Answer:
10
Step-by-step explanation:
Explanation
The |-6| part simplifies to 6. The absolute value removes the negative inside. This is because absolute value represents distance on a number line. The number -6 is 6 units away from 0.
That's how we go from 8x - |-6| to 8x - 6
Since we do not know what x is, we can't simplify further.
x(x2 + 5) – 6(x2 + 5)
x2(x – 5) + 6(x – 5)
x2(x + 5) – 6(x + 5)
The answer choice which shows how to determine the factors of the expression by grouping is; Choice D; x²(x + 5) – 6(x + 5)
The given expression is; x³ + 5x² – 6x – 30.
The expression is tetranomial, hence, by grouping into 2 terms each; we have;
Ultimately, upon factorisation of each subunit of the expression, we have;
Read more on factorisation by grouping;
Answer:
D
Step-by-step explanation:
group them first :
( x3+5x2) and ( -6x-30)
then simply by gcf ( greatest common factor) :
x2(x+5) and -6(x+5)
and just add them together:
x2(x+5)-6(x+5)
bonus :
it can be written as (x2-6)(x+5)
Answer:
C
Step-by-step explanation:
Half of the students like football.
The students would prefer to play sports over going to school.
None of the students like tennis.
Answer:
C. The students would prefer to play sports over going to school
Step-by-step explanation:
Hope this helps :)
can u brainlist
O y = 0.5 (x - 2)(+ 8)
O y = 0.5(x2 -2x - 16)
O y = 0.5 (x2 -2x + 16)
Answer:
y = 0.5 (x^2 -2x + 16) has a y-intercept of 8.
Step-by-step explanation:
The x-coordinate of every y-intercept is zero. To determine which of the four quadratics given here has a y-intercept of 8, we need only substitute 0 for x in each; if the result is 8, we've found the desired quadratic.
O y = 0.5(x + 2)(x + 4) becomes y = 0.5(2)(4) = 4 (reject this answer)
O y = 0.5 (x - 2)(x + 8) becomes y = 0.5(-2)(8) = -8 (reject)
O y = 0.5(x2 -2x - 16) becomes y = 0.5(-16) = -8 (reject)
O y = 0.5 (x2 -2x + 16) becomes y = 0.5(16) = 8 This is correct; that '8' represents the y-intercept (0, 8).
Answer:
(0,-7)
Step-by-step explanation:
Answer:
(0,-7)
Step-by-step explanation:
Just took the test
Good luck :)