To find out which recipes use more or less flour than Robert's current recipe, compare the quantity of flour needed per bag of chocolate chips in the new recipes to the 3.5 cups of flour needed in his current recipe.
In response to Robert's request, we would compare the amount of flour used in his current recipe to that used in other recipes. Since Robert's present recipe demands 3.5 cups of flour for each bag of chocolate chips, we would then have a baseline to compare with other recipes.
For instance, if a new recipe requires 4 cups of flour for a bag of chocolate chips, it means this recipe takes more flour. Conversely, if the recipe takes 3 or 2.5 cups for the same amount of chocolate chips, it uses less flour.
Overall, the process involves measuring the amount of flour that each new recipe requires and comparing it to the 3.5 cups in Robert's current recipe.
Therefore, to find out which recipes use more or less flour than Robert's current recipe, compare the quantity of flour needed per bag of chocolate chips in the new recipes to the 3.5 cups of flour needed in his current recipe.
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Answer:
Step-by-step explanation:
so first u need to add all the numbers
-Bertha
a) The probability that a new municipal bond issued by a city will receive an A rating is 0.625 or 62.5%.
b) 56% of municipal bonds are issued by cities.
c) The proportion of municipal bonds issued by suburbs is 0.325 or 32.5%.
Let's solve each part of the problem:
a. If a new municipal bond is to be issued by a city, what is the probability that it will receive an A rating?
Use conditional probability here.
Using conditional probability notation, we have:
P(A | City)
To calculate this, use the following formula:
P(A | City) = P(A and City) / P(City)
We are given:
- P(A) = 0.70 (probability of an A rating)
- P(B) = 0.20 (probability of a B rating)
- P(C) = 0.10 (probability of a C rating)
For bonds issued in cities:
- P(City | A) = 0.50 (probability that it's a city if it's rated A)
- P(City | B) = 0.60 (probability that it's a city if it's rated B)
- P(City | C) = 0.90 (probability that it's a city if it's rated C)
Now, let's calculate:
P(A and City) = P(A) * P(City | A)
P(City) = P(A) * P(City | A) + P(B) * P(City | B) + P(C) * P(City | C)
Substitute the values:
P(A and City) = 0.70 * 0.50
= 0.35
P(City) = (0.70 * 0.50) + (0.20 * 0.60) + (0.10 * 0.90)
= 0.35 + 0.12 + 0.09
= 0.56
Now, calculate the conditional probability:
P(A | City) = P(A and City) / P(City)
= 0.35 / 0.56
= 0.625
So, the probability is 0.625 or 62.5%.
b. What proportion of municipal bonds are issued by cities?
56% of municipal bonds are issued by cities.
c. What proportion of municipal bonds are issued by suburbs?
To find the proportion of municipal bonds issued by suburbs, use a similar approach:
P(Suburb) = P(A) * P(Suburb | A) + P(B) * P(Suburb | B) + P(C) * P(Suburb | C)
We are given:
- P(Suburb | A) = 0.40
- P(Suburb | B) = 0.20
- P(Suburb | C) = 0.05
Now, calculate:
P(Suburb) = (0.70 * 0.40) + (0.20 * 0.20) + (0.10 * 0.05)
= 0.28 + 0.04 + 0.005
= 0.325
So, the proportion of municipal bonds issued by suburbs is 0.325 or 32.5%.
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The probability that a municipal bond issued by a city will receive an A rating is 35%. The proportion of all municipal bonds issued by cities is 56%. The proportion of all municipal bonds issued by suburbs is 32.5%.
This question requires an understanding of probability and conditional probability.
a) To find the probability that a new municipal bond issued by a city will receive an A rating, we must first determine the likelihood that an A-rated municipal bond is issued by a city. Given that 50% of A-rated bonds are issued by cities and that 70% of all bonds receive an A rating, we can calculate this probability as (0.50)*(0.70) = 0.35, or 35%.
b) To find the proportion of municipal bonds issued by cities, we must add up the bonds issued by cities across all ratings. So, (0.70*0.50) + (0.20*0.60) + (0.10*0.90) = 0.35 + 0.12 + 0.09 = 0.56, or 56%.
c) To calculate the proportion of municipal bonds issued by suburbs, we do the same calculation as in part b) but for suburbs. So, (0.70*0.40) + (0.20*0.20) + (0.10*0.05) = 0.28 + 0.04 + 0.005 = 0.325, or 32.5%.
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The first transformation was a
.
The second transformation was a
The first transformation was a rotation about point A.
The second transformation was a reflection across line M.
In Mathematics, a rotation can be defined as a type of transformation which moves every point of the object through a number of degrees around a given point, which can either be clockwise or counterclockwise (anticlockwise) direction.
By critically observing the diagram which illustrates the sequence of transformations, we can logically deduce that the first transformation was a clockwise rotation about point A by 180 degrees.
Furthermore, the second transformation that maps W'X'Y'Z' to W''X''Y''Z'' is a reflection across the line of reflection M.
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G.33
H.6 with an exponent of 5
I.65
Step-by-step explanation:
x=5,y=-1
6(5)-3(-1)=30+3=33
answer G .33
Answer options: 9,000 27,000 24,360
Answer:
24,360
Step-by-step explanation:
30P3 = 30!/(30-3)! = 30·29·28 = 24,360
Answer:
Compute the permutation. 30 P 3
Answer options: 9,000 27,000 24,360
Step-by-step explanation:
The factorial function (symbol:!) Means that descending numbers are multiplied. 30 P 3.
30! = 30 x 29 x 28 =24,360
The answer is: 24,360
The correct representation for the total amount of money in dollars will be;
⇒ $1.50 + $0.35x
What is an expression?
Expression in math is defined as the collection of the numbers, variables and functions by using signs like addition, subtraction, multiplication, and division.
Given that:
Carmen has 1.50$ in a coffee can.
She is going to place a quarter in the can every day for x days.
Now,
Carmen has 1.50$ in a coffee can.
And, She is going to place a quarter in the can every day.
That mean;
Cost = $1.50 / 4 = $0.35
And, For x days, the cost = $0.35x
Hence, Total amount = $1.50 + $0.35x
Thus, The correct representation for the total amount of money in dollars will be;
⇒ $1.50 + $0.35x
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Answer:
(a + b + c)/2
Step-by-step explanation:
Number of kids in first class: a
Number of kids in second class: b
Number of kids in third class: c
The total number of kids in all classes is: a + b + c
The total number of kids is divided equally between 2 buses:
(a + b + c)/2
Answer:
(a + b + c)/2
Step-by-step explanation:
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