Answer:
0.8
Step-by-step explanation:
(2 x 10^-4)
= 0.0002
(4x10^3)
= 4000
0.0002 x 4000 = 0.8
The amount Howie will pay back at the end of one year is $26000.00
The given parameters are:
-- the principal amount
-- the interest rate
--- the duration
The amount to pay back in this duration is then calculated using:
So, we have:
Express percentage as decimal
Multiply
Hence, the amount to pay back is $26000.00
Read more about simple interest at:
Order is operation is PEMDAS which means Parentheses, Exponents Mulitiplication,division,Addition and Subtraction so you follow the order whether they exist or not.
So (41-3^2)-(4+4)=
41-9-8 = 32-8 = 24
Answer:
See explanation below
Step-by-step explanation:
Here a coin was tossed three times.
Let H = head & T = tail
Find the following:
a) The sample space:
Since a coin is tossed thrice, all possible outcome would be:
S = { HHH, HHT, HTH, HTT, TTT, TTH, THH, THT}
b) i) A = Exactly 2 tails: Here exactly 2 tails were recorded.
A = {HTT, TTH, THT}
ii) B = at least two tails: Here 2 or more tails were recorded.
B = {HTT, TTT, TTH, THT}
iii) C = the last two tosses are heads:
C = { HHH, THH}
c) List the elements of the following events:
i) A. This means all outcomes in A
= {HTT, TTH, THT}
ii) A∪B. A union B, means all possible outcomes present in A or B or in both
= {HTT, TTH, THT, TTT}
iii) A∩B. This means all possible outcomes of A that are present in B.
= {HTT, TTH, THT}
iv) A∩C. All outcomes A that are present in B
= {∅}
The sample space of tossing a coin three times consists of eight possible outcomes: HHH, HHT, HTH, THH, TTH, THT, HTT, and TTT. Events A, B, and C can be determined by listing the appropriate outcomes. The intersection and union of events A and B can also be determined.
(a) The sample space, Ω, of tossing a coin three times can be determined by listing all the possible outcomes: HHH, HHT, HTH, THH, TTH, THT, HTT, and TTT.
(b) i. A = {HHT, HTH, THH}
ii. B = {TTT, TTH, THT, HTT, HHT, HTH, THH}
iii. C = {HTH, TTH}
(c) i. A = {HHT, HTH, THH}
ii. A∪B = {HHT, HTH, THH, TTT, TTH, THT, HTT, HHT}
iii. A∩B = {HHT, HTH, THH}
iv. A∩C = {HHT, HTH}
#SPJ3
Answer:
it is point B
Step-by-step explanation:
because im smart
Answer:
Point B
Step-by-step explanation:
√11 is 3.3
And A is about 2. Something and inbetween D and E is 4 which means C will be 3.5
So it leaves it at B
question is below
The missing justification is for the statement that three angles add to a particular angle. The appropriate choice is ...
... c. Angle Addition Postulate