How many minutes in a year

Answers

Answer 1
Answer:

There are 525600 minutes in a regular year

There are 527040 minutes in a leap year


I hope that's help !


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1. You decide to buy some new clothes. The subtotal comes to $123.79, butyou have a 15% off coupon. What is the total you will spend? *

Answers

Answer:

$105.22

Step-by-step explanation:

Evaluate the function w/o using a calculator! calculate
cos(135)
and then take the reciprocal

Answers

In your question where ask to evaluate the function using calculator and then take its reciprocal and the function is cos(135). Base on my calculation and through step by step procedure and with the guidance of the theories and by the use of formulas, I came up with an answer - sqrt of 2

If the mean of positively skewed distribution is 126 which of these values could be the median of the distribution ? A. 126
B. 122
C. 130
D. 134

Answers

i think its 122 not 100% tho I'll check for you

Answer:122

Step-by-step explanation:just took it

5.75 , 7.75 , 9.75 , 11.75 is a Non linear sequence ? is it true or false

Answers

Answer:

false because each go up by two and I didnt even look it up

Solve this problem. The hiking trails in Roman Nose Park are 3.6, 7.9, 10.4, 5.7, and 3.5 miles long. Cindy and Geoff hiked two of the trails for a total of 9.3 miles. What were the lengths of the trails they hiked? 3.6 and 7.9 miles 3.5 and 7.9 miles 3.6 and 5.7 miles 3.5 and 5.7 miles

Answers

They hiked 3.6 and 5.7 miles. Since 3.6+5.7=9.3

Numbers 1-6 please and thank you This is really hard and I really really need help. I appreciate all the help I can get.

Answers

Area of prism = base area × altitude

1. (2x²-10)(x+4)

= 3x³-2x - 40

2. Base area = 2πr

Volume = (2πr)(r²+ 5r)

=2πr³ + 10πr²

3. Base area=½(6)(x-4)(x+3)=3(x-4)(x+3)

Volume= 3(x-4)(x+3)(⅓)

=(x-4)(x+3)= x² - x -12

4. Base circumference= 10π

Base radius = 10π/(2π) = 5

Base area = πr² = 25π

Volume = 25π(3x²-2x)

=125πx²-50πx

5. Volume = 3π√50

=15π√2

6. Base diameter = 16

Base radius = 16/2 = 8

Base area = 2πr = 16π

Volume = 16π(23a²)

=368πa²