Two objects are connected by a light string that passes over a frictionless pulley as shown in the figure below. Assume the incline is frictionless and take m1 = 2.00 kg, m2 = 7.35 kg, and θ = 50.0°.1) Find the magnitude of the accelerations of the objects. (m/s^2)
2)Find the tension in the string. (N)
3)Find the speed of each object 2.50 s after being released from rest. (m/s)
Two objects are connected by a light string that passes - 1

Answers

Answer 1
Answer:

Answer:

Part a)

a = 3.81 m/s^2

Part b)

T = 27.2 N

Part c)

v_f = 9.53 m/s

Explanation:

For m2 mass along the inclined plane we can write

m_2g sin\theta - T = m_2 a

for m1 mass we can write equation in vertical direction

T - m_1 g = m_1 a

so we will have

m_2g sin\theta - m_1g = (m_1 + m_2) a

so we have

a = ((m_2 sin\theta - m_1)g)/(m_1 + m_2)

now plug in all data in it

a = ((7.35 sin50 - 2)9.81)/(7.35 + 2)

a = 3.81 m/s^2

Part b)

from above equation

T = m_1g + m_1 a

T = 2(9.81 + 3.81)

T = 27.2 N

Part c)

Speed of the object after t = 2.50 s

v_f = v_i + at

v_f = 0 + 3.81(2.50)

v_f = 9.53 m/s

Answer 2
Answer: assume m1 moving down, so m2 is moving up and accelleration direction of each box is the same as its movement.

check forces act on m1
1. tension of the rope T up
2. m1g down
3. moving down with a
f = ma --> m1g - T = m1a ...(1)
or. T = m1g - m1a ... (1.1)

check forces act on m2
1. tension of the rope T up alone the incline. it must be equal to previous one because it is the same segment of the rope.
2. m2gsine(θ) down along the incline
3. moving up with a
f = ma --> T - m2gsine(θ) = m2a ...(2)

replace T from (1.1) to (2)
(m1g - m1a) - m2gsin(θ) = m2a
m1g - m2gsin(θ) = m2a + m1a
a = g(m1 - m2sin(θ))/(m1 + m2)

plug in value you will get the answer. if a is negative, it means direction on our assumption is not correct. it's the opposite (direction).

after get a, you will get T
and velocity use v = u + at

... i cannot post pict. draw the diagram will make you understand this better.

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Please show calculations!

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The potential energy of each kg of water, before it falls, is

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HOPE THIS HELPS!!!!!!!

Albert Einstein was a German-born theoretical physicist. He developed the general theory of relativity, one of the two pillars of modern physics. Einstein's work is also known for its influence on the philosophy of science.

Two bowling balls each have a mass of 6.9-kg.They are located next to each other with their centers 21.8-cm apart.What gravitational force do they exert on each other

Answers

We can start with Newton's Law of Universal Gravitation, which is
F_(grav) = (G. m_(1) .m_(2))/d^(2)
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We can thus plug in the given values to receive the answer...
F_(grav)=(6.673x10^(-11).(6.9)^(2))/(0.218)^2
I converted the 21.8cm into 0.218m, for the equation calls for meters.

I hope this helps!
P.S. I'm currently enrolled in IB Physics, so if you have any more questions, feel free to contact me for help.

Final answer:

The gravitational force between two 6.9 kg bowling balls, which are 21.8 cm apart, is approximately 1.99 x 10^-9 Newtons, showing the relative weakness of gravitational forces at an everyday scale.

Explanation:

The gravitational force between two objects can be calculated using Newton's law of universal gravitation. The formula for this force is F = G * (M1 * M2) / R^2, where F is the force, G is the universal gravitational constant (6.67 × 10^-11 Nm^2/kg^2), M1 and M2 are the masses of the two objects, and R is the distance between the objects.

In this scenario, each of the bowling balls has a mass of 6.9 kg and their centers are 21.8 cm (or 0.218 m) apart. Substituting these values into the formula, we get the gravitational force to be approximately 1.99 x 10^-9 Newtons. This value is quite small, which is consistent with our intuition that everyday objects like bowling balls don't seem to attract each other noticeably — this is because the gravitational force is extremely weak in comparison to other forces such as electromagnetic forces.

Learn more about Gravitational Force here:

brainly.com/question/32609171

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What the unit for electric current

Answers

The unit of electric current is the Ampere.

1 Ampere of current means that if you set up your chair and
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see 1 coulomb of charge passing that point every second.

How will you recognize 1 coulomb of charge ?
Well, every electron carries the same amount of charge, and
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experiment in 1909.)  So we know how many electrons it takes
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All you have to do is count the electrons as they zip past.
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If you reach that count every second, you know the current
passing that point is 1 Ampere.

Answer: amps

Explanation: