What can you infer from the fact that metals are good conductors of electricity?

Answers

Answer 1
Answer:

Answer:

Knowing that these metals are infact good conductors of electricity we can infer that metals are able to hold and conduct certain temperatures. Another thing we can infer is that these good conductors can be used in connection to transferring energy or electricity.

Answer 2
Answer: Metals are an excellent conductor of electricity and heat because the atoms in the metals form a matrix through which outer electrons can move freely. Instead of orbiting their respective atoms, they form a sea of electrons that surround the positive nuclei of the interacting metal ions.

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How does activity on the Sun affect natural phenomena on Earth?

If you travel 2 km north, then travel 5 km south, what is your displacement?

Answers

Answer:

This is a vector addition problem which requires magnitude and direction as the answer. First is to resolve the southbound vector and the northbound vector. Since they are opposite in directions their vector sum is their algebraic sum. 3 km north + 5 km south = 2 km south.

We then add 2 km west and 2 km south using Pythagorean theorem since west and south form a right angle. (2 km)^2 west + (2 km)^2 south gives (4 + 4) km^2 southwest = 8 (km)^2 45 degrees south of west

Extracting the square root of 8 gives us about 2.83 km 45 degrees south of west.

Explanation:

I hope it will help you...

Light from a sodium lamp (λ = 589 nm) illuminates two narrow slits. The fringe spacing on a screen 150 cm behind the slits is 4.0 mm. What is the spacing (in mm) between the two slits?

Answers

The spacing between the two slits is 0.221mm.

The spacing  between the two slits is given as,

                    D=(\lambda L)/(y)

Where \lambda is wavelength, y is fringe spacing and L is length of screen.

Given that, \lambda=589nm,L=150cm,y=4mm

Substitute in above equation.

               D=(589*10^(-9)*150*10^(-2)  )/(4*10^(-3) )\n \nD=2.21*10^(-4) m\n\nD=0.221mm

Hence, the spacing between the two slits is 0.221mm.

Learn more about the sodium lamp here:

brainly.com/question/24867424

A piston above a liquid in a closed container has an area of 0.75m^2, and the piston carries a load of 200kg. What will be the external pressure on the upper surface of the liquid?

Answers

Answer:

2613.3 pa

Explanation:

p=F/A

p=ma/A

p=200×9.8/0.75

p=2613.3

How much longer will it taketo travel a distance of 6ookm at
a speed of 50kmh than it
would at a
speed of 6okmh?

Answers

Answer:

2hr much longer

Explanation:

Given parameters

  Distance  = 600km

   Speed 1  = 50km/h

   Speed 2 = 60km/h

Unknown:

How much longer will it take to travel a distance  = ?

Solution:

  Speed is the distance divided by time;

          Speed  = (distance)/(time)  

 Now;

           Time taken  = (Distance)/(Speed)  

Time 1;

                        = (600)/(50)

                       = 12hr

Time 2;

                       = (600)/(60)

                       = 10hr

To find how much more time;

            Time 1 will take 12hr - 10hr, 2hr much longer to travel the distance at that rate.

_ is the name given to the heat energy received from the sun

Answers

Answer:

The think the answer is solar radiation.

Explanation:

here, we gain the heat from the sun through a radiation. When it travels from the sun the harmful radiation are absorbed by ozone layer and heat enegry is provided to the surface of the Earth.

hopeit helps..

A sinusoidal wave is travelling on a string under tension T = 8.0(N), having a mass per unit length of 1 = 0.0128(kg/m). It’s displacement function is D(x,t) = Acos(kx - t). It’s amplitude is 0.001m and its wavelength is 0.8m. It reaches the end of this string, and continues on to a string with 2 = 0.0512(kg/m) and the same tension as the first string. Give the values of A, k, and , for the original wave, as well as k and  the reflected wave and the transmitted wave.

Answers

Answer:

Explanation:

A sinusoidal wave is travelling on a string under tension T = 8.0(N), having a mass per unit length of 1 = 0.0128(kg/m). It’s displacement function is D(x,t) = Acos(kx - t). It’s amplitude is 0.001m and its wavelength is 0.8m. It reaches the end of this string, and continues on to a string with 2 = 0.0512(kg/m) and the same tension as the first string. Give the values of A, k, and , for the original wave, as well as k and  the reflected JJJJJJave and the transmitted wave.