Points A(-2,-2) and B(6,2) are of end points of line AB, if C(0,5) is also on the same coordiante place, find the are of triangle ABC

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Answer 1

Answer: I took the route the question was calling me to but I may be wrong because I may have made tiny assumption

Related Questions

Classify the following polynomials by degree and number of terms.1. 3p^3 + 2p^2 + 19p - 5 2. 5x^4 + 12 3. n^2 - 7n - 21 4. 3 5. 2x + 7 6. -8y^2
24+ =120÷3what's supposed to be in the space?
Which terms and 45p4q have a GCF of 9p3? Check all that apply. 18p3r 27p4q 36p3q6 63p3 72p3q6
Make R the subject for this formula V = pi r squared h
43.5 as a whole number

Is 89 a prime number

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89 is a prime number because it's only factors are 1 and itself

Yes , 89 is a prime number !

Yvette is trying to calculate the distance between point C(1, 2) and point D(7, 10). Which of the following expressions will she use? square root of the quantity of 10 minus 2 all squared plus 7 minus 1 all squared square root of the quantity of 10 minus 1 all squared plus 7 minus 2 all squared square root of the quantity of 10 minus 7 all squared plus 2 minus 1 all squared square root of the quantity of 7 minus 10 all squared plus 1 minus 2 all squared

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So this can be solve using the distance formula: D = sqrt [ (x2 – x1)^2 + (y2 – y1)^2] So the expression she should use is: D = sqrt [ (7 – 1)^2 + (10 – 2)^2] Then the answer would be: D = sqrt [ (6)^2 + (8)^2] D = 10

Answer:

square root of the quantity of 10 minus 2 all squared plus 7 minus 1 all squared

Step-by-step explanation:

Need help with a problem. For some reason I can not seem to get it correct. Thinking my formula is wrong. Here's the problem:Assume that there are approximately 140x10^9 stars in our galaxy.
Our galaxy is 50,000 light years from the center to the edge, but just 1,000 light years thick. It's shaped like a thin disk or cylinder. If the stars were distributed equally throughout the galaxy, how many stars would you expect to find in one cubic light year?

I thought it would be Pi*r^2*l. Then divide that by the number of stars. What am I doing wrong? Thanks, been 20 years since I had to do math like this!

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$r=50,000\text{ ly}=5\cdot10^4\text{ ly}\nh=1,000 \text{ ly}=10^(3)\text{ ly}\n V=\pi r^2h\n\n V=\pi \cdot(5\cdot10^4)^2\cdot10^3\nV=\pi \cdot25 \cdot10^8 \cdot10^3\n V=2.5\pi\cdot10^(12) \text{ ly}^3\n\n(140\cdot10^9)/(2.5\pi\cdot10^(12))=\n(1.4\cdot10^(11))/(2.5\pi\cdot10^(12))=\n0.56\pi\cdot10^(-1)=\n5.6\pi\cdot10^(-2)\approx1.76\cdot10^(-1)$

Least to greatest 4.3,5.5, 61/6, 15/4, 43/8

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It would be

15/4 < 4.3 < 43/8 < 5.5 < 61/6

Can anyone help with this algebra graphing problem???

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Dennis ihbqceubb So easy man search it up duhh

Ethan stands 256 cm at point C from a lamp post AB. He is 180 cm tall and his shadow from the lamp is 144 cm long. Find the height AB, in metres, of the lamp post.