A ray of light is projected into a glass tube that is surrounded by air. The glass has an index of refraction of 1.50 and air has an index of refraction of 1.00. At what minimum angle will light in the glass tube be totally reflected at the glass/air interface?

Answers

Answer 1
Answer:

Answer:

θ = 41.8º

Explanation:

This is an internal total reflection exercise, the equation that describes this process is

         sin θ = n₂ / n₁

where n₂ is the index of the incident medium and n₁ the other medium must be met n₁> n₂

        θ = sin⁻¹ n₂ / n₁

let's calculate

       θ = sin⁻¹ (1.00 / 1.50)

       θ = 41.8º


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A rocket travels vertically at a speed of 1300 km/hr.1300 km/hr. The rocket is tracked through a telescope by an observer located 13 km13 km from the launching pad. Find the rate at which the angle between the telescope and the ground is increasing 3 min3 min after the lift-off.

Answers

Final answer:

This calculus problem can be solved by defining the appropriate variables, constructing a relationship using trigonometry, taking the derivative of both sides with respect to time, and solving for the rate of change of the angle with respect to time. The initial distances, rocket's speed, and angle are used to determine the rocket's position after 3 minutes and thus the rate at which the angle is changing.

Explanation:

This problem involves the concept of related rates in calculus and the understanding of trigonometric relationships. Let's denote the rocket's altitude as y and the angle between the ground and the telescope as θ. We know Δy/Δt = 1300 km/hr, we're given the initial distance (13 km), and we want to find Δθ/Δt at 3 min after lift-off.

From trigonometry, we know that tan(θ) = y/x, where x is the horizontal distance (which remains constant at 13 km) and y is the vertical distance (which is changing). Differentiating both sides with respect to t gives sec²(θ) * Δθ/Δt = Δy/Δt / x. Assuming that the speed of the rocket remains constant, we find that y = (1300 km/hr * 3min)*(1hr/60min) = 65 km at 3 min after launch. Plugging x = 13 km and y = 65 km into the equation tan(θ) = y/x, we get θ = atan(65/13) = 78.69°. Now we can solve for Δθ/Δt using the differentiated equation: Δθ/Δt = ( Δy/Δt / x ) / sec²(θ) = (1300 km/hr / 13 km) / sec²(78.69°). Solving this gives the rate of change of θ with respect to time.

Learn more about Related Rates here:

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State guy lussac law

Answers

The combined gas law has no official founder; it is simply the incorporation of the three laws that was discovered. The combined gas law is a gas law that combines Gay-Lussac’s Law, Boyle’s Law and Charle’s Law.  Boyle’s law states that pressure is inversely proportional with volume at constant temperature. Charle’s law states that volume is directly proportional with temperature at constant pressure. And Gay-Lussac’s law shows that pressure is directly proportional with temperature at constant volume. The combination of these laws known now as combined gas law gives the ratio between the product of pressure-volume and the temperature of the system is constant. Which gives PV/T=k(constant). When comparing a substance under different conditions, the combined gas law becomes P1V1/T1 = P2V2/T2.

Calculate the man’s mass. (Use PE = m × g × h, where g = 9.8 N/kg.)A man climbs a wall that has a height of 8.4 meters and gains a potential energy of 4,620 joules. His mass is about
kilograms

Answers

Answer:

mass=56.12kg

Explanation:

PE=mgh

4620=m×9.8×8.4

make msubject of the formula...

m =4620/(9.8×8.4)

m=4620/82.32

m=56.12kg

how do you describe and determine the direction of the magnetic field produced by an electric current?

Answers

Answer:

the magnet or electric current produces a magnetic field

Explanation:

this magnetic field can be visualized as a pattern of a circular field lines surrounding a wire. hall probes can determine the magnitude of the field

hope it helps you

How was Bohr's atomic model different from those of previous scientists?

Answers

Answer:Bohr placed the electrons in distinct energy levels.  Rutherford described the atom as consisting of a tiny positive mass surrounded by a cloud of negative electrons. Bohr thought that electrons orbited the nucleus in quantised orbits.

Explanation: also rutherfords was just a hypothesis while Bhor took the time to make his an experiment

It takes 56.5 kilojoules of energy to raise the temperature of 150 milliliters of water from 5°C to 95°C. If youuse an electric water heater that is 60% efficient, how many kilojoules of electrical energy will the heater
actually use by the time the water reaches its final temperature?

Answers

You'd get an extra 40/60 of the energy, or 2/3. Multiply 5/3 by the required energy to get the actual consumption.