Answer:
Not a function
Step-by-step explanation:
Because the line is vertical, it is not a function.
-5/6b = 30
Answer:
b = -36
Step-by-step explanation:
In other words, solve this given equation -5/6b = 30 for b.
For clarity we rewrite this as (-5/6)b = 30.
To isolate b, we multiply both sides of the above equation by (-6/5):
(-6/5)(-5/6)b = (30)(-6/5), or
b = -36
The sum of the first two digits is equal to 9
sin x = sqrt(3)/2
Answer:
Step-by-step explanation:
We are given that
We have to find all solutions of the given equation
We know that
sin x is positive then the value of sin x will lie in I quadrant and II quadrant.The value of sin x is negative in III and IV quadrant .
We are given that sin x is positive then the solution will lie in I and II quadrant only.Therefore, the solution of sin x will not lie in III and IV quadrant .
...(I equation )and ...(II equation)
In II quadrant change into
Cancel sin on both side of equation I
Then, we get
...(II equation )
Cancel sin on both side of equation II
Then we get
Hence, the solutions of equation are
The solutions of the equation are:
x = 60 degrees
x = 120 degrees
x = 420 degrees
x = 480 degrees, and so on.
We have,
The solutions to the equation sin(x) = √3/2 are any angles where the sine of the angle is equal to √3/2.
So,
sin 60 = √3/2
sin 120 = sin (π - 60) = sin 60 = √3/2
In trigonometry 180 is written as π.
Since (π - 60) is in the secondquadrant sin 60 is positive.
sin 420 = sin (360 + 60) = sin 60 = √3/2
In trigonometry 360 is written as 2π.
Since (2π + 60) is in the Firstquadrant sin 60 is positive.
Similarly,
sin 480 = sin (2π + 120) = sin 120 = sin (π - 60) = sin 60 = √3/2
Thus,
The solutions of the equation are:
x = 60 degrees
x = 120 degrees
x = 420 degrees
x = 480 degrees, and so on.
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segment CD
b. segment AB congruent d. segment BC
c. segment AD congruent segment BC
d. segment AC congruent segment BD
Answer:
A. Segment AB congruent segment CD
C. Segment AD congruent segment BC
Step-by-step explanation:
These are both true because a characteristic of a rhombus is that all four sides are congruent. Therefore we must prove that AB is congruent to CD and AD is congruent to BC.
B. 8
C. 1/8
D. 3/8