How can you determine the speed of an object with only a tape measure and a stopwatch?

Answers

Answer 1

Answer:

We can determine the speed of an object with only a tape measure and a stopwatch first by measuring the distance traveled by any given body and simultaneously measuring the time taken to cover this distance with the help of the stopwatch

What is speed?

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is meter/second. The generally considered unit for speed is a meter per second.

The mathematical expression for speed is given by

speed = total distance /Total time

Suppose a body travels a total distance of 750 meters in a total time of 75 seconds, we can measure this distance with the help of a tape measure and the time with the help of a stopwatch its speed would be 4 meters/seconds

speed = distance measured by tape measure /stopwatch time

= 750/75

= 10 m/s

Thus, we can determine the speed of an object with only a tape measure and a stopwatch

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Answer 2

Answer: see how far the object travels in the amount of time

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At which point on this electric field will a test charge show the maximum strength?A
B
C
D

Answers

Answer:

Explanation:

The figure shows the electric field produced by a spherical charge distribution - this is a radial field, whose strength decreases as the inverse of the square of the distance from the centre of the charge:

$E\propto (1)/(r^2)$

More precisely, the strength of the field at a distance r from the centre of the sphere is

$E=k(Q)/(r^2)$

where k is the Coulomb's constant and Q is the charge on the sphere.

From the equation, we see that the field strength decreases as we move away from the sphere: therefore, the strength is maximum for the point closest to the sphere, which is point A.

This can also be seen from the density of field lines: in fact, the closer the field lines, the stronger the field. Point A is the point where the lines have highest density, therefore it is also the point where the field is strongest.

A 50 Kg football player is standing still when he experiences an inelastic collision with a 150 Kg football player who is traveling at 10 m/s. What is the velocity of the player immediately after the collision?

Answers

Answer:

V = 7.5 m/s

Explanation:

Given that,

Mass of player 1, m₁ = 50 kg

Mass of player 2, m₂ = 150 kg

50 kg player stands still and 150 kg player is traveling at 10 m/s

We need to find the velocity of the player immediately after the collision. As the inelastic collision occurs. The linear momentum will remain conserved. After the collision, let they move with a constant velocity say V.So,

$m_1u_1+m_2u_2=(m_1+m_2)V\n\nV=(m_1u_1+m_2u_2)/((m_1+m_2))\n\n=(150* 10)/((50+150))\n\n=7.5\ m/s$

So, the velocity of the player immediately after the collision is 7.5 m/s.

Phileas Fogg, the character who went around the world in 80 days, was very fussy about his bathwater temperature. It had to be exactly 38.0o C. You are his butler, and one morning while checking his bath temperature, you notice that it’s 42.0oC. You plan to cool the 100.0 kg of water to the desired temperature by adding an aluminum-duckie originally at freezer temperature (-24.0oC). Of what mass should the Al-duckie be? [Specific heat of Al = 0.900 J/(goC); density of water =1 .00 g/ml]. Assume that no heat is lost to the air

Answers

Answer:

The mass of the Al-duckie should be 30 kg.

Explanation:

We will use the first law of thermodynamics:

ΔU = m·Cv·ΔT

Since the specific heat of water is 4.185 J(gºC), the change in the water's internal energy would be:

ΔU = 100 kg · 4.185 J(gºC) · (42ºC - 38ºC) = 1674 KJ

Given that no heat is lost, all the internal energy that the water loses while cooling down will transfer to the duckie. So, if the duckie has ΔU = 1674 KJ and its final temperature is the desired 38 ºC, we can calculate its mass using the first law again:

$m=\frac{\Delta{U}}{Cv{\Delta{T}}}=(1674)/(0.9*[38-(-24)])=30Kg$

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Answers

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Answer in units of m/s?.

Answers

When you drop a 0.4 kg apple, Earth exerts a force on it that accelerates it at 9.8 m/s° toward the earth's surface. According to Newton's third law, the apple must exert an equal but opposite force on Earth.
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Answer in units of m/s?.

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Answers

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