will give 5 stars and thanks for correct answer Richard starts high school every day at 7:45 A.M.. How many seconds is Richard in school each day of school dismissed at 2:15 P.M.

Answers

Answer 1
Answer: Richard spends 21,600 seconds at school each day.

Related Questions

Charlie has—$19 in his bank account. This is $28 more then Steve’s bank account. How much money does Steve have in his bank account?
Please help I've been trying to solve this for a long time
a plane ticket cost b dollars for an adult ticket and k dollars for a child. Find an expression that represents the total cost for 9 adults and 3 children.
Gloria earned a total of $810 over the summer. She earned $162 babysitting and the restfrom mowing lawns. Which bar model and solution represent x, the amount of money Gloriaearned mowing lawns?
According to a recent report, 60% of U.S. college graduates cannot find a full time job in their chosen profession. Assume 57% of the college graduates who cannot find a job are female and that 18% of the college graduates who can find a job are female. Given a male college graduate, find the probability he can find a full time job in his chosen profession? (See exercise 58 on page 220 of your textbook for a similar problem.)

Equations
Solve T = C(9+ AB) for B

Answers

Answer:

Simplifying

T = C(9 + AB) * forB

Reorder the terms for easier multiplication:

T = C * forB(9 + AB)

Multiply C * forB

T = forBC(9 + AB)

T = (9 * forBC + AB * forBC)

Reorder the terms:

T = (forAB2C + 9forBC)

T = (forAB2C + 9forBC)

Solving

T = forAB2C + 9forBC

Solving for variable 'T'.

Move all terms containing T to the left, all other terms to the right.

Simplifying

T = forAB2C + 9forBC

Step-by-step explanation:

Simplifying

T = C(9 + AB) * forB

Reorder the terms for easier multiplication:

T = C * forB(9 + AB)

Multiply C * forB

T = forBC(9 + AB)

T = (9 * forBC + AB * forBC)

Reorder the terms:

What is the measure of

Answers

Answer: w= 155

Step-by-step explanation:

The world’s population is currently estimated at 7,125,000,000. What is this to the nearest billion? billion

Answers

Answer:

7,000,000,000

Step-by-step explanation:

since the closest number is less than 5 (1<5) you round down making the nearest billion 7

Answer:

7,000,000,000 OR 7 Billion

Step-by-step explanation:

Since the 1 is millions place and its less than 5, you need to round down meaning that 7,125,000,00 rounded to the nearest billion is 7 billion.

The point 3 2 is reflected in the origin the coordinates of its image are

Answers

When a point is reflected across the origin, both coordinates change sign.

The image is (-3, -2).

Isaac works a job that pays him based oncommission. He earns 5% commission on all
sales after the first $5000. To determine the
amount of sales he earns commission on, he
uses the function f(x) = x - 5000. Then he uses
a different equation to determine how much
commission he actually earns, g(x) = 0.05x. He
wants to create a composite that includes
both. What is the composite function?
-
=

Answers

Answer: 1000000

Step-by-step explanation:

5x100

You are trying to determine if you should accept a shipment of eggs for a local grocery store. About 4% of all cartons which are shipped have had an egg crack while traveling. You are instructed to accept the shipment if no more than 10 cartons out of the 300 you inspect have cracked eggs. What is the probability that you accept the shipment? (In other words, what is the probability that, at the most, you had 16 cartons with cracked eggs?)a. 1012.
b. 3669.
c. 5319.
d. 4681.
e. 5832.
f. 6331.

Answers

Answer:

0.8809

Step-by-step explanation:

Given that:

The population proportion p = 4% = 4/100 = 0.04

Sample mean x = 16

The sample size n = 300

The sample proportion \hat  p =(x)/(n)

= 16/300

= 0.0533

P(\hat p \leq 0.0533) = P\bigg ( \frac{\hat p - p}{\sqrt{(P(1-P))/(n)}}\leq\frac{0.0533 - 0.04}{\sqrt{(0.04(1-0.04))/(300)}}\bigg )

P(\hat p \leq 0.0533) = P\bigg ( Z\leq\frac{0.0133}{\sqrt{(0.04(0.96))/(300)}}\bigg )

P(\hat p \leq 0.0533) = P\bigg ( Z\leq\frac{0.0133}{\sqrt{(0.0384)/(300)}}\bigg )

P(\hat p \leq 0.0533) = P\bigg ( Z\leq\frac{0.0133}{\sqrt{1.28 * 10^(-4)}}\bigg )

P(\hat p \leq 0.0533) = P\bigg ( Z\leq(0.0133)/(0.0113)}\bigg )

P(\hat p \leq 0.0533) = P\bigg ( Z\leq1.18}\bigg )

From the z tables;

= 0.8809

OR

Let X be the random variation that follows a normal distribution;

Then;

population mean \mu = n × p

population mean \mu = 300 × 0.04

population mean \mu = 12

The standard deviation \sigma = √(np(1-p))

The standard deviation  \sigma = √(300 * 0.04(1-0.04))

The standard deviation \sigma = √(11.52)

The standard deviation  \sigma = 3.39

The z -score can be computed as:

z = (x - \mu)/(\sigma)

z = (16 -12)/(3.39)

z = (4)/(3.39)

z = 1.18

The required probability is:

P(X ≤ 10) = Pr (z  ≤ 1.18)

= 0.8809