Answer:
14m^2
Step-by-step explanation:
Area of a triangle is - 1/2 base times hight
two triangels find the srea of both and add them
4x4x1/2 = 16x1/2 = 8m
3x4x1/2 = 12x1/2 = 6m
6m + 8m = 14m
Answer:
Step-by-step explanation:
Drop in sales
Percentage drop
Answer:
(a)105° (b)105° (c)105°
Step-by-step explanation:
The Question Image is attached and a labeled one for explanation.
(a)If the Car is travelling east from the direction point A and heads North East on Kings Avenue in the direction of E, the angle which the car makes is Angle AFE
Angle AFE=180-75=105°
(b)If a car is traveling southwest on King Avenue and is to turn left onto 3rd Street. His probable starting point is North of 3rd street, say F. The angle created is Angle FGC.
Angle AFE =Angle FGC (Corresponding Angles)
Angle FGC =105°
(c)Suppose a car is traveling northeast on King Avenue is to turn right onto 3rd Street. His starting point will be South of 3rd Street.
Angle HGD will be the angle with which it turns.
Angle HGD= Angle CGE(Vertically Opposite Angles)
Angle HGD=105°
What is the measure of the angle created by the car's turning? Explain your answer.
Answer:
11
Step-by-step explanation:
According to Hooke's law, the force required to compress or stretch a spring from an equilibrium position is given by F(x)=kx, for some constant k. The value of k (measured in force units per unit length) depends on the physical characteristics of the spring. The constant k is called the spring constant and is always positive.
In this problem we assume that the force applied doesn't distort the metal in the spring.
A 2 m spring requires 11 J to stretch to 2.4 m. Find the force function, F(x), for the spring described.
Answer:
Check the explanation
Step-by-step explanation:
Kindly check the attached images below to see the step by step explanation to the question above.
To find the force function of a spring using Hooke's Law, you first identify the spring constant 'k' using the given work done and extension. In this case, we found 'k' to be 137.5 N/m. Hence, the force function F(x) for the spring comes out to be 137.5x N.
The problem revolves around Hooke's Law, which is used to determine the force needed to stretch or compress a spring by a certain distance away from its equilibrium position. This law can be mathematically represented as F(x)=kx, where 'F(x)' represents the force applied, 'k' is the spring constant, and 'x' is the distance.
In this question, the work done (W) to stretch the spring is given as 11 J, and the extension (Δx) is 0.4 m (from 2 m to 2.4 m). The work done on a spring is calculated by the equation W = 1/2 * k * (Δx)^2. From this, you can solve for 'k' value. Once you have 'k', you can find the force function F(x) for the spring.
1. Calculate 'k' using the work done equation:
11 J = 1/2 * k * (0.4 m)^2 ➔ k = 137.5 N/m
2. Substitute 'k' in F(x):
F(x) = 137.5 N/m * x
Hence, the force function F(x) = 137.5x N is required to extend the spring by 'x' metres.
#SPJ3
Use π=3.14. Round to the nearest tenth
Answer:
The area of the putting green is 1133.5 square feet.
Step-by-step explanation:
Area of a circle:
The area of a circle is given by:
In which r is the radius, which is half the diameter.
The circular putting green has a diameter of 38 ft.
This means that
What is the area of the putting green?
The area of the putting green is 1133.5 square feet.
Answer:
1133.5 is the answer.
Step-by-step explanation:
Hope its right
It worked for me
Answer:
16
Step-by-step explanation:
(x-8)^2 + (y-4)^2= 16