Answer:
x = -2/3
y = 10/9
Step-by-step explanation:
3y - 4x = 6
x=3y-4
Substitute the second equation into the first for x
3y - 4( 3y-4) =6
3y - 12y +16 = 6
Combine like terms
-9y +16 = 6
Subtract 16 from each side
-9y +16-16 = 6-16
-9y = -10
Divide by -9
-9y/-9 = -10/-9
y = 10/9
x = 3y -4
x =3(10/9) -4
=10/3 - 12/3
=-2/3
b. P(A|B) = y
c. P(B|A) = x
d. P(A and B) = x + y
e. P(A and B) = x/y
P(A)
If two events are independent, then
.
Use formulas for conditional probabilities:
.
For independent events these formulas will be:
.
Now in your case and .
This shows that the only correct choice is A.
Answer:
To find the horizontal asymptote of the function,
we need to find the intersection points of the function with the
y-axis.
These points are the solutions of the equation
f(x) = 0.
We decompose the function in the form of the product of two expressions:
f(x) = (x + 4)(x² + 13x + 36)
Now we can set each of the expressions inside the parentheses equal to zero and solve the horizontal equations:
x + 4 = 0 or x² + 13x + 36 = 0
To solve the first equation
, we can factor out
x: x = -4
To solve the second equation, we can use the analysis method or the quadratic formula.
Using the analysis method, we can decompose the expression
x² + 13x + 36 in the following form:
(x + 4)(x + 9) = 0 So the two horizontal equations are equal to
x + 4 = 0 (that is, x = - 4) and x + 9 = 0 (that is, x = -9).
So the horizontal asymptote of the function
f(x) = (x + 4)(x² + 13x + 36) is equal to
x = -4 and x = -9.
The horizontal asymptote of the function f(x) = (x+4)(x²+13x+36) is y = x³.
The function given is f(x) = (x+4)(x²+13x+36). To find the horizontal asymptotes, we need to determine the behavior of the function as x approaches positive and negative infinity.
As x approaches positive or negative infinity, the function behaves like the highest power term in the expression. In this case, the highest power term is x³, so the horizontal asymptote is y = x³.
Therefore, the horizontal asymptote of the function is y = x³.
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