Different fatty acids are distinguished by the length of their_?double bonds
single bonds
carboxylic groups
carbon chains

Answers

Answer 1

Answer: The answer is carbon chains.

Related Questions

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Which is an example of plasmas in nature? solar cells plasma balls auroras clouds
The standard free energy change for a reaction can be calculated using the equation ΔG∘′=−nFΔE∘′ ΔG∘′=−nFΔE∘′ where nn is the number of electrons transferred, FF is Faraday's constant, 96.5 kJ·mol−1·V−1, and ΔE∘′ΔE∘′ is the difference in reduction potential. For each of the given reactions, determine the number of electrons transferred (n)(n) and calculate standard free energy (ΔG∘′)(ΔG∘′) . Consider the half-reactions and overall reaction for reaction 1. half-reactions:fumarate 2−+2H+CoQH2↽−−⇀succinate−↽−−⇀CoQ+2H+ half-reactions:fumarate−+2H+↽−−⇀succinate2−CoQH2↽−−⇀CoQ+2H+ overall reaction:fumarate2−+CoQH2↽−−⇀succinate2−+CoQΔE∘′=−0.009 V
Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial chemist studying this reaction fills a 50.0L tank with 14. mol of sulfur dioxide gas and 2.6 mol of oxygen gas, and when the mixture has come to equilibrium measures the amount of sulfur trioxide gas to be 1.6 mol. Calculate the concentration equilibrium constant for the reaction of sulfur dioxide and oxygen at the final temperature of the mixture. Round your answer to 2 significant digits.
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MassWhat is the percent composition by mass of
nitrogen in the compound N,H, (gram-formula
32 g/mol)?
(1) 13%
(3) 88%
(2) 44%
(4) 93%

Answers

Answer: 88%

Explanation:

Secondary amines react with the nitrosonium ion to generate ________. n-nitrosoamines diazonium salts anilines imines oximes

Answers

Answer:
Secondary amines react with the nitrosonium ion to generate N-Nitrosoamines.

Explanation:
Nitosonium Ion is generally utilized in the formation of Diazonium Salts which are considered excellent starting Material from synthesis point of View. Diazonium salts are formed by reacting Primary Amine or Anilines with Nitrosonium Ions. In our case, the Amine given is Secondary. So, reaction of Sec. Amines with Nitrosonium Ions stops after the formation of N-Nitrosoamine as there is no Hydrogen attached to Nitrogen atom of Amine to be eliminated and form a double and eventually triple bond with the Nitrogen atom of Nitrosonium Ion.

In a climatological sense, dryness is a function of both annual rainfall and ________.This a geology question.

Answers

Answer:

In a climatological sense, dryness is a function of both annual rainfall and evaporation

What nuclide undergoes fission to form molybdenum-103, atomic number 42, tin-131, atomic number 50, and two neutrons? Element symbol: _______ mass number: _______

Answers

Answer:

The correct answer is Pu, 234.

Explanation:

In the given case, let us consider the reactant as X. Now the mass number (balanced) on both the sides will be,

Mass of X = Mass of Molybdenum + Mass of Tin + Mass of neutrons

M = 1 * 103 + 1 * 131 + 2 * 0

M = 234

Now the atomic number (balanced) on both the sides,

Atomic number of X = Atomic number of Molybdenum + Atomic number of Tin + Atomic number of neutrons

A = 1*42 + 1*50 + 2*1

A = 94

The atomic number 94 is for the element Plutonium, whose symbol is Pu. Thus, the reactant is 234-Pu.

Be sure to answer all parts. (a) How many atoms are directly bonded to the central atom in a trigonal planar molecule?

i. two
ii. three
iii. six
iv. eight

(b) How many atoms are directly bonded to the central atom in a trigonal bipyramidal molecule?

i. three
ii. four
iii. five
iv. six

(c) How many atoms are directly bonded to the central atom in an octahedral molecule?

i. three
ii. four
iii. six
iv. eight

Answers

Answer:

a) ii

b)iii

c)iii

Explanation:

three atoms directly bonded then only it is possible to achieve trigonal planar

trigonal bipyramidal means five atoms should attach to central atom

for octahedral six atoms must directly connected to central atom

15.0 L of an ideal gas at 298 K and 3.36 atm are heated to 383 K with a new pressure of 5.60 atm. What is the new volume in liters

Answers

Answer:

$V_2=11.6L$

Explanation:

Hello!

In this case, since we volume, pressure and temperature which are all changing, we can use the combined ideal gas law to write:

$(P_1V_1)/(T_1) =(P_2V_2)/(T_2)$

Thus, since the final volume V2 is required, by solving for it, we write:

$V_2=(P_1V_1T_2)/(T_1P_2)$

In such a way, we plug in the given data to obtain:

$V_2=(3.36atm*15.0L*383K)/(298K*5.60atm)\n\nV_2=11.6L$

Which means that the process compressed the gas.

Best regards.

Final answer:

To find the new volume, we can use the combined gas law equation.

Explanation:

To solve this problem, you can use the combined gas law equation, which relates the initial and final conditions of pressure, volume, and temperature.

The combined gas law equation is: P1 * V1 / T1 = P2 * V2 / T2

Substituting the given values into the equation, we can solve for the new volume:

(3.36 atm * 15.0 L) / 298 K = (5.60 atm * V2) / 383 K

Simplifying and solving for V2, the new volume, we find V2 = 11.78 L.