Rewrite the expression as a product using GCF and distributive property= 27+45= Explain your answer.

Answers

Answer 1
Answer:

Step-by-step explanation:

The greatest common factor (GCF) of 27 and 45 is 9.

27 + 45

9 (3 + 5)

9 (8)

72

Answer 2
Answer:

Final answer:

The expression 27 + 45 is rewritten using the Greatest Common Factor (GCF) and the distributive property as 9*(3 + 5) = 72.

Explanation:

The given expression is 27 + 45. To rewrite this using the Greatest Common Factor (GCF) and the distributive property, we first find the GCF of the two numbers. The GCF of 27 and 45 is 9. We then divide each number by the GCF and rewrite the expression using the distributive property.

So, 27 + 45 = 9*(3 + 5) = 9*8 = 72.

The above step is the application of the distributive property, where a*(b + c) = ab + ac.

Learn more about GCF and distributive property here:

brainly.com/question/11023604

#SPJ3


Related Questions

A box contains 5 plain pencils and 5 pens. A second box contains 3 color pencils and 7 crayons. One item from each box is chosen at random. What is the probability that a plain pencil from the first box and a color pencil from the second box are selected
Need Help on this, First RIGHT answer gets brainliest :)
1/4 times 2 equals??
F3 + 11g - 4h when f=3 g=2 h=7
If the police have 8 ​suspects, how many different ways can they select 5 for a​ lineup?

6^3x=14 Show your work

Answers

Answer:

Is 3x supposed to be an exponent?

Step-by-step explanation:

Both possible answer are provided

3x as an exponent and as 6 times 3x

What is 23 squared ?

Answers

The value of the 23² number will be 529.

What is an expression?

Expression in maths is defined as the relation of numbers variables and functions by using mathematical signs like addition, subtraction, multiplication, and division.

In mathematics, expression is defined as the relationship of numbers, variables, and functions using mathematical signs such as addition, subtraction, multiplication, and division.

Given that there is a number 23 and is squared. The value of the 23² will be calculated as:-

E = 23²

E = 23 x 23

E = 529

Therefore, the value of the 23² number will be equal to 529.

To know more about an expression follow

brainly.com/question/51920

#SPJ5

what is 23 squared ? :

23^2 is 529.

A city currently has 31,000 residents and is adding new residents steadily at the rate of 1200 per year. If the proportion of residents that remain after t years is given by S(t) = 1/(t + 1), what is the population of the city 7 years from now?

Answers

Answer:

Population of the city after 7 years from now, P(7) = 6370

Given:

Initial Population, P_(i) = 31000

rate, r(t) = 1200 /yr

S(t) = [/tex]\frac{1}{1 + t}[/tex]

Step-by-step explanation:

Let the initial population be  P_(i) = 31000

The population after T years is given by the equation:

P(T) = P_(i)S(T) + \int_(0)^(T)S(T - t)r(t) dt          (1)

Thus, the population after 7 years from now is given by using eqn (1):

P(7) = (3100)/(1 + 7) + 1200\int_(0)^(7)(1)/(8 - t) dt

P(7) = 3875 - 1200ln(8 - t)|_(0)^(7)

P(7) = 3875 - 1200ln(8 - t)|_(0)^(7)

P(7) = 3875 - 1200(ln(1) - ln(8))

P(7) = 3875 + 2495 = 6370

Express the number as a ratio of integers. 3.469 = 3.469469469

Answers

If you're looking for a fractional representation of the non-terminating decimal,
3.469469469....
then:

Let x=3.469469469.....
then
1000x-x=(3469.469469469...) - (3.469469469....)
999x = 3466
x=3466 / 999
= 3+469/999
=3(469)/(999)

What is the standard deviation of 98.21

Answers

Answer: 0.61

Step-by-step explanation:

38.5 hope this helps :)))))

The population of a city (in millions) at time t (in years) is P(t)=2.6 e 0.005t , where t=0 is the year 2000. When will the population double from its size at t=0 ?

Answers

Answer:

  year 2139

Step-by-step explanation:

The population will double when the factor e^(.005t) is 2.

  e^(.005t) = 2

  .005t = ln(2)

  t = ln(2)/0.005 = 138.6

The population will be double its size at t=0 when t=138.6. That is the population will be about 5.2 million in the year 2139.

The population will double by the year 2139 from its value of 2.6 million in year 2000.

Population function :

P(t) = 2.6 {e}^(0.005t)

Population size at t = 0

P(0) = 2.6 {e}^(0.005(0))  = 2.6(1) = 2.6

Population at t = 2.6 million.

For the population to double ;

2.6 × 2 = 5.2 million :

5.2 = 2.6 {e}^(0.005t)

We solve for t

(5.2)/(2.6) =  {e}^(0.005t)

2 =  {e}^(0.005t)

Take the In of both sides

ln(2)  = 0.005t

t \:  =  ln(2)  / 0.005 = 138.629

The population will double after 139 years

Therefore, the population will double by the 2139 (Year 2000 + 139 years) = year 2139.

Learn more : brainly.com/question/11672641?referrer=searchResults