Answer:
Step-by-step explanation:
Given that:
population mean = 10
variance = 25 ; = = 5
sample size n = 28
The standard deviation of the sample mean:
=
= 0.95
To halve the standard deviation of the sample mean, the size of how large the sample will be can be computed as follows:
= 2
n = 4 × 28
n = 112
The standard deviation is 0.95 and if the standard deviation is halved then the sample mean is 112.
It is the measure of the dispersion of statistical data. Dispersion is the extent to which the value is in a variation.
A normal population has a mean of 10 and a variance of 25.
A random sample of sizes n-28 is selected.
A. The standard deviation will be
B. The sample be if you want to halve the standard deviation of the sample mean
More about the standard deviation link is given below.
h(x)=-49x-125
04
01-2
110
16.
For the function h(x) = 6 - X the value of (hoh)(10) is 10.
A relation is a function if it has only One y-value for each x-value.
The given function is h(x) = 6 - X
We have to find the value of (hoh)(10)
The composite function (hoh)(10) can be written as h(h(10))
h(h(10))
Plug in the value 10 in place of x
=h(6-10)
=h(-4)
Now let us find h(-4)
=6-(-4)
=6+4
=10
Hence, for the function h(x) = 6 - X the value of (hoh)(10) is 10.
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Answer:
h(h(10))---> h(-4)---->10 ......hOh(10)=10
Step-by-step explanation:
Answer:
i am aware that this is already answered but here is proof that the person above is correct!
Step-by-step explanation:
Answer: A), No
Step-by-step explanation:
Answer:
111°
Step-by-step explanation:
By exterior angle theorem:
Answer:
x = 111
Step-by-step explanation:
180- 82 -29 is 69 and 180-69 is x which x is equal to 111
Answer:
a. 0.5 or 50%
b. 5 rolls.
Step-by-step explanation:
a. There are 30 possible outcomes for this experiment, the sample space for the outcomes in which the six-sided die produces a value larger than the roll of the five-sided die is:
S={6,1; 6,2; 6,3; 6,4; 6,5; 5,1; 5,2; 5,3; 5,4; 4,1; 4,2; 4,3; 3,2; 3,1; 2,1}
There are five outcomes when rolling a 6, four when rolling a 5, three when rolling a 4, two when rolling a 3 and one when rolling a two.
The probability is:
b. The probability of rolling a 3 on the five-sided die is 1 in 5 or 0.20. The expected number of rolls until a fair five-sided die rolls a 3 is: