Answers
Answer : The Lewis-dot structure of the following molecules are shown below.
Explanation :
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
(1) The given molecule is,
As we know that hydrogen has '1' valence electron, nitrogen has '5' valence electrons.
Therefore, the total number of valence electrons in = 5 + 3(1) = 8
According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.
(2) The given molecule is,
As we know that sulfur and oxygen has '6' valence electrons.
Therefore, the total number of valence electrons in = 6 + 2(6) = 18
According to Lewis-dot structure, there are 8 number of bonding electrons and 10 number of non-bonding electrons.
(3) The given molecule is,
As we know that carbon has '4' valence electrons, hydrogen has '1' valence electron and oxygen has '6' valence electrons.
Therefore, the total number of valence electrons in = 4 + 4(1) + 6 = 14
According to Lewis-dot structure, there are 10 number of bonding electrons and 4 number of non-bonding electrons.
(4) The given molecule is,
As we know that hydrogen has '1' valence electron, nitrogen has '5' valence electrons and oxygen has '6' valence electrons.
Therefore, the total number of valence electrons in = 1 + 5 + 2(6) = 18
According to Lewis-dot structure, there are 8 number of bonding electrons and 10 number of non-bonding electrons.
(5) The given molecule is,
As we know that nitrogen has '5' valence electrons.
Therefore, the total number of valence electrons in = 2(5) = 10
According to Lewis-dot structure, there are 6 number of bonding electrons and 4 number of non-bonding electrons.
(6) The given molecule is,
As we know that carbon has '4' valence electrons, hydrogen has '1' valence electron and oxygen has '6' valence electrons.
Therefore, the total number of valence electrons in = 4 + 2(1) + 6 = 12
According to Lewis-dot structure, there are 8 number of bonding electrons and 4 number of non-bonding electrons.
Related Questions
PromptDescribe the general process by which new elements are synthesized.Please help!!!!
Problem Page What kind of intermolecular forces act between a hydrogen peroxide molecule and an iron(III) cation? Note: If there is more than one type of intermolecular force that acts, be sure to list them all, with a comma between the name of each force.
Calculate the enthalpy for this reaction: 2C(s) + H2(g) ---> C2H2(g) ΔH° = ??? kJ Given the following thermochemical equations: C2H2(g) + (5/2)O2(g) ---> 2CO2(g) + H2O(ℓ) ΔH° = -1,123 kJ C(s) + O2(g) ---> CO2(g) ΔH° = -340 kJ H2(g) + (1/2)O2(g) ---> H2O(ℓ) ΔH° = -211 kJ
Calculate the molarity of a solution that contains 0.50 g of NaCl dissolved in 100mL of solution?
Answers
Answer:
C₆H₆
Explanation:
Each border of the figure represents 1 atom of carbon. We have 6 borders = 6 atoms of carbon.
Each atom of carbon form 4 bonds. All the carbons are doing a double bond and a single bond with other carbons. That means are bonded 3 times. The other bond (That is not represented in the figure. See the image) comes from hydrogens. As we have 6 carbons that are bonded each 1 with one hydrogen. There are six hydrogens and the molecular formula is:
C₆H₆
This structure is: Benzene
Answers
The volume of 45.6g of silver if the density of silver is 10.5g/mL is 4.342 ml. The correct option is A.
What is Volume?
Volume is the space occupied by a three-dimensional object. The volume of any object can be calculated by dividing the mass by its density. It is a scalar quantity. It is the total weight is that object.
Silver is an element in the periodic table. It is non-metal, and it is used in making ornaments and in medicines. The volume of the solver is calculated, and the mass and density are given.
The mass of silver is given, 45.6g
The density of the element is 10.5g/mL
Putting the value in the equation
The density and the mass would be divided.
Volume = 45.6g / 10.5 = 4.342
Thus, the volume of silver is 4.342 ml. The correct option is A.
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Explanation:
first you get moles of silver
n=m/M
hence you add no of moles to this equation
c=nv
v=n/c
Answers
Answer:
0.432 drinks are toxic
Explanation:
The toxic dose of ethylene glycol is 0.1 mL per kg body weight (mL/kg). In grams (Density ethylene glycol = 1.11g/mL):
1.11g/mL * (0.1mL / kg) = 0.111g/kg
If the victim weighs 85kg, its letal dose is:
85kg * (0.111g/kg) = 9.435g of ethylene glycol
Using the concentration of ethylene glycol in the liquid:
9.435g of ethylene glycol * (550g liquid / 120g ethylene glycol) = 43.2g of liquid are toxic.
The drinks are:
43.2g of liquid * (1 drink / 100 g) =
0.432 drinks are toxic
Answers
Answer:
See explanation below
Explanation:
To solve this problem, we need to use the expression of half life decay of concentration (or mass) which is the following:
m = m₀e^-kt (1)
In this case, k will be the constant rate of this element. This is calculated using the following expression:
k = ln2/t₁/₂ (2)
Let's calculate the value of k first:
k = ln2/2.7 = 0.2567 d⁻¹
Now, we can use the expression (1) to calculate the remaining mass:
m = 8.1 * e^(-0.2567 * 2.6)
m = 8.1 * e^(-0.6674)
m = 8.1 * 0.51303
m = 4.16 mg remaining
Final answer:
The half-life of gold-198 is the time it takes for half of it to decay. Given that the half-life is 2.7 days, and the period in consideration is 2.6 days, approximately half of the original amount of 8.1 mg, which is 4.05 mg, will remain.
Explanation:
This problem is related to the concept of half-life in radioactive decay. The half-life of a substance is the time it takes for half of it to decay. As the half-life of gold-198 is 2.7 days and we are considering a period of 2.6 days, which is almost one half-life, therefore, approximately half the substance should have decayed.
So, if you start with 8.1 mg of gold-198, at the end of one half-life (or close to it at 2.6 days), you should have approximately half of this amount remaining. Half of 8.1 mg is 4.05 mg, thus, approximately 4.05 mg remains after 2.6 days.
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in 5.164 g of Call2?
Answers
Answer:
1.06x10²² formula units
Explanation:
First we convert 5.164 g of CaI₂ into moles, using its molar mass:
- 5.164 g ÷ 293.887 g/mol = 0.0176 mol
Then we convert 0.0176 moles into formula units, using Avogadro's number, which relates the number of formula units present in 1 mol:
- 0.0176 mol * 6.023x10²³ FormulaUnits/mol = 1.06x10²² formula units
Answers
Answer:
¹₀n+ ²³⁸₉₂U → ²³⁹₉₃Np + ⁰₋₁e
Explanation:
Key statement;
The first transuranium element neptunium, NpNp, was prepared by bombarding U−238U−238 with neutrons to form a neptunium atom and a beta particle.
This is the beta particle; ⁰₋₁e
¹₀n+ ²³⁸₉₂U → Np + ⁰₋₁e
The mass number of Np;
1 + 238 = Np + 0
Np = 239
The atomic number of Np;
0 + 92 = Np + (-1)
92 + 1 = Np
Np = 93
The equation is given as;
¹₀n+ ²³⁸₉₂U → ²³⁹₉₃Np + ⁰₋₁e