MATHEMATICS HIGH SCHOOL

Quadrilateral ABCD is a kite. A kite. Angle A is 90 degrees, angle B is unknown, angle C is 130 degrees, angle D is unknown. What is the measure of angle B? degrees
Quadrilateral ABCD is a kite. A kite. Angle A is - 1

Answers

Answer 1
Answer:

Final answer:

A kite is a quadrilateral with two pairs of adjacent congruent sides. In a kite, the two angles between the congruent sides are equal. To find angle B in this given kite, we can subtract the sum of the other three angles from 360 degrees.

Explanation:

A kite is a quadrilateral with two pairs of adjacent congruent sides. In a kite, the two angles between the congruent sides are equal. In this given kite, angle A is 90 degrees, angle C is 130 degrees, and angle D is unknown. Since the sum of the angles in a quadrilateral is 360 degrees, we can find angle B by subtracting the sum of the other three angles from 360 degrees.



Let's calculate it:



  1. Angle A = 90 degrees
  2. Angle C = 130 degrees
  3. Angle D = (360 - 90 - 130) degrees
  4. Angle B = (360 - 90 - 130 - Angle D) degrees



By substituting the values, we can find that angle D is 140 degrees.



Therefore, angle B is (360 - 90 - 130 - 140) degrees, which simplifies to 0 degrees.

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Answer 2
Answer:

Answer:

70 degrees

Step-by-step explanation:

(360 - 90 - 130)/2=70

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Two classes have a total of 50 students. One of the classes has 6 more students than the other. How many students are in the larger class.

Answers

Let's say 'x' to number of the students in the smaller class. Since the larger one is 6 more than the smaller one, its number would be 'x+6'. So their sum is equal to 

x+x+6=2x+6 and we know total is 50 so:
2x+6=50\n 2x=50-6\n 2x=44\n x=\frac { 44 }{ 2 } \n x=22 

x is 22 so the larger number 'x+6' is equal to : x+6=22+6=28

There are 28 students in the larger class.

Let's assume the number of students in one class is x.

Since the other class has 6 more students, the number of students in the other class is x + 6.

The total number of students in both classes is 50.

Therefore, we can write the equation:

x + (x + 6) = 50

2x + 6 = 50

Subtracting 6 from both sides:

2x = 44

Dividing both sides by 2:

x = 22

So, the number of students in the larger class, which is x + 6, is:

22 + 6 = 28

Therefore, there are 28 students in the larger class.

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Does it appear that there blank sufficient evidence

Answers

Answer:

1%798%/5*2+-6746%6-9437

Solve the inequality 2(x-3)-5x<9

Answers

Answer:

x > -5

Step-by-step explanation:

Answer:

Step-by-step explanation:

2(x-3)-5x<9 expand left side

2x-6-5x<9. group like terms on left side

-3x-6<9. add 6 to each side

-3x<15. divide each side by -3 (reverse sign because of division by a negative)

x>-5

(Permutations) what is he value of 8C6?

Answers

8C6 = 8!/[6!(8-6)!] = 56/2 = 28

The function H(t) = −16t2 + 90t + 50 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in the air along a path represented by g(t) = 28 + 48.8t, where g(t) is the height, in feet, of the object from the ground at time t seconds.Part A: Create a table using integers 1 through 4 for the 2 functions. Between what 2 seconds is the solution to H(t) = g(t) located? How do you know? (6 points)

Part B: Explain what the solution from Part A means in the context of the problem. (4 points)

Answers

Part A:
      
         H(t)       g(t)
1     124      76.8
2     166      125.6
3     176      174.4
4     154      223.2

The solution is between 3 and 4 seconds because it can be seen that there was a shift in the trend between them. H(t) had higher values for the first 3 seconds. It can be seen that in 3 seconds, g(t) is already approaching H(t). Finally at 4 seconds, g(t) surpasses H(t).

Part B:
This means that between 3 and 4 seconds, g(t) was able to catch up to H(t) in terms of height. At H(t)=g(t), this gives 3.03 secs which is indeed between 3 and 4 seconds. Above 3.03 seconds, g(t) overtakes the height of H(t).

10/18=c/4.5
what is c

Answers

(10)/(18)=(c)/(4,5)\n\ncross\ multiplication\n\n4,5*10=18c\n\n45=18c\ \ \ \ | divide\ by\ 18\n\nc=(45)/(18)=2(1)/(2)\n\n\\boxed{c=2(1)/(2)}
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