A force (F) applied to an object of mass m1 produces an acceleration of 3.00 m/s^2. The same force applied to a second object of mass m2 produces an acceleration of 1.00 m/s^2.

a) what is the value of the ratio m1/m2?

b) if m1 and m2 are combined into one object, what is its acceleration under the action of the force

Answers

Answer 1
Answer:

Force is the product of mass and acceleration

  • The ratio m1/m2 is 1/3
  • The acceleration is 3/4

(a) The ratio m1/m2

Force is calculated as:

F = ma

For the first object, we have:

F = m_1 * 3

For the second object, we have:

F = m_2 * 1

The forces on both objects are equal.

So, we have:

m_1 * 3 = m_2 * 1

Divide both sides by 3m2

(m_1)/(m_2)= (1)/(3)

Hence, the ratio m1/m2 is 1/3

(b) The acceleration when the masses are combined

In (a), we have:

(m_1)/(m_2)= (1)/(3)

Make m2 the subject

m_2 = 3m_1

Recall that:

F = ma

So, we have:

F =(m_1 +m_2) * a

Substitute m_2 = 3m_1

F =(m_1 +3m_1) * a

F =4m_1 * a

Substitute F = m_1 * 3 --- because the force is the same

m_1 * 3 =4m_1 * a

Cancel out m1

3 =4 * a

Divide both sides by 4

a = \frac 34

Hence, the acceleration is 3/4

Read more about force and acceleration at:

brainly.com/question/13370981

Answer 2
Answer: a) using f=ma, F=m1 x 3.00 =3m1
also F=m2 x 1.00 = m2
as the Fs are the same: 3m1=m2
this means that the ratio of m1 to m2 is 3 to 1 as there are 3 m1s for every m2.
b) again using f=ma, the combination of the masses is m1 + m2 or 4m1 as there are 3m1s in m2. so F=4m1 x a = 3m1 (as F is the same for all of them).
a = 3m1/4m1 = 3/4ms^-2

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Mr Solidarios charged Randolf Php 320.00 for parts and Php 150.00 per hour for labor to repair his bicycle.If he spent 3 hours repairing his bicycle,how much does Randolf owe him?

Answers

Answer:

  Php 770.00

Step-by-step explanation:

The cost of labor is ...

  (hours) × (hourly rate)

  = (3 h) × (Php 150.00/h) = Php 450.00

The total cost is ...

  total cost = cost of labor + cost of parts

  = (Php 450.00) + (Php 320.00) = Php 770.00

Randolf owes Mr. Solidarios Php 770.00 for the repair.

Convert the following equation from polar to rectangular form: theta=pi/3

Answers

The question is asking to convert the equation theta = pi/3 from polar to rectangular form, and base on the given values and the equation, the possible answer would be Y =sqrt(3)x. I hope you are satisfied with my answer and feel free to ask for more if you have question and clarifications 

Answer:

D on e2020

Step-by-step explanation:

Find b, given that a = 18.2, B = 62°, and C = 48°. Round answers to the nearest whole number. Do not use a decimal point or extra spaces in the answer or it will be marked incorrect.

Answers

Answer:

17

Step-by-step explanation:

We have been given that in triangle ABC, measure of angle B is 62 degrees and measure of angle C is 48 degrees. The length of side opposite to angle a is 18.2. We are asked to find length of side b.

We will use law of sines to solve for side b.

\frac{a}{\text{sin}(A)}=\frac{b}{\text{sin}(B)}=\frac{c}{\text{sin}(C)}

m\angle A+m\angle B+m\angle C=180^(\circ)\n\nm\angle A+62^(\circ)+48^(\circ)=180^(\circ)

m\angle A+110^(\circ)=180^(\circ)

m\angle A+110^(\circ)-110^(\circ)=180^(\circ)-110^(\circ)

m\angle A=70^(\circ)

Upon substituting our given values, we will get:

\frac{18.2}{\text{sin}(70^(\circ))}=\frac{b}{\text{sin}(62^(\circ))}

\frac{18.2}{\text{sin}(70^(\circ))}*\text{sin}(62^(\circ))=\frac{b}{\text{sin}(62^(\circ))}*\text{sin}(62^(\circ))

\frac{18.2}{\text{sin}(70^(\circ))}*\text{sin}(62^(\circ))=b

b=\frac{18.2}{\text{sin}(70^(\circ))}*\text{sin}(62^(\circ))

b=(18.2)/(0.939692620786)*0.882947592859

b=19.1551999*0.882947592859

b=16.9130376

b\approx 17

Therefore, the length of side b is 17 units.

If f(x) = x+3/4 , what is the equation for f–1(x)?

Answers

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Which statement can be used to prove that a given parallelogram is a rectangle?

Answers

Diagonals of the parallelogram are congruent.

Answer:

Diagonals of the parallelogram are congruent.

Step-by-step explanation: