A commercial aircraft is flying westbound east of the Sierra Nevada Mountains in California. The pilot observes billow clouds near the same altitude as the aircraft to the south, and immediately turns on the "fasten seat belt" sign. Explain why the aircraft experiences an abrupt loss of 500 meters of altitude a short time later.

Answers

Answer 1

Answer:

Answer:

Billow clouds provide a visible signal to aviation interests of potentially dangerous turbulent sky since they indicate instability in air currents.

Explanation:

Billow clouds are created in regions that are not stable in a meteorological sense. They are frequently present in places with air flows, and have marked vertical shear and weak thermal separation and inversion (colder air stays on top of warmer air). Billow clouds are formed when two air currents of varying speeds meet in the atmosphere. They create a stunning sight that looks like rolling ocean waves. Billow clouds have a very short life span of minutes but they provide a visible signal to aviation interests of potentially dangerous turbulent sky since they indicate instability in air currents, which although may not affect us on the ground but is a concern to aircraft pilots. The turbulence due to the Billow wave is the only logical explanation for the loss of 500 m in altitude of the plane.

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I need a good phisics teacher for one day online please123

Dawn is trying to find out how much weight she can push across the room. She is really trying to find her

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Dawn is trying to figure out how much weight she can push with her strength, or what her maximum pushing force is, across the room. She could do an experiment to find out.

She must first prepare a testing space with a flat, smooth surface to reduce friction. She can then progressively add weights to a cart or other object and use all of her strength to try to push it across the room. She can determine her maximum pushing force by noting the heaviest weight she can move. For a variety of jobs, including moving furniture or participating in physical sports that call for pushing heavy things, this knowledge can be essential.

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Answer:

Muscular strength

Explanation:

She is testing her strength while pushing the weights

Use the worked example above to help you solve this problem. A ball is thrown upward from the top of a building at an angle of 30.0° to the horizontal and with an initial speed of 15.0 m/s. The point of release is h = 46.0 m above the ground.(a) How long does it take for the ball to hit the ground?
(b) Find the ball's speed at impact.
(c) Find the horizontal range of the ball.

Answers

Answer:

Explanation:

A construction foreman exerts 1300 Newtons of force trying to move a 1200-kg block of concrete. How many Joules of work does he perform?

Answers

He does no work until the block starts to move ... an unlikely event.

If it ever does move, then the work he does is

(1300) x (the distance the block moves, in meters) .

The unit is 'joules.

A 220 kg crate hangs from the end of a rope of length L = 14.0 m. You push horizontally on the crate with a varying force F to move it 4.00 m to the side.(a) What is the magnitude of F when the crate is in this final position? During the crate's displacement, what are
(b) the total work done on it,
(c) the work done by the gravitational force on the crate, and
(d) the work done by the pull on the crate from the rope?
(e) Knowing that the crate is motionless before and after its displacement, use the answers to (b), (c), and (d) to find the work your force F does on the crate.
(f) Why is the work of your force not equal to the product of the horizontal displacement and the answer to (a)?

Answers

Answer:

(a) magnitude of F = 797 N

(b)the total work done W = 0

(c)work done by the gravitational force = -1.55 kJ

(d)the work done by the pull = 0

(e) work your force F does on the crate = 1.55 kJ

Explanation:

Given:

Mass of the crate, m = 220 kg

Length of the rope, L = 14.0m

Distance, d = 4.00m

(a) What is the magnitude of F when the crate is in this final position

Let us first determine vertical angle as follows

=> $Sin \theta = (d )/(L)$

=> $\theta = Sin^(-1) (d)/(L)$ =

Now substituting thje values

=> $\theta = Sin^(-1) (4)/(12)$ =

=> $\theta = Sin^(-1) (1)/(3)$

=> $\theta = Sin^(-1)(0.333)$

=> $\theta = 19.5^(\circ)$

Now the tension in the string resolve into components

The vertical component supports the weight

=> $Tcos\theta = mg$

=> $T = (mg)/(cos\theta)$

=> $T = (230 * 9.8 )/(cos(19.5))$

=> $T = (2254 )/(cos(19.5))$

=> $T = (2254 )/(0.9426)$

=>T =2391N

Therefore the horizontal force

$F = TSin(19.5)$

F = 797 N

b) The total work done on it

As there is no change in Kinetic energy

The total work done W = 0

c) The work done by the gravitational force on the crate

The work done by gravity

Wg = Fs.d = - mgh

Wg = - mgL ( 1 - Cosθ )

Substituting the values

= $-230 * 9.8* 12 ( 1 - cos(19.5) )$

= $-230 * 9.8* 12 ( 1 - 0.9426) )$

= $-230 * 9.8* 12 (0.0574)$

= $-230 * 9.8* 0.6888$

= $-230 * 6.750$

= -1552.55 J

The work done by gravity = -1.55 kJ

d) the work done by the pull on the crate from the rope

Since the pull is perpendicular to the direction of motion,

The work done = 0

e)Find the work your force F does on the crate.

Work done by the Force on the crate

WF = - Wg

WF = -(-1.55)

WF = 1.55 kJ

(f) Why is the work of your force not equal to the product of the horizontal displacement and the answer to (a)

Here the work done by force is not equal to F*d

and it is equal to product of the cos angle and F*d

So, it is not equal to the product of the horizontal displacement and the answer to (a)

Which lists mixtures, in order, from the smallest particles to the largest particles?O solution, colloid, suspension
solution, suspension, colloid
O suspension, colloid, solution
O suspension, solution, colloid

Answers

The order of mixtures according to their particle size from smallest to the largest is: solution< colloid< suspension. So, the first option is correct.

What is meant by solvent and solute in a mixture ?

Solvent is defined as the substance in which the solute particles dissolve and forms a mixture. Solute is defined as the particles that get dissolved in the solvent to form the mixture.

Here,

The particles of the solutions, colloids and suspension varies according to their size and the type of mixture they comes under.

Colloid is a heterogenous mixture, that means it has a non-uniform composition of particles. In colloid, the particles have an intermediate size between 1 nm to 1000 nm which is the size range between that of solution and suspension.

Solution is a homogenous mixture in which the particles have a diameter of less than 1 nm. The size of the particles in solution is the smallest when compared to that of colloid and suspension.

Suspension is a homogenous mixture in which the size of the particles is larger than 10000 nm. The particles of suspension are the largest among the particles of colloid and solution.

Hence,

The order of mixtures according to their particle size from smallest to the largest is: solution< colloid< suspension.

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Answer:

A or 1

Explanation:

solution, colloid, suspension

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