electric force between objects is "electrons are added to two negatively charged objects".
The electric force between objects is determined by applying Coulomb's law as shown below;
F = kq₁q₂/r²
where;
Increase in the magnitude of the charges will increase the electric force between the objects.
Thus, the change that will increase the electric force between objects is "electrons are added to two negatively charged objects".
Learn more about electric force here: brainly.com/question/20880591
Using Newton's second law of motion, if the net force on a sled is tripled and the mass halved, the new acceleration would be 12 m/s².
The subject of this question is derived from the principle of Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This can be represented as: F=ma (Force = mass * acceleration).
Given that the original acceleration 'a' is 2 m/s², the force 'F' acting on the sled can be calculated as F=ma. But since the net force is being tripled and the mass halved, the new force would be 3F, and the new mass would be m/2.
Now we need to determine the new acceleration, which can be calculated as a = F/m. Plugging in our new values, we get a = (3F)/(m/2). This equates to a = 6F/m. Since the original force is calculated as F=ma, we can substitute this in the above equation. Hence the new acceleration is 6*2 m/s² = 12 m/s².
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B) The current in the four bulbs is much less than the current in three bulbs.
C) The current in each bulb remained the same even though another bulb was added.
D) The current in the fourth bulb is less than the current int he other three bulbs.
Since all the bulbs are connected in parallel with each other
so here voltage across each bulb will remains the same
so here we will have
now all bulbs are identical and we have same voltage source across all the bulbs
so we will have current in each bulb given by same equation
now we can say that correct answer will be
C) The current in each bulb remained the same even though another bulb was added.
The answer is C) The current in each bulb remained the same even though another bulb was added.