If b^2=a then b is what of a?

Answers

Answer 1

Answer:

Answer:

$\huge\boxed{b = √(a)}$

Step-by-step explanation:

If we have an equation $b^2 = a$ and we want to find what b is in relation to a, we can change the equation so that we have b on one side and whatever is on the other side is what b is.

$b^2 = a$

To isolate b, we can take the square root of both sides as taking the square root of something squared results in the base.

$√(b^2) = √(a)$

$b = √(a)$

So b is the square root of a.

Hope this helped!

Answer 2

Answer: 1:: If
a
is divisible by a square of a prime number, then we cannot conclude from |2
a
|
b
2
that |
a
|
b
.

Any time
a
is divisible by a square of a prime number, =⋅
a
=
k
⋅
p
n
where ≥2
n
≥
2
and
p
does not divide
k
, you can see that
a
divides (⋅−1)2
(
k
⋅
p
n
−
1
)
2
, but
a
does not divide ⋅−1
k
⋅
p
n
−
1
.

Part 2: If
a
is not divisible by a square of a prime number, then we can conclude from |2
a
|
b
2
that |
a
|
b
.

On the other hand, if
a
is not divisible by a square of a prime number, then =12⋯
a
=
p
1
p
2
⋯
p
n
where
p
i
is prime for all
p
. Then, assuming
a
divides 2
b
2
, you can conclude that
p
i
divides 2
b
2
, and therefore
p
i
divides
b
(from prime factorization) for all
i
. From this, you can conclude that
a
divides
b
.

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Tickets for a carnival for a family of 4 costs $28. The ticket includes 1 food item and 3 games.Select ALL true statements below based on this information.
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There are four shelves of books along a wall in the library. On the top shelf, 16 of the 126 books are checked out. On the second shelf, 8 of the 137 books are checked out. On the bottom shelf, 17 of the 138 books are checked out. How many books are currently on the four shelves?

Answers

1st shelf = 126 - 16 = 110

2nd shelf = 137 - 8 = 129

3rd shelf = Doesn't say

Last shelf = 138 - 17 = 121

Add:

121 + 129 + 110 = 360

I think the answer is 360 but since it doesn't mention anything about the 3rd shelf, I'm not sure.

Hope this helped☺☺

there are currently 360 books on all the shelves

Is (2,3) a solution of y + 1 > 1/2x + 3?

Answers

Answer:

No, it is not.

Step-by-step explanation:

You graph the inequality by finding the boundary line, then shading the appropriate area.

bananas cost $0.80 a pound. in a relation, the input is the number of pounds of bananas and the output is the cost.

Answers

Yes because one input (number of pounds of banana) will always have the same output (cost).

Answer:

True. This isn't really a question but it is a statement

Step-by-step explanation:

1 pound 80 cents

2 pounds 1.60

3 pounds 2.40

and so on

The lifetime of a certain type of battery is normally distributed with a mean value of 10 hours and standard deviation of 2 hours. Find the probability that a randomly selected battery has a lifetime greater than 12 hou g

Answers

Answer:

$P(X>12)=P((X-\mu)/(\sigma)>(12-\mu)/(\sigma))=P(Z>(12-10)/(2))=P(z>1)$

And we can find this probability using the complement rule:

$P(z>1)=1-P(z<1)$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(z>1)=1-P(z<1)=1-0.841=0.159$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the lifetime of a certain type of battery of a population, and for this case we know the distribution for X is given by:

$X \sim N(10,2)$

Where $\mu=10$ and $\sigma=2$

We are interested on this probability

$P(X>12)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=(x-\mu)/(\sigma)$

If we apply this formula to our probability we got this:

$P(X>12)=P((X-\mu)/(\sigma)>(12-\mu)/(\sigma))=P(Z>(12-10)/(2))=P(z>1)$

And we can find this probability using the complement rule:

$P(z>1)=1-P(z<1)$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(z>1)=1-P(z<1)=1-0.841=0.159$

Give two examples of addition of two mixed numbers with different denominators
SHOW ALL STEPS

Answers

Answer:

First Example: 3 1/2 + 4 3/4, Second Example: 6 3/8 + 7 9/15

Extra Example: 8 4/20 + 3 5/10

Step-by-step explanation:

First Example:

1/2 + 3/4

1/2 is equal to 2/4 so it is now compatible to be added to 3/4.

2/4 + 3/4

= 5/4

Now for the mixed numbers since its 3 and 4, 3 + 4 = 7.

Final answer is 7 5/4.

Second Example:

3/8 + 9/15

9/15 can be reduced to 3/5

Now the equation is 3/8 + 3/5

= 15/40 + 24/40 is an equivalent equation

15/40 + 24/40

= 39/40

Now for the mixed numbers since its 6 and 7, 6 + 7 = 13

Final answer is 13 39/40.

I am going to include one last example just in case you need one:

Third Example:

4/20 + 5/10

We can reduce these to

1/5 + 1/2

= 2/10 + 5/10 is the equivalent equation

2/10 + 5/10

= 7/10

Now for the mixed numbers since its 8 and 3, 8 + 3 = 11.

Final answer is 11 7/10.

I Hope this helps!

Carlos purchased an antique chair for $56.He later sold the chair for $68 to an antique
dealer. What was the percent markup of the
chair?

Answers

Answer:

about 22 percent

Step-by-step explanation:

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A certain test preparation course is designed to help students improve their scores on the MCAT exam. A mock exam is given at the beginning and end of the course to determine the effectiveness of the course. The following measurements are the net change in 7 students' scores on the exam after completing the course: 37,12,12,17,13,32,23 Using these data, construct a 80% confidence interval for the average net change in a student's score after completing the course. Assume the population is approximately normal. Step 1 of 4 : Calculate the sample mean for the given sample data. Round your answer to one decimal place.

-8.46 greater or less than 5.31

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