Answer:electrical,kinetic,kinetic,electrical
Explanation:
Answer:
Electrical, kinetic, kinetic, electrical
Explanation:
Just did it
Answer:
The correct answer for this problem is conduction.
Explanation:
I just did the test and conduction was the correct answe.
501 cm3
1232 cm3
616 cm3
To solve this we assumethat the gas inside the balloon is an ideal gas. Then, we can use the ideal gasequation which is expressed as PV = nRT. At a constant pressure and number ofmoles of the gas the ratio T/V is equal to some constant. At another set ofcondition of temperature, the constant is still the same. Calculations are asfollows:
T1 / V1 = T2 / V2
V2 = T2 x V1 / T1
V2 = 308 K x 556 cm³ / 278 K
V2 = 616 cm³
Answer:
One student measures liquids for the experiment by holding the flask up at eye level. The other student measures liquids for the experiment while the flask sits on the table.
Explanation:
Just did the test
b. 11 kg.
c. 110 kg.
d. 1100 kg.
e. none of the above
A lamb that weighs 110 N has a mass of around 11 kg. Hence, option B is correct except B all options are incorrect.
The mass of a physical body is a measure of its entire makeup. Inertia, or the body's resistance to acceleration when a net force is applied, is also measured by this term. The strength of a body's gravitational pull on other bodies is also influenced by its mass. The kilogram is the fundamental mass unit of the SI.
In physics and engineering, the weight of an object refers to the gravitational force that pulls on it. Weight is the term used in many widely used textbooks to describe the gravitational force acting on the object. Some people think of weight as a scalar quantity that gauges the gravitational force's strength.
According to the question, the given values are :
Weight, w = 110 N and,
Taking value of g = 10 m/s²
As we know that :
w = m × g
110 = m (10)
m = 11 kg
Hence, the mass of the lamb will be 11 kg.
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Answer:
x = 400 [m]
Explanation:
To solve this problem we must use the following kinematics equations, first, we find the final speed, and then we proceed to find the distance traveled.
where:
Vf = final velocity [m/s]
Vi = initial velocity = 15 [m/s]
a = acceleration = 5 [m/s^2]
t = time = 10 [s]
Note: the positive sign in the Equation indicates that the car is accelerating, i.e. its speed is increasing.
Now replacing
Vf = 15 + (5*10)
Vf = 65 [m/s]
Now using the second equation:
where:
x = distance traveled [m]
x = (65^2 - 15^2)/ (2*5)
x = 400 [m]